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Merging two JSON values as one to array


By : Billy O'Connor
Date : August 01 2020, 05:00 AM
To fix this issue I have a JSON object like , You can try this,
code :
var obj = JSON.parse(countrylist);
var countries=Object.values(countrylist);


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Merging JSON and overwriting values


By : dhansen
Date : March 29 2020, 07:55 AM
To fix this issue with $.extend the second object replaces the values in the first object: http://api.jquery.com/jquery.extend/
code :
var obj1 = {
    "name":"bob",
    "age":99,
    "occupation":"builder"
}

var obj2 = {
    "name":"Joe",
    "age":23,
}

jQuery.extend(obj1, obj2);
for (var j in obj1) {
        alert(j + " " + obj1[j]);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
var obj1 = {
        "name":"bob",
        "age":99
    }

    var obj2 = {
        "name":"Joe",
        "age":23,
        "occupation":"builder"
    }
    if(Object.keys(obj1).length>Object.keys(obj2).length)
    jQuery.extend(obj1, obj2);
else
  jQuery.extend(obj2,obj1);
    for (var j in obj1) {
            alert(j + " " + obj1[j]);
    }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

Merging and adding values of 2 JSON feeds in PHP


By : Thang Vu
Date : March 29 2020, 07:55 AM
it helps some times I'm trying to write a shopping list app for a website which already has ingredients listed in JSON. , You can use the following code to get the expected result:
code :
<?php
$a = '{"ingredients":[{"name": "Sunflower oil","quantity": 100,"measure": "ml"},{"name": "Olive oil","quantity": 50,"measure": "ml"}]}';
$b = '{"ingredients":[{"name": "Sunflower oil","quantity": 10,"measure": "ml"},{"name": "Fennel seeds","quantity": 1,"measure": "teaspoon"},{"name": "Garlic","quantity": 1,"measure": "clove"}]}';

$aArr = json_decode($a, true);
$bArr = json_decode($b, true);
$sumArr = array("ingredients" => array());

foreach ($aArr['ingredients'] as $valA) {
    foreach ($bArr['ingredients'] as $keyB => $valB) {
        if ($valA['name'] == $valB['name'] && 
            $valA['measure'] == $valB['measure']) {

            $valA['quantity'] += $valB['quantity'];
            $sumArr['ingredients'][] = $valA;

            unset($bArr['ingredients'][$keyB]);
            continue 2;
        } 
    }
    $sumArr['ingredients'][] = $valA;
}
$sumArr['ingredients'] = array_merge($sumArr['ingredients'], $bArr['ingredients']);
print_r( json_encode( $sumArr ));
?>

Merging array values into single key and multiple values in php


By : user3842728
Date : March 29 2020, 07:55 AM
it should still fix some issue This line does nothing because it is superseded just a bit later as the same variable is being set:
code :
$aExtraFilter2[$extrafilterkey] = [];
array_push($extrafiltervalue, $value['value']);
// fill array of arrays
$aExtraFilter2 = [];
foreach ($aExtraFilter as $key => $value) {
    if (!array_key_exists($value['key'], $aExtraFilter2)) $aExtraFilter2[$value['key']] = [];
    $aExtraFilter2[$value['key']][] = $value['value'];
}
// convert to string (if needed at all, depends on what you're doing later)
foreach ($aExtraFilter2 as $key => $set) {
    $aExtraFilter2[$key] = join(',', $set);
}

Merging two json arrays (loaded into memory) into one json array


By : Brijendra Pratap Sin
Date : March 29 2020, 07:55 AM
it helps some times I have two json array, which i have initialised as given below. , Use +, not *:
code :
#!/bin/sh

j1='[{"account_id":"01C","id":"0XVWKCFV6P9CA5"},{"account_id":"CSDTHQ","id":"631QGYBNSF"}]'
j2='[{"account_id":"BJPKWSH","id":"15BS0XP4F91V6YH4G0PV"},{"account_id":"01BKK44V5F6A1FKH60Q0ANX9JX","id":"01BKK44V7"}]'
echo $(jq -s '.[0] + .[1]' <<EOF
$j1
$j2
EOF
)
[ { "account_id": "01C", "id": "0XVWKCFV6P9CA5" }, { "account_id": "CSDTHQ", "id": "631QGYBNSF" }, { "account_id": "BJPKWSH", "id": "15BS0XP4F91V6YH4G0PV" }, { "account_id": "01BKK44V5F6A1FKH60Q0ANX9JX", "id": "01BKK44V7" } ]

Merging an array of JSON objects to one JSON column in Postgres


By : user3091220
Date : March 29 2020, 07:55 AM
wish help you to fix your issue demo:db<>fiddle
Use json_object_agg():
code :
SELECT
  p.product_id AS product_id,
  json_object_agg(e.key, e.value)
FROM
  products AS p
JOIN
  products_ext AS e ON p.product_id = e.product_id
GROUP BY p.product_id;
SELECT
  p.product_id AS product_id,
  COALESCE(
      json_object_agg(e.key, e.value) FILTER (WHERE e.key IS NOT NULL),
      '{}'
  )
FROM
  products AS p
LEFT JOIN
  products_ext AS e ON p.product_id = e.product_id
GROUP BY p.product_id;
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