logo
Tags down

shadow

pandas merge rows based on grouping


By : mandi sh
Date : August 02 2020, 03:00 AM
this will help Let's say I have a dataframe that looks like this: , IIUC
code :
df.groupby([df.col1,df.col3.replace({'xx':'xz','xy':'xz'})]).col2.first().reset_index()
Out[29]: 
  col1 col3  col2
0    a    a     1
1    a   xz    98
2    b    a     1
3    b    b     2
4    b    c     3
5    b   xz     8


Share : facebook icon twitter icon

Accepting top rows in pandas dataframe based on grouping


By : Kirill Karetnikov
Date : March 29 2020, 07:55 AM
around this issue Related to the question here: Reordering pandas dataframe based on multiple column and sum of one column , UPDATE:
code :
In [166]: df.loc[df.Country_FAO.isin(df.groupby('Country_FAO').sum().nlargest(2, 'mean_area').index)]
Out[166]:
   Country_FAO type   mean_area        sort
5    Australia  car  12141000.0  18910501.0
4    Australia  car   6475695.0  18910501.0
6    Australia  bus    293806.0  18910501.0
0  Afghanistan  car   2029000.0   2141000.0
1  Afghanistan  car    112000.0   2141000.0
In [153]: df.groupby('Country_FAO').sum()
Out[153]:
              mean_area
Country_FAO
Afghanistan   2141000.0
Algeria        829351.0
Australia    18910501.0

In [154]: df.groupby('Country_FAO').sum().nlargest(2, 'mean_area')
Out[154]:
              mean_area
Country_FAO
Australia    18910501.0
Afghanistan   2141000.0

In [155]: df.groupby('Country_FAO').sum().nlargest(2, 'mean_area').index
Out[155]: Index(['Australia', 'Afghanistan'], dtype='object', name='Country_FAO')
In [156]: df.groupby('Country_FAO').sum().nlargest(2, 'mean_area').reset_index()
Out[156]:
   Country_FAO   mean_area
0    Australia  18910501.0
1  Afghanistan   2141000.0

Merge rows of pandas data frame by grouping a column


By : Mohammad Jawad Azhar
Date : March 29 2020, 07:55 AM
I hope this helps you . A beginner in panda and trying to achieve this in a pandas data frame- , Use:
code :
(df.groupby('Name', as_index=False)
   .agg({'Count':'sum','Address':lambda x: ' \n '.join(x)}))
   Name                              Address  Count
0  Jake  XXXXXXXXX \n YYYYYYYYY \n ZZZZZZZZZ      3
1   Jon                  AAAAAAA \n BBBBBBBB      2

How to merge dictionaries of a pandas dataframe when grouping by rows


By : EddieReyes
Date : March 29 2020, 07:55 AM
Hope that helps You are nearly there. You just need to use a custom function which merges dictionaries across non-null series values:
code :
def merge_dicts(x):
    return {k: v for d in x.dropna() for k, v in d.items()}

res = df.groupby(['id', 'date'], as_index=False).agg(merge_dicts)

print(res)

   id      date                        area1                        area2
0  01  20181010  {'a': 10, 'b': 15, 'c': 17}  {'a': 20, 'c': 13, 'b': 12}
1  02  20180506             {'a': 2, 'b': 3}            {'c': 4, 'a': 18}

grouping pandas rows above and below based on specified value


By : user3519240
Date : March 29 2020, 07:55 AM
I hope this helps . Is there a simple way to group pandas dataframe according to a given value. In the code below,the value is 1.5, I want to find the last row with value equal to or greater 1.5 and add a new column 'Group' such that all the rows above that last row are in one group and rows below it are in another group. , Try this
code :
df_srtd['Group'] = df_srtd.Value.ge(fnd_val)[::-1].cummax() + 1

Out[321]:
   Class   Value  Group
0      1 -1.1306      2
1      2 -0.5694      2
2      3 -0.7241      2
3      4  1.8211      2
4      5  1.5555      2
5      6  0.0416      2
6      7  1.9236      2
7      8  0.1944      1
8      9 -0.0204      1
Sample `df_srtd_rev`

