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Message format on giving desired output

By : Justin Crapse
Date : August 01 2020, 06:00 AM
this one helps. I am trying to replace the {0} in a String with a value. The code I have written for it is: , Try the below code :
code :
 String formattedText = MessageFormat.format("''{0}''", "1");

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DateFormat not giving date in the desired format

By : Evan
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I want to get the current date in the following format yyyy_mm_dd , Use upper case MM, lower case mm is for minutes.
code :
DateFormat date = new SimpleDateFormat("yyyy_MM_dd");

Not giving desired output in python

By : Wilker Mesquita
Date : March 29 2020, 07:55 AM
will be helpful for those in need As I mentioned in a comment, the input you provided doesn't match your description thereof. Your code shows the year field starting at index 88, but your provided input is only 44 characters long. I'd start there.
EDIT: here is how I would write your program, given you can't use any containers.
code :
def filter_results(input_file, output_file, year):
    for line in input_file:
        if not line: continue # skips if the line is blank
        if year == '' or line[88:92].startswith(year) or year.lower() == 'all':

def main():
    year = input("Give me a year: ")

    try: infile = open('measles.txt','r')
    except IOError: print("Error opening file: measles.txt")

    try: outfile = open(input("Name of output file?"),'w')
    except IOError: print("Error opening output file")

    try: infile,outfile
    except NameError: raise IOError("One of the files could not be opened")



lines = list()
with open('path/to/input_file') as input_file:
    for line in input_file:
        # I may have screwed up that string splicing -- do one and doublecheck
year = input("Enter a four-digit year (or part thereof): ")
filtered_list = [line for line in lines if line['year'].startswith(year)]
while True:
        input_file = open("measles.txt")
        break # ?
    except IOError:
        print("Error opening file:",input_file)
        break # ?

Regex not giving output as desired

By : user3705901
Date : March 29 2020, 07:55 AM
hop of those help? I am using the regex - [{]{[}][}] for the input {{id}} The output I expect is id. But I am getting {{id}}. , You use patter group incorrectly. Try this one:
code :
String patternString = "[{][{](?<id>.*)[}][}]";
// String patternString = "\\{\\{(?<id>[^}]+)}}";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(string);
List<String> allMatches = new ArrayList<>();
while (matcher.find()) {
String patternString = "[{][{](.*)[}][}]";
//String patternString = "\\{\\{([^}]+)}}";
Pattern pattern = Pattern.compile(patternString);
Matcher matcher = pattern.matcher(string);
List<String> allMatches = new ArrayList<>();
while (matcher.find()) {

Javascript not giving the desired output

By : Bharathi Anuchuri
Date : March 29 2020, 07:55 AM
Hope this helps No difference, " " and ' ' are two different way to write the same string literal and the function shouldn't be able to discover which one was used.
Could you reproduce a situation where they would behave differently? Can you post a minimum snippet on jsfiddle?

My code is not giving the desired output

By : Alisha Bussart
Date : March 29 2020, 07:55 AM
hop of those help? My text file has the following information , Why are you doing this?
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