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Python SymPy Block Matrix TypeError


By : Mr. X
Date : August 01 2020, 08:00 PM
hop of those help? I am using the following code, but it's producing a TypeError (Data type not understood) for the last line (block matrix Z). I am new to SymPy. Could someone please point out my mistake? , The argument should be a list of lists:
code :
Z = sp.BlockMatrix([[i.T*i, i.T*X], [X.T*i, X.T*X]])

Z:
⎡[3]   [6  6  6]  ⎤
⎢                 ⎥
⎢⎡6⎤  ⎡14  14  14⎤⎥
⎢⎢ ⎥  ⎢          ⎥⎥
⎢⎢6⎥  ⎢14  14  14⎥⎥
⎢⎢ ⎥  ⎢          ⎥⎥
⎣⎣6⎦  ⎣14  14  14⎦⎦


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In python sympy, how do I apply an external python funtion to each element of the sympy matrix?


By : mygodccl
Date : March 29 2020, 07:55 AM
hop of those help? To be more specific, I want to apply the following sigmoid function:
code :
>>> M.applyfunc(sigmoid)

Matrix([
[1/(exp(-1) + 1), 1/(exp(-3) + 1)],
[1/(exp(-2) + 1), 1/(exp(-4) + 1)]])
class sigmoid(Function):
    pass
>>> M.applyfunc(sigmoid)
Matrix([
[sigmoid(1), sigmoid(3)],
[sigmoid(2), sigmoid(4)]])

sympy nsolve typeError with Matrix starting vector


By : user1507283
Date : March 29 2020, 07:55 AM
it helps some times The workaround you have is necessary, given the following:
nsolve passes the x0 argument directly to mpmath.findroot, on this line findroot only supports iterables in x0 that satisfy isinstance(x0, (list, tuple)), on this line. Moreover it has to be a flat tuple or list; its elements are assumed to be scalars in the subsequent x0 = [ctx.convert(x) for x in x0].

Can sympy simplify block matrix expressions?


By : user1655866
Date : March 29 2020, 07:55 AM
Any of those help Yes, using the function block_collapse which evaluates block-matrix expressions down to the level of blocks.
code :
sy.block_collapse(A.inverse()*M)   

Access different blocks (submatrices) of a symbolic block matrix in SymPy


By : user1733969
Date : March 29 2020, 07:55 AM
seems to work fine The (i, j) block of a block matrix C is accessed with C.blocks[i, j]. An example:
code :
from sympy import *
b = Matrix([1, 2, 4, 8])
C = BlockMatrix([[b, 3*b], [5*b, 7*b]])
print(C.blocks[0, 1])

creating a block band diagonal matrix in sympy


By : Bas Wesselink
Date : March 29 2020, 07:55 AM
it helps some times I would like to create a block band diagonal matrix using sympy. Basically, the matrix should look like , The recently added banded might be a solution for you:
code :
>>> size=3
>>> var('d n r')
(d, n, r)
>>> banded(size,{0:d,1:n,-1:r})
Matrix([
[d, n, 0],
[r, d, n],
[0, r, d]])
>>> banded(2*size, {0:D,2:N,-2:R})
Matrix([
[      a, b - I*c,       e,     I*f,       0,       0],
[b + I*c,       d,       g,    -I*h,       0,       0],
[      e,       g,       a, b - I*c,       e,     I*f],
[   -I*f,     I*h, b + I*c,       d,       g,    -I*h],
[      0,       0,       e,       g,       a, b - I*c],
[      0,       0,    -I*f,     I*h, b + I*c,       d]])
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