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Compiler-like Java Reflection method resolution

By : dara
Date : July 29 2020, 07:00 PM
it helps some times
I could not find the exact spects about how does the compiler actually perform the task
code :

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C# - Value Type Equals method - why does the compiler use reflection?

By : user1185549
Date : March 29 2020, 07:55 AM
may help you . The following is the decompiled ValueType.Equals method from mscorlib:
code :
public override bool Equals(object obj)
    if (obj == null)
        return false;
    RuntimeType type = (RuntimeType) base.GetType();
    RuntimeType type2 = (RuntimeType) obj.GetType();
    if (type2 != type)
        return false;
    object a = this;
    if (CanCompareBits(this))
        return FastEqualsCheck(a, obj);
    FieldInfo[] fields = type.GetFields(BindingFlags.NonPublic | BindingFlags.Public | BindingFlags.Instance);
    for (int i = 0; i < fields.Length; i++)
        object obj3 = ((RtFieldInfo) fields[i]).InternalGetValue(a, false);
        object obj4 = ((RtFieldInfo) fields[i]).InternalGetValue(obj, false);
        if (obj3 == null)
            if (obj4 != null)
                return false;
        else if (!obj3.Equals(obj4))
            return false;
    return true;

I'm attempting to write a .NET compiler using System.Reflection.Emit how do I do type resolution?

By : user1750447
Date : March 29 2020, 07:55 AM
wish of those help Could you elaborate on the issue that you're running into (perhaps showing code a small example of code that isn't working for you)? Because TypeBuilder derives from Type, if you're trying to define mutually recursive types you can pass the two TypeBuilders wherever you'd like to refer to the types.
code :
private void DefineAutoProp(string name, Type t, TypeBuilder tb)
    var fldName = name.Substring(0, 1).ToLower() + name.Substring(1);
    var fld = tb.DefineField(fldName, t, FieldAttributes.Private);
    var prop = tb.DefineProperty(name, PropertyAttributes.None, t, null);
    var getter = tb.DefineMethod("get_" + name, MethodAttributes.Public, t, null);
    var ilg = getter.GetILGenerator();
    ilg.Emit(OpCodes.Ldfld, fld);
    var setter = tb.DefineMethod("set_" + name, MethodAttributes.Public, typeof(void), new[] { t });
    ilg = setter.GetILGenerator();
    ilg.Emit(OpCodes.Stfld, fld);

public void DefineTypes()
    var ab = AppDomain.CurrentDomain.DefineDynamicAssembly(new AssemblyName("test"), AssemblyBuilderAccess.Run);
    var mb = ab.DefineDynamicModule("test");
    var A = mb.DefineType("A", TypeAttributes.Public | TypeAttributes.Class);
    var B = mb.DefineType("B", TypeAttributes.Public | TypeAttributes.Class);
    DefineAutoProp("AnInstanceOfA", A, B);
    DefineAutoProp("AnInstanceOfB", B, A);

Reflection and dynamic method resolution

By : Bernardo Marongiu Ho
Date : March 29 2020, 07:55 AM
will be helpful for those in need Yes, dynamic always resolves the parameter (in this case new Dog()) to the most specific type possible.

Does using System.Reflection.MethodBase.GetCurrentMethod() in a method prevent the JIT compiler from inlining the method

By : Atuador
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , No, the JIT compiler is free to inline the method.
You'll need to add the [MethodImpl(MethodImplOptions.NoInlining)] to any method that calls GetCurrentMethod() to prevent it from being inlined.

Scala Overloaded Method resolution issue. How to get the compiler to select the right method?

By : Robert Wensley
Date : March 29 2020, 07:55 AM
hop of those help? The compiler says right things to you.
addVertex(f"class:$NPPhrase") matches both addVertex(Any) and addVertex(x$1: Any, x$2: Any*). This happens because the x$2 parameter may be empty and you can omit it when calling the addVertex(x$1: Any, x$2: Any*) (like addVertex("whatever"))
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