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Python challenge I cannot solve


By : seangeleno
Date : July 31 2020, 07:00 AM
this will help You can try something like this to change a number into what that code would represent in asci text:
code :
>>> hidden_invite=[105, 117, 117, 113, 116, 59, 48, 48, 120, 120, 120, 47, 103, 98, 100, 102, 99, 112, 112, 108, 47, 100, 112, 110, 48, 104, 115, 112, 118, 113, 116, 48, 51, 49, 51, 50, 54, 49, 54, 52, 56, 54, 55, 53, 54, 56, 55, 48, 33, 33, 33, 33, 36, 33, 122, 112, 118, 115, 33, 106, 111, 119, 106, 117, 102, 33, 100, 112, 101, 102, 33, 106, 116, 33, 81, 115, 112, 110, 102, 117, 105, 102, 118, 116]
>>> ''.join([chr(i-1) for i in hidden_invite])
# 'https://www.facebook.com/groups/202150537564576/    # your invite code is Prometheus'
# Also not sure why the number is 'off by one',
# is that a mistake, or is this supposed to be like a basic cipher?
>>> chr(105)
'i'
>>> ord('i')
105


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Can anybody solve this programming challenge?


By : Maruko Chan
Date : March 29 2020, 07:55 AM
I wish this help you I don't see anything particularly special about a solution in the Go programming language. For example,
code :
// The Love-Letter Mystery
// https://www.hackerrank.com/challenges/the-love-letter-mystery

package main

import (
    "bufio"
    "fmt"
    "io"
    "os"
    "strconv"
)

// palindrome returns the minimum number of operations carried out
// to convert a word into a palindrome.
// A word is a set of lower-case ASCII letters.
func palindrome(word string) (ops int) {
    for i, j := 0, len(word)-1; i < j; i, j = i+1, j-1 {
        n := int(word[i]) - int(word[j])
        if n < 0 {
            n = -n
        }
        ops += n
    }
    return ops
}

func main() {
    scanner := bufio.NewScanner(os.Stdin)
    if scanner.Scan() {
        t, err := strconv.Atoi(scanner.Text())
        if err != nil {
            fmt.Fprintln(os.Stderr, "reading input:", err)
            t = 0
        }
        for ; t > 0 && scanner.Scan(); t-- {
            fmt.Println(palindrome(scanner.Text()))
        }
        if t > 0 {
            fmt.Fprintln(os.Stderr, "reading input:", io.ErrUnexpectedEOF)
        }
    }
    if err := scanner.Err(); err != nil {
        fmt.Fprintln(os.Stderr, "reading input:", err)
    }
}
3
abc
abcba
abcd
2
0
4
3
cba
cbabc
dcba
2
0
4

Need help to solve the hackerrank challenge


By : MsLeece
Date : March 29 2020, 07:55 AM
I hope this helps you . For the following code, pass in A as the original array and B as the sorted array.
code :
private static boolean CheckSingleSwap(int[] A, int[] B)
{
    int L = A.length;
    int firstSwap = -1, secondSwap = -1;
    for(int i = 0; i < L; i++)
    {
        if(A[i] != B[i])
        {
            if (firstSwap == -1)
                firstSwap = i;
            else if (secondSwap == -1 && A[i] == B[firstSwap] && A[firstSwap] == B[i])
                secondSwap = i;
            else
                return false;
        }
    }
    if (firstSwap != -1 && secondSwap != -1)
    {
        System.out.println("yes");
        System.out.println("swap " + (firstSwap + 1) + " " + (secondSwap + 1));
        return true;
    }
    System.out.println("array is already sorted!");
    return false; // or whatever you decide to do; maybe even an exception or enumerated type
}
private static boolean CheckSingleReverse(int[] A, int[] B)
{
    // find region
    int L = A.length;
    int diffStart = -1, diffEnd = -1; boolean mid = false, found = false;
    for (int i = 0; i < L; i++)
    {
        if (A[i] != B[i])
        {
            if (found)
            {
                if (i - diffEnd == 2 && !mid)
                {
                    mid = true;
                    found = false;
                    diffEnd = -1;
                }
                else
                    return false;
            }
            else if (diffStart == -1)
                diffStart = i;
        }
        else 
        if (diffStart != -1 && diffEnd == -1)
        {
            found = true;
            diffEnd = i - 1;
        }
    }
    if (diffEnd == -1)
    {
        if (A[L - 1] != B[L - 1])
            diffEnd = L - 1;
        else if (!found)
        {
            System.out.println("array is already sorted!");
            return false;
        }
    }

