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finding the sum of two integers in array that match an element in another array


By : wadethefred
Date : August 01 2020, 12:00 PM
this will help The function takes two arrays arr1 and arr2 return true of any two integers in arr1 sums up to any element in arr2.I tried to do it but it's giving me a runtime error. , You can do something like this below :
code :
for i in range(0, len(arr1)):
    for j in range(1, len(arr1)):
        if arr1[i] + arr1[j] in arr2:
            print("TRUE")
print("FALSE")


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PHP Multi-Dimensional Array: Finding a multi-element sub-array match ... is there an alternate option to looping?


By : Axeniel Cua
Date : March 29 2020, 07:55 AM
may help you . I think that you should do a preprocessing on the log doing a hash (or composed key) of row_id and source_tbl and store it in an hashmap then for each row just construct the hash of the key and check if it is already defined in the hashmap.
I am telling you to use hashed set because you can search in it with O(k) time otherwise it would be the same as you are proposing only that it would be a cleaner code.

Finding the largest mirror image of integers present in an array of integers [CodingBat riddle: MaxMirror]


By : Faoiltiama Mckinney
Date : March 29 2020, 07:55 AM
To fix the issue you can do The fix made the flag was not being set to false in the outer loop the fix is not visible here

Finding the first combination of two integers in an array whose latter element appears the earliest and sum matches a gi


By : Linquan Chen
Date : March 29 2020, 07:55 AM
I wish this helpful for you I would use Set (which would be a bit more efficient than using Array#include?) and do something like this:
code :
array = [10, 5, 1, 9, 7, 8, 2, 4, 6, 9, 3, 2, 1, 4, 8, 7, 5]
sum_of_two = 10

require 'set'

array.each_with_object(Set.new) do |element, set| 
  if set.include?(sum_of_two - element)
    break [sum_of_two - element, element]
  else
    set << element
  end
end
#=> [1, 9]

Finding string element in array with integers using lodash includes not working


By : Ehbencom
Date : March 29 2020, 07:55 AM
like below fixes the issue If your pins array is as simple as that, you don't need anything just vanilla JavaScript.
code :
new Vue({
  el: "#app",
  data: {
    pins: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
    pin: '',
    result: ''
  },
  methods: {
    isThisPin() {
      if (this.pin) {
        this.result = this.pins.includes(Number(this.pin))
      } else {
        this.result = ''
      }
    }
  }
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.17/vue.js"></script>
<div id="app">
  <label>IS THIS PIN: <input type="number" v-model="pin" @input="isThisPin"></label>
  <br /> RESULT: {{result}}
</div>

Finding a sum of two elements in an array of integers and returning the indexes of first match of two elements, work for


By : scandey
Date : March 29 2020, 07:55 AM
should help you out The inner loop condition index2 < nums.length - 1 is incorrect, it should be index2 < nums.length. For instance if you are given
code :
nums = {1, 2, 3, 4} target = 7
for (index=0; index < nums.length; index++) {
   for (int index2 = index + 1 ; index2 < nums.length - 1; index2++) {
       ...
   }
public int[] twoSum(int[] nums, int target) {
  for (int i = 0; i < nums.length; ++i) 
    for (int j = i + 1; j < nums.length; ++j) 
      if (nums[i] + nums[j] == target) 
        return new int[] {i, j};   // we've found it! Let's return it 

  return new int[0]; // let's return an empty array, not {0, 0} one  
}
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