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Comparison behavior of ' <' operator


By : Sim Xing
Date : August 01 2020, 07:00 AM
around this issue Since char[100] doesn't have an operator<, you fall back to operator< for char*. That was not what you intended - it returns the first object in memory. And v[0] definitely precedes v[1].
You want std::string, where operator< is overloaded to do what you want.
code :


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Weird behavior of comparison operator JavaScript when using empty array


By : Nicolas Fantini
Date : March 29 2020, 07:55 AM
seems to work fine They're not identical. Object identity is defined by both operands pointing to the same instance.
code :
var a = [],
    b = [];
a == b; // false
a == a; // true

Oracle SQL comparison operator(ALL) behavior


By : Revital Sheleg
Date : March 29 2020, 07:55 AM
like below fixes the issue When you use >= ALL (...), the check is that your value is greater than or equal to the largest value in the list. Your list, in this case, is (80,90,100), so only those values which are greater than or equal to 100 are part of the result set.
Check this link for a more thorough understanding of ALL: http://www.oracle-base.com/articles/misc/all-any-some-comparison-conditions-in-sql.php
code :
select first_name|| ' ' || last_name "Name", department_id 
from employees 
where department_id in (80, 90, 100);

Ternary operator strange behavior while doing comparison of number


By : Abdel' Yahya
Date : March 29 2020, 07:55 AM
Hope this helps You are checking whether the variable rowind is equal to empty string in your condition.
code :
((rowind == '')) // this will return as false since you variable is not an empty string. Rather it contains a string with 0 character
((rowind == '0')) //This will return true since the string is as same as the variable.
console.log(0 == '0');  //True
console.log(0 == '');   //True
console.log('' == '0'); //False
console.log(3 == '3') //True
console.log(3 === '3') //False

C++ comparison operator overload confusing behavior


By : 宋智春
Date : March 29 2020, 07:55 AM
it helps some times
Comparing A instances with B ones, the A class operator is called, is this the correct behavior?
code :
struct A {
    int getN() const { return _n; }  

    virtual bool equals(A &other) const {
        return getN() == other.getN();
    }

    friend bool operator==(const A &one, const A &other);

    A(int n) : _n(n) { }

private:
    int _n;
};

struct B : public A
{
    B(int n, int m = 0) : A(n), _m(m) { }
    virtual bool equals(B &other) const {
        return A::equals(*this, other) && _m == other._m;
    }
private:
    int _m;
};

bool operator==(const A &one, const A &other) {
    return typeid(one)==typeid(two) && one.equals(two);
}

Behavior of VHDL comparison operator with integer argument


By : peter stallone
Date : March 29 2020, 07:55 AM
should help you out I cannot confirm the behavior that you are seeing "in your experience". Here is my vetsmod code example.
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