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Easy-to-Use Regular Expression Support in C++?


By : Mark Tran
Date : July 26 2020, 09:00 AM
may help you . C++11 now includes the support of regular expressions. It will be platform independent. You just need a recent compiler. Check the following list to know which one to use.
http://wiki.apache.org/stdcxx/C%2B%2B0xCompilerSupport
code :


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Easy regular expression


By : Rafa
Date : March 29 2020, 07:55 AM
Any of those help This pertains to a regex expression.If I have a document with the word Chapter in it how could I select the space right before it?
code :
\s+(?=Chapter)

java easy Regular expression


By : wtsn
Date : March 29 2020, 07:55 AM
This might help you I have strings like "xxxxx?434334", "xxx?411112", "xxxxxxxxx?11113" and so on.
code :
str = str.replaceAll("[?].*", "");

Porting a regular expression to a more restrictive regular expression implementation that does not support conditional r


By : user2191993
Date : March 29 2020, 07:55 AM
this will help If I understand you correctly you want to make sure that both xx-yy belong to same category (alphabetic, numeric). In case they are place xx in group 1 and yy in group 2.
If that is true then you can use look-ahead to test if string is in form you want to accept, and then place each part in separate groups.

easy regular expression in python


By : user2210423
Date : March 29 2020, 07:55 AM
This might help you You can take advantage of the negative lookbehind regex to help you. Here you can use this regex:
code :
(?<!/)@a

Easy regular expression- please correct


By : user2807945
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have AUD0.7195. I want to mach AUD in $1 and 0.7195in $2. The amount may vary. It can be positive integer. I have tried with: , \d{+} doesn't make sense and should be \d+
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