   Class   Value
8      9 -0.0204
7      8  0.1944
6      7  1.9236
5      6  0.0416
4      5  1.5555
3      4  1.8211
2      3 -0.7241
1      2 -0.5694
0      1 -1.1306

df_srtd_rev['Group'] = df_srtd_rev.Value.ge(fnd_val)[::-1].cummax() + 1

Out[326]:
   Class   Value  Group
8      9 -0.0204      2
7      8  0.1944      2
6      7  1.9236      2
5      6  0.0416      2
4      5  1.5555      2
3      4  1.8211      2
2      3 -0.7241      1
1      2 -0.5694      1
0      1 -1.1306      1

Pandas date based grouping to return rows on a condition


By : GeekYzp
Date : March 29 2020, 07:55 AM
hope this fix your issue You need sort_values + groupby + GroupBy.last:
Related Posts Related Posts :
  • Print a table with aligned columns in python
  • PYTHON AND IBPY: UNEXPECTED EOF WHILE PARSING ; I can't figure it out
  • Entity Linking with spacy/Wikipedia
  • Question about "running times" of a for loop
  • Best way to .clean and .strip long string?
  • Jupyter Labs: Kernel Dies when Converting Tuple to PandasData Frame
  • Writing a CSV table from column variables?
  • Calling a function using a dictionary - dictionary keys as its parameters, dictionary values as its arguments
  • if error then do something else - string split
  • Filling values in a column
  • What are these set operations, and why do they give different results?
  • How can I run a function forever?
  • For loop resulting in wrong output
  • How to vectorize this simple NumPy function?
  • Matplotlib: creating a scatter plot where each point is colored (weighted) based on its count of instances in the datase
  • other possible way to duplicate a string from one variable in python
  • Cannot delete the column in DataFrame Pandas by del function
  • How to convert a string into ASCII?
  • Assigning values to a new column in Pandas
  • Django 3 - Making Model's FK Dropdown Display Current User's Data Only
  • Python Error of unsupported operand types for *: 'Nonetype' and 'Float' with array problem
  • Python in Jupyter Notebooks: 'Table' is not defined
  • Extract ID and value from set of strings in an array
  • finding the position of an element within a numpy array in python
  • Cannot run apache airflow after fresh install, python import error
  • Replace climbing sequence with its average
  • How to create a new column with a conditional count in a groupby pandas dataFrame
  • In python how to mix two sentence?
  • returning the 2nd letter in a string in a list and sorted the words by it. keep getting indexing range out of bound. Pyt
  • Convert string in an a tuple into an integer
  • Comparison using modifiable signs (python)
  • Python Beginning in new line for each letter in string
  • Byte to integer conversion
  • Why is 1e100+1 == 1e100 if ints do not have a maximum?
  • How to show list of certain items from JSON
  • How to fill a circle contour at the edge of an image?
  • How to BEST extract information from multiple dataframes based on a series of if\else conditions and matching values? (G
  • Convert string to few variables with pattern
  • Python Deleting Multiple Lines
  • How to replace a string based on first and last character
  • How can I resolve problem with tag_add in Tkinter
  • Check if csv file is empty in pandas
  • pd.NA vs np.nan for pandas
  • How to not display () and '
  • How to write a large dask array (numpy.ndarray) to a Zarr file leveraging GPUs?
  • How to crop circle image from webcam OpenCV and remove background
  • Can we login on a website with pure Python urllib, modify some form values, and submit? (without Selenium browser automa
  • Python: Fastest way of packing a 2d array of binary values into UINT64 array
  • Using global variable from one python file to another
  • How to add "<>" symbols to a string?
  • "IndexError: list assignment index out of range" in python
  • counting of elements (strings) in list python
  • if a certain columns's var is lower then n i want to drop that column
  • ValueError: Units 'M' and 'Y' are no longer supported, as they do not represent unambiguous timedelta values durations
  • How I get data in one column and put into a list using pandas?
  • What takes more memory, an 8 char string or 8 digit int?
  • I want to know what is the purpose of lambda x=x in the below code?
  • Pandas groupby select top N rows based on column value AND group size share
  • Appending to list produces None
  • Multiply List of RGB values Python
  • shadow
    Privacy Policy - Terms - Contact Us © voile276.org