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Python - why '&' and 'and' operators provide different results though evaluate the condition with same result


By : Adam Chesney
Date : July 31 2020, 10:00 PM
wish of those help
why are the results different? Why is '&' giving wrong answer?
code :


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Why does return/redo evaluate result functions in the calling context, but block results are not evaluated?


By : Ian Morrison
Date : March 29 2020, 07:55 AM
this will help The short answer is because it is generally unnecessary to evaluate a block at the call point, because blocks in Rebol don't take parameters so it mostly doesn't matter where they are evaluated. However, that "mostly" may need some explanation...
It comes down to two interesting features of Rebol: static binding, and how do of a function works.
code :
>> a: 10 do do has [a] [a: 20 [a]]
** Script error: a word is not bound to a context
** Where: do
** Near: do do has [a] [a: 20 [a]]
>> a: 10 do has [a] [a: 20 return/redo does [a]]
** Script error: a word is not bound to a context
** Where: function!
** Near: [a: 20 return/redo does [a]]
>> do f: function [x] [a: 10 either zero? x [do f 1] [a: 20 [a]]] 0
== 10
>> do f: function [x] [a: 10 either zero? x [f 1] [a: 20 return/redo does [a]]] 0
== 10

SQL Server / T-SQL: Does CHOOSE evaluate all results, or just the result being returned?


By : Schuss
Date : March 29 2020, 07:55 AM
wish of those help It would appear that it does not perform all the computations. Both examples below contain a 1/0 option, but only 1 of the statements below will error on a divide by zero error:
code :
select CHOOSE(2, 1, 1+4, 1/0)
select CHOOSE(2, 1, 1/0, 1+4)

Compare each row string from columns and add condition to evaluate and print the result in new column


By : user2493214
Date : March 29 2020, 07:55 AM
wish helps you I have a dataframe as below
code :
string1 <-c(T,T,F)
string2 <-c(T,F,F)
var1 <- c(1,0,0)
var2 <- c(1,1,0)
df <- data.frame(string1,string2,var1,var2)
df
  string1 string2 var1 var2
1    TRUE    TRUE    1    1
2    TRUE   FALSE    0    1
3   FALSE   FALSE    0    0
df$new_column <- apply(df, 1, function(x) ifelse(x[1] == T & x[2] == T & x[3] > 0 & x[4] > 0, x[1]+x[2], NA))
df
  string1 string2 var1 var2 new_column
1    TRUE    TRUE    1    1          2
2    TRUE   FALSE    0    1         NA
3   FALSE   FALSE    0    0         NA

Python - chaining of or operators in if statement don't provide expected results


By : Chris McCullins
Date : March 29 2020, 07:55 AM
With these it helps Trying to chain OR operators in an if statement to cut down on redundant code but it seems only the first 2 operators are executed. , Another alternative
code :
if a not in ["sql", "csv"]:

Laravel provide different result when using where condition with update


By : user3412356
Date : March 29 2020, 07:55 AM
it helps some times Condition 1: , please chnage your code
it is integer value
code :
update([$updateField => 1]);
$update=Model:where(..)->Where(..)->Where(..)->update([$updateField => 1]);
 if($update==1)
{
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