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parse float in java with trailing junk


By : Arjay Almocera
Date : August 02 2020, 02:00 AM
To fix this issue The documentation for Double.valueOf(String) actually includes a regex that you can use to check whether a string is a double.
Here it is, without the comments:
code :
final String Digits     = "(\\p{Digit}+)";
final String HexDigits  = "(\\p{XDigit}+)";
final String Exp        = "[eE][+-]?"+Digits;
final String fpRegex    =
        ("[\\x00-\\x20]*"+
                "[+-]?(" +
                "NaN|"+
                "Infinity|" +
                "((("+Digits+"(\\.)?("+Digits+"?)("+Exp+")?)|"+
                "(\\.("+Digits+")("+Exp+")?)|"+
                "((" +
                "(0[xX]" + HexDigits + "(\\.)?)|" +
                "(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" +
                ")[pP][+-]?" + Digits + "))" +
                "[fFdD]?))" +
                "[\\x00-\\x20]*");
Matcher m = Pattern.compile(fpRegex).matcher(input);
if (m.find()) {
    String doublePartOnly = m.group();
}


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Remove junk trailing xml from an inputstream


By : user3334413
Date : March 29 2020, 07:55 AM
wish help you to fix your issue
I'm about to create a class that will take my InputStream, read through it until I find the junk, break, then take what I just wrote to, convert it back into an InputStream and pass it along like nothing happened. But I'm worried that it'll be grossly inefficient, have bugs I shouldn't have to deal with (e.g. breaking on binary values such as embedded images) and hopefully unnecessary.
code :
class WebStream extends FilterInputStream {

    byte[] buff = new byte[1024];
    int offset = 0, length = 0;

    public WebStream(InputStream i) {
        super(i);
    }

    @Override
    public boolean markSupported() {
        return false;
    }

    @Override
    public int read() throws IOException {
        if (offset == length)
            readNextChunk();
        if (length == -1)
            return -1;// eof
        return buff[offset++];
    }

    @Override
    public int read(byte[] b, int off, int len) throws IOException {
        if (offset == length)
            readNextChunk();
        if (length == -1)
            return -1;// eof

        int cop = length - offset;
        if (len < cop)
            cop = len;
        System.arraycopy(buff, offset, b, off, cop);
        offset += cop;
        return cop;
    }

    private void readNextChunk() throws IOException {
        if (offset <= length) {
            System.arraycopy(buff, offset, buff, 0, length - offset);
            length -= offset;
            offset = 0;
        }
        int read = in.read(buff, length, buff.length - length);
        if (read < 0 && length <= 0) {
            length = -1;
            offset = 0;
            return;
        }

        // note that this is assuming ascii compatible
        // anything like utf16 or utf32 will break here
        for (int i = length; i < read + length; i += 16) {
            if (buff[i] == 0x04) {
                while (buff[--i] == 0x04)
                    ;// find beginning of delim block
                length = i;
                read = 0;
            }
        }
    }

}

How can I make a DateTimeFormatter that accepts trailing junk?


By : user3311830
Date : March 29 2020, 07:55 AM
To fix this issue Use the parse() method that takes a ParsePosition, as that one doesn't fail when it doesn't read the entire text:
code :
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");

TemporalAccessor parse = formatter.parse("20140314 some extra text", new ParsePosition(0));
System.out.println(LocalDate.from(parse));

How can I convert a string to a float without losing trailing 0s in Java?


By : SandeepLoka
Date : March 29 2020, 07:55 AM
seems to work fine Usually when converting a string to a float you lose decimal trailing 0s. For specific reasons I need to keep exactly the number of trailing 0s I have in the string. The code I currently use for this is , Try this:
code :
float res = Float.parseFloat(avgStr);
System.out.printf("%.2f", res);
String st = "12.0000";
float dd = Float.valueOf(st);
int len = st.substring(st.indexOf(".") + 1, st.length()).length();
System.out.printf("%." + len + "f", dd);

Java keep trailing 0 in float operations


By : Lakkeri
Date : March 29 2020, 07:55 AM
Hope that helps You are confusing a number value and its formatting. It is not possible to actually store 1.80 as a float, however it is possible to display the number as a formatted String which forces two decimal places. Your options are:

Java float to string conversion with trailing zeros


By : Abhi
Date : March 29 2020, 07:55 AM
I wish this helpful for you If you want it to store the whole number, why don't you just use a String?
I guess if you are getting "1.10" from somewhere, you are getting it as a String (or you would be getting just a "1.1").
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