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Convert Maybe String to (Maybe?) Integer

By : Artem Valiulin
Date : August 01 2020, 05:00 AM
I think the issue was by ths following , Use Text.Read.readMaybe
code :
> readMaybe "123" :: Maybe Int
Just 123

> readMaybe "hello" :: Maybe Int
import Text.Read

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Is it possible to convert the String value we are getting by intent via get string extra into integer with Integer.parse

By : Ahmet Sakal
Date : March 29 2020, 07:55 AM
I wish this helpful for you This happens because you are trying to parse a String that does not match with an integer, in order to avoid this, use NumberFormatException thrown by parseInt
code :
String a=qw.getStringExtra("19");  // 19 is the extra name, right???
int b = 0;
try {
    b= Integer.parseInt(a);
} catch (NumberFormatException e) {
    // tell error because extra string is not an integer number

Can't convert string to an integer in VBA or by Excel formulas (failure to convert or wrong number even if string is all

By : Amorino89
Date : March 29 2020, 07:55 AM
To fix the issue you can do You can identify this error (overflow) in your error-handling block using the Description property of the intrinsic Err object:
code :
MsgBox "Failed to convert """ & v1 & """ to an integer." & vbCrLf & Err.Description, , "Aborting - Failed Conversion" 
Dim tempArray As Variant
Dim arraySize As Double
arraySize = (Len(v1) - 1)
ReDim tempArray(arraySize)
Sub foo()
Dim lrg As New cLarge

MsgBox lrg.LargeAdd("105501008962100001", "205501231962100003")
End Sub
'### Class module for adding very large (> Decimal precision) values
'    http://tushar-mehta.com/misc_tutorials/project_euler/LargeNumberArithmetic.htm
'    Modified by David Zemens, 9 December 2015
Option Explicit

Public cDecMax As Variant, cDecMaxLen As Integer, cSqrDecMaxLen As Integer
Private pVal As String

Public Sub Class_Initialize()
    Static Initialized As Boolean
    If Initialized Then Exit Sub
    Initialized = True
    cDecMax = _
        CDec(Replace("79,228,162,514,264,337,593,543,950,335", ",", ""))
            'this is 2^96-1, the limit on Decimal precision data in Excel/VBA
    cDecMaxLen = Len(cDecMax) - 1
    cSqrDecMaxLen = cDecMaxLen \ 2
End Sub

Function Ceil(X As Single) As Long
    If X < 0 Then Ceil = Fix(X) Else Ceil = -Int(-X)
End Function

Private Function addByParts(ByVal Nbr1 As String, ByVal Nbr2 As String) _
    As String
    Dim NbrChunks As Integer
    If Len(Nbr1) > Len(Nbr2) Then _
        Nbr2 = String(Len(Nbr1) - Len(Nbr2), "0") & Nbr2 _
    Else _
        Nbr1 = String(Len(Nbr2) - Len(Nbr1), "0") & Nbr1
    NbrChunks = Ceil(Len(Nbr1) / cDecMaxLen)
    Dim I As Integer, OverflowDigit As String, Rslt As String
    OverflowDigit = "0"
    For I = NbrChunks - 1 To 0 Step -1
        Dim Nbr1Part As String
        Nbr1Part = Mid(Nbr1, I * cDecMaxLen + 1, cDecMaxLen)
        Rslt = CStr(CDec(Nbr1Part) _
            + CDec(Mid(Nbr2, I * cDecMaxLen + 1, cDecMaxLen)) _
            + CDec(OverflowDigit))
        If Len(Rslt) < Len(Nbr1Part) Then
            Rslt = String(Len(Nbr1Part) - Len(Rslt), "0") & Rslt
            OverflowDigit = "0"
        ElseIf I = 0 Then
        ElseIf Len(Rslt) > Len(Nbr1Part) Then
            OverflowDigit = Left(Rslt, 1): Rslt = Right(Rslt, Len(Rslt) - 1)
            OverflowDigit = "0"
            End If
        addByParts = Rslt & addByParts
        Next I
End Function

Function LargeAdd(ByVal Nbr1 As String, ByVal Nbr2 As String) As String
    If Len(Nbr1) <= cDecMaxLen And Len(Nbr2) <= cDecMaxLen Then
        LargeAdd = CStr(CDec(Nbr1) + CDec(Nbr2))
        Exit Function
        End If
    If Len(Nbr1) > cDecMaxLen Then LargeAdd = addByParts(Nbr1, Nbr2) _
    Else LargeAdd = addByParts(Nbr2, Nbr1)
End Function

How can I convert string to integer and access each individual char in string as integer?

By : Karan Nimrani
Date : March 29 2020, 07:55 AM
wish helps you , This is very easy, to get your String as an integer use:
code :
no = Integer.parseInt(s);
char[] charArray = ("" + no).toCharArray();
int x = Character.getNumericValue(charArray.charAt(0)); // or any index instead of 0

how to convert integer variable having values greater than the integer size to string in talend

By : Nick Pullen
Date : March 29 2020, 07:55 AM
Hope this helps Don't use Integer. Switch to Long or BigDecimal, depending on your requirements.

Read multiple integer columns as string, trying to gsub and convert back to integer

By : André Lucas
Date : March 29 2020, 07:55 AM
hop of those help? Try using dplyr::mutate_at() to select multiple columns and apply a transformation to them.
code :
ItemStats_2014 <- ItemStats_2014 %>%
    mutate_at(intColList, funs(as.integer(gsub(',', '', .))))
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