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Convert Maybe String to (Maybe?) Integer


By : Artem Valiulin
Date : August 01 2020, 05:00 AM
I think the issue was by ths following , Use Text.Read.readMaybe
code :
> readMaybe "123" :: Maybe Int
Just 123

> readMaybe "hello" :: Maybe Int
Nothing
import Text.Read


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Is it possible to convert the String value we are getting by intent via get string extra into integer with Integer.parse


By : Ahmet Sakal
Date : March 29 2020, 07:55 AM
I wish this helpful for you This happens because you are trying to parse a String that does not match with an integer, in order to avoid this, use NumberFormatException thrown by parseInt
code :
String a=qw.getStringExtra("19");  // 19 is the extra name, right???
int b = 0;
try {
    b= Integer.parseInt(a);
} catch (NumberFormatException e) {
    // tell error because extra string is not an integer number
}

Can't convert string to an integer in VBA or by Excel formulas (failure to convert or wrong number even if string is all


By : Amorino89
Date : March 29 2020, 07:55 AM
To fix the issue you can do You can identify this error (overflow) in your error-handling block using the Description property of the intrinsic Err object:
code :
100:
MsgBox "Failed to convert """ & v1 & """ to an integer." & vbCrLf & Err.Description, , "Aborting - Failed Conversion" 
End
Dim tempArray As Variant
Dim arraySize As Double
arraySize = (Len(v1) - 1)
ReDim tempArray(arraySize)
Sub foo()
Dim lrg As New cLarge

MsgBox lrg.LargeAdd("105501008962100001", "205501231962100003")
End Sub
'### Class module for adding very large (> Decimal precision) values
'    http://tushar-mehta.com/misc_tutorials/project_euler/LargeNumberArithmetic.htm
'
'    Modified by David Zemens, 9 December 2015
Option Explicit

Public cDecMax As Variant, cDecMaxLen As Integer, cSqrDecMaxLen As Integer
Private pVal As String

Public Sub Class_Initialize()
    Static Initialized As Boolean
    If Initialized Then Exit Sub
    Initialized = True
    cDecMax = _
        CDec(Replace("79,228,162,514,264,337,593,543,950,335", ",", ""))
            'this is 2^96-1, the limit on Decimal precision data in Excel/VBA
    cDecMaxLen = Len(cDecMax) - 1
    cSqrDecMaxLen = cDecMaxLen \ 2
End Sub


Function Ceil(X As Single) As Long
    If X < 0 Then Ceil = Fix(X) Else Ceil = -Int(-X)
End Function

Private Function addByParts(ByVal Nbr1 As String, ByVal Nbr2 As String) _
    As String
    Dim NbrChunks As Integer
    If Len(Nbr1) > Len(Nbr2) Then _
        Nbr2 = String(Len(Nbr1) - Len(Nbr2), "0") & Nbr2 _
    Else _
        Nbr1 = String(Len(Nbr2) - Len(Nbr1), "0") & Nbr1
    NbrChunks = Ceil(Len(Nbr1) / cDecMaxLen)
    Dim I As Integer, OverflowDigit As String, Rslt As String
    OverflowDigit = "0"
    For I = NbrChunks - 1 To 0 Step -1
        Dim Nbr1Part As String
        Nbr1Part = Mid(Nbr1, I * cDecMaxLen + 1, cDecMaxLen)
        Rslt = CStr(CDec(Nbr1Part) _
            + CDec(Mid(Nbr2, I * cDecMaxLen + 1, cDecMaxLen)) _
            + CDec(OverflowDigit))
        If Len(Rslt) < Len(Nbr1Part) Then
            Rslt = String(Len(Nbr1Part) - Len(Rslt), "0") & Rslt
            OverflowDigit = "0"
        ElseIf I = 0 Then
        ElseIf Len(Rslt) > Len(Nbr1Part) Then
            OverflowDigit = Left(Rslt, 1): Rslt = Right(Rslt, Len(Rslt) - 1)
        Else
            OverflowDigit = "0"
            End If
        addByParts = Rslt & addByParts
        Next I
End Function

Function LargeAdd(ByVal Nbr1 As String, ByVal Nbr2 As String) As String
    'Initialize
    If Len(Nbr1) <= cDecMaxLen And Len(Nbr2) <= cDecMaxLen Then
        LargeAdd = CStr(CDec(Nbr1) + CDec(Nbr2))
        Exit Function
        End If
    If Len(Nbr1) > cDecMaxLen Then LargeAdd = addByParts(Nbr1, Nbr2) _
    Else LargeAdd = addByParts(Nbr2, Nbr1)
End Function

How can I convert string to integer and access each individual char in string as integer?


By : Karan Nimrani
Date : March 29 2020, 07:55 AM
wish helps you , This is very easy, to get your String as an integer use:
code :
no = Integer.parseInt(s);
char[] charArray = ("" + no).toCharArray();
int x = Character.getNumericValue(charArray.charAt(0)); // or any index instead of 0

how to convert integer variable having values greater than the integer size to string in talend


By : Nick Pullen
Date : March 29 2020, 07:55 AM
Hope this helps Don't use Integer. Switch to Long or BigDecimal, depending on your requirements.

Read multiple integer columns as string, trying to gsub and convert back to integer


By : André Lucas
Date : March 29 2020, 07:55 AM
hop of those help? Try using dplyr::mutate_at() to select multiple columns and apply a transformation to them.
code :
ItemStats_2014 <- ItemStats_2014 %>%
    mutate_at(intColList, funs(as.integer(gsub(',', '', .))))
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