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How to sort dates from a list using Python


By : Jose Dutra
Date : August 02 2020, 03:00 AM
Hope that helps Your dates are in dd.mm.yyyy order, and you want to sort them in yyyy.mm.dd order; so you can use a key function which splits on . and reverses the components.
code :
>>> date_strings = ['01.01.2009', '04.07.2007', '05.06.2007', '06.06.2007']
>>> sorted(date_strings, key=lambda d: d.split('.')[::-1])
['05.06.2007', '06.06.2007', '04.07.2007', '01.01.2009']


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What is the most efficient way to sort a list of dates in string format in Python?


By : StaticNomad
Date : March 29 2020, 07:55 AM
will help you Suppose I have a list of dates in the string format, 'YYYYMMDD.' How do I sort the list in regular and reverse order? , For that particular format, you can just sort them as strings
code :
>>> sorted(['20100405','20121209','19990606'])
['19990606', '20100405', '20121209']
>>> sorted(['20100405','20121209','19990606'], reverse=True)
['20121209', '20100405', '19990606']

Python sort list of dates in [MMM dd, MMM dd...] format


By : Alexa
Date : March 29 2020, 07:55 AM
hope this fix your issue I have a list in the format , You could parse the dates into datetime objects:
code :
from datetime import datetime

sorted(lst, key=lambda d: datetime.strptime(d, '%b %d'))
>>> from datetime import datetime
>>> lst = ['Jan 01', 'Feb 02', 'Mar 05', 'Feb 04', 'Jan 05']
>>> sorted(lst, key=lambda d: datetime.strptime(d, '%b %d'))
['Jan 01', 'Jan 05', 'Feb 02', 'Feb 04', 'Mar 05']

Sort a list of dates by month in python


By : Alicia Johnson
Date : March 29 2020, 07:55 AM
it should still fix some issue Try sorted with key.
code :
from datetime import datetime
days_sorted = sorted(days, key=lambda day: datetime.strptime(day, "%d/%b/%Y"))

Sort list of list with dates strings python


By : user1709609
Date : March 29 2020, 07:55 AM
This might help you I'm trying to sort my list of list with a.sort(key=lambda x: x[0]) or a.sort(). The first element of my date is the day and I need to sort by it. , You can use str.split:
code :
a = [['1/8/2018', 71], ['10/8/2018', 76], ['11/8/2018', 6], ['12/8/2018', 60], ['13/8/2018', 81], ['14/8/2018', 74], ['15/8/2018', 7], ['16/8/2018', 77], ['17/8/2018', 81], ['18/8/2018', 69], ['19/8/2018', 66], ['2/8/2018', 81], ['20/8/2018', 74], ['21/8/2018', 88], ['22/8/2018', 92], ['23/8/2018', 90], ['24/8/2018', 84], ['25/8/2018', 66], ['26/8/2018', 64], ['27/8/2018', 82], ['28/8/2018', 82], ['29/8/2018', 79], ['3/8/2018', 8], ['4/8/2018', 64], ['5/8/2018', 64], ['6/8/2018', 12], ['7/8/2018', 8], ['8/8/2018', 83], ['9/8/2018', 77]]
new_a = sorted(a, key=lambda x:[int(i) for i in x[0].split('/')])
[['1/8/2018', 71], ['2/8/2018', 81], ['3/8/2018', 8], ['4/8/2018', 64], ['5/8/2018', 64], ['6/8/2018', 12], ['7/8/2018', 8], ['8/8/2018', 83], ['9/8/2018', 77], ['10/8/2018', 76], ['11/8/2018', 6], ['12/8/2018', 60], ['13/8/2018', 81], ['14/8/2018', 74], ['15/8/2018', 7], ['16/8/2018', 77], ['17/8/2018', 81], ['18/8/2018', 69], ['19/8/2018', 66], ['20/8/2018', 74], ['21/8/2018', 88], ['22/8/2018', 92], ['23/8/2018', 90], ['24/8/2018', 84], ['25/8/2018', 66], ['26/8/2018', 64], ['27/8/2018', 82], ['28/8/2018', 82], ['29/8/2018', 79]]

Python: Sort list of JSON by mm/dd/yyyy dates


By : David Copelovici
Date : March 29 2020, 07:55 AM
hope this fix your issue You got the wrong date 02/31/2014 (31 February). It is not possible
You can sort right dates like this:
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