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Different uses of noexcept


By : Lionel Bouchat
Date : July 31 2020, 05:00 PM
I wish this help you The language grammar allows only the noexcept specifier to appear in that position.
Therefore your first point is correct. g() will be marked noexcept, because f() returns true.
code :
void g() noexcept(noexcept(f()))
{
    f();
}


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How to declare noexcept if only a member function of an attribute is noexcept?


By : Rubengcv
Date : March 29 2020, 07:55 AM
hop of those help? As a work around, you may use (which works for gcc 4.7.1, gcc 4.8.1 and clang 3.4):
code :
void swap(A& other) noexcept(noexcept(std::declval<decltype(A::vec)&>().swap(std::declval<decltype(A::vec)&>())))
void swap(A& other) noexcept(noexcept(vec.swap(vec)))

C++ omitting `noexcept` specifier versus `noexcept(false)`, what is their precise meaning?


By : user3517599
Date : March 29 2020, 07:55 AM
Does that help By specifying noexcept(true), you claim that the function never throws exceptions. By specifying noexcept(false), or not specifying anything, you do not claim that the function never throws exceptions.
So it's basically your statement (2), but note that for the compiler, that's equivalent to your statement (1). If the compiler is not assured that the function will not throw, it must assume that it can.

Using the noexcept operator to chain noexcept declarations


By : tmt
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Why does the noexcept operator take an expression rather than a function signature/declaration?
code :
void method1() noexcept(noexcept(strProcessor(""))) {
//   Second 'noexcept'  ^^^^^^^^^                ^
void method2() noexcept(noexcept(
    (std::declval<Type>().*&Type::method1)()
)) {};

Protected noexcept constructor doesn't seem noexcept from derived class. Why?


By : Ching Ching Yeung
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further std::is_nothrow_constructible and std::is_nothrow_move_constructible check if the expression
code :
T obj(std::declval<Args>()...);

C++11 - How to fix noexcept operator that fails to detect function declaration with noexcept specifier


By : John Anderson
Date : March 29 2020, 07:55 AM
Hope this helps I'm setting up a new library for personal research purpose, and i'm trying to fully understand c++ standard library tools and core functionalities. Now i have a problem understanding the noexcept operator. , Your first test, don't work: This pass
code :
void no_throw() noexcept(true) {};
void do_throw() noexcept(false) {};

static_assert(noexcept(no_throw), "");
static_assert(noexcept(do_throw), "");
void no_throw() noexcept(true) {};
void do_throw() noexcept(false) {};

static_assert(noexcept(no_throw()), "");
static_assert(!noexcept(do_throw()), "");
template<class T>
   struct TD;

TD<decltype(no_throw)> e;
TD<decltype(std::declval<decltype(no_throw)>())> e2;
prog.cc:14:24: error: aggregate 'TD<void()> e' has incomplete type and cannot be defined
 TD<decltype(no_throw)> e;
                        ^
prog.cc:15:50: error: aggregate 'TD<void (&)()> e2' has incomplete type and cannot be defined
 TD<decltype(std::declval<decltype(no_throw)>())> e2;
prog.cc:14:24: error: aggregate 'TD<void() noexcept> e' has incomplete type and cannot be defined
 TD<decltype(no_throw)> e;
                        ^
prog.cc:15:50: error: aggregate 'TD<void (&)() noexcept> e2' has incomplete type and cannot be defined
 TD<decltype(std::declval<decltype(no_throw)>())> e2;
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