    // find out if it's reversed
    int count = (diffEnd - diffStart + 1) / 2;
    for (int i = 0; i < count; i++)
    {
        int oneEnd = diffStart + i, otherEnd = diffEnd - i;
        if (!(A[oneEnd] == B[otherEnd] && A[otherEnd] == B[oneEnd]))
            return false;
    }
    System.out.println("yes");
    System.out.println("reverse " + (diffStart + 1) + " " + (diffEnd + 1));
    return true;   
}

How would you solve the following Golang challenge?


By : Maria Gelber
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have to solve following TreeHouse Go challenge, but I'm stuck in the Print method.
code :
func Print(d Displayable) {
     d.Display()
}

How can I solve the 3-sum challenge using arrayLists?


By : user2988870
Date : March 29 2020, 07:55 AM
this one helps. I'm currently trying to solve the "three sum" challenge (I'm using java by the way). Here is the challenge description: , After finding a solution, pleas instantly add it to the results list:
code :
class Solution {
    public List<List<Integer>> threeSum(int[] nums) {

        List<List<Integer>> result = new ArrayList<>();


        for (int i = 0; i < nums.length - 2; i++) {
            for (int j = i + 1; j <  nums.length - 1; j++) {
                for (int k = j + 1; k < nums.length; k++) {
                    if (nums[i] + nums[j] + nums[k] == 0) {
                        List<Integer> subList = new ArrayList<>();
                        subList.add(nums[i]);
                        subList.add(nums[j]);
                        subList.add(nums[k]);
                        result.add(subList);
                    }
                }
            }
        }

        return result;
    }
}
public class Solution {
    public List<List<Integer>> threeSum(int[] nums) {

        List<List<Integer>> result = new ArrayList<>();

        for (int i = 0; i < nums.length - 2; i++) {
            for (int j = i + 1; j <  nums.length - 1; j++) {
                for (int k = j + 1; k < nums.length; k++) {
                    if (nums[i] + nums[j] + nums[k] == 0) {
                        List<Integer> subList = new ArrayList<>();
                        subList.add(nums[i]);
                        subList.add(nums[j]);
                        subList.add(nums[k]);

                        Collections.sort(subList);
                        boolean duplicate = false;

                        for (List<Integer> list : result) {
                            if (list.equals(subList)) {
                                duplicate = true;
                                break;
                            }
                        }

                        if (!duplicate) {                            
                            result.add(subList);
                        }   
                    }
                }
            }
        }

        return result;
    }
}

How Do I Solve This Challenge? I don't know how to do it


By : mrfmunger
Date : March 29 2020, 07:55 AM
This might help you , I attached my approach below.
code :
element(air).
element(earth).
element(fire).
element(water).

compound(animal, [life,forest]).
compound(bird,  [animal,air]).
compound(cloud, [water,air]).
compound(fish,  [life,ocean]).
compound(forest, [plant,plant]).
compound(life,  [lightning,ocean,volcano]).
compound(lightning, [storm,cloud,earth]).
compound(ocean,   [water,water,water]).
compound(plant,  [earth,life]).
compound(rain,  [cloud,water]).
compound(storm,  [cloud,wind]).
compound(volcano, [fire,earth]).
compound(wind,  [air,air]).


checkElement([]).
checkElement([H|T]):- element(H) , checkElement(T).

com([],[]).
com([H|T],[H|Q]):- element(H) , com(T,Q).
com([H|T],[Z|Q]):- compound(H,_) , simplify(H,Z) , com(T,Q).

simplify(X,X):- element(X).
simplify(X,Y):- compound(X,Y) , checkElement(Y) .
simplify(X,Z):- compound(X,Y) , \+checkElement(Y) , com(Y,Z).
?-simplify(lightning,X).
  X = [[[water, air], [air, air]], [water, air], earth]

?-simplify(volcano, X).
  X = [fire, earth]
?-simplify(rain, X).
  X = [[water, air], water]
?-simplify(life, X).
  X = [[[[water, air], [air, air]], [water, air], earth], [water, water, water], [fire, earth]]
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