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How to SUM with COUNT function wih conditions


By : Toutouf L'xtazi
Date : August 02 2020, 04:00 AM
I wish this helpful for you Here my table: , You can use count(*)
code :
SELECT
COUNT(CASE WHEN marital = 'divorced'   THEN 1 END) AS divorcestat,
COUNT(CASE WHEN marital = 'married' THEN 1 END) AS marriedstat,
COUNT(CASE WHEN marital = 'single' THEN 1 END) AS singlestat,
COUNT(*) AS Total 
FROM status_tbl


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Getting the sum of a count with conditions


By : akhil Youtub
Date : March 29 2020, 07:55 AM
like below fixes the issue So I am trying to get a sum of a count that has conditions (different from the rest of the query) , Try replacing the line:
code :
(select count(*) where attend.attendc IN ('E','G','H','I','J','L','M','P','Q','V','X')) AS [Days Absent],
sum(case when attend.attendc IN ('E','G','H','I','J','L','M','P','Q','V','X') then 1 else 0 end) over () as [Days Absent]
sum(case when attend.attendc IN ('E','G','H','I','J','L','M','P','Q','V','X') then 1 else 0 end)
          over (partition by SSID) as [Days Absent]

How to count OR conditions which are "true" in a If loop and execute different code for different count result


By : brian.alston
Date : March 29 2020, 07:55 AM
will help you I have 5 different OR conditions in a If loop:
code :
int count =     
Convert.ToInt32(cond1)+Convert.ToInt32(cond1)+...+Convert.ToInt32(cond1);

switch(count)
{
    case 1:
    //your code here
    break;
    .
    .
    .
    case 5:
    //your code here
    break;
}

SQL count from same column but different conditions fetching later count result for all


By : Muhammad Omer
Date : March 29 2020, 07:55 AM
seems to work fine The WHERE condition in your query are the problem: you can't have both eqa.QU_ANSWER = 'Yes' and eqa.QU_ANSWER = 'No', so the query return 0 rows, and the count of the values of 0 rows is also 0.
You can change the condition to OR, or you can take the same condition in the COUNT, while doing that you should also change the query to use explicit JOIN instead of writing the join condition in the WHERE clause.
code :
SELECT COUNT(CASE WHEN eqa.QU_ANSWER = 'Yes' THEN 1 ELSE NULL END) as gold_yes
     , COUNT(CASE WHEN eqa.QU_ANSWER = 'No' THEN 1 ELSE NULL END) as gold_no
FROM   EC_SECTION_ANSWER esa
       INNER JOIN EC_QUESTION_ANSWER eqa ON esa.ID = eqa.SC_ID
WHERE  esa.SC_NUMBER = 1079 
  AND  eqa.QU_TYPE = 'abc'; 

Join table on conditions, count on conditions


By : DiegoAxxel
Date : March 29 2020, 07:55 AM
it fixes the issue You seem to be nearly there.
In your question you talked about adding the AND r.approved = 1 to the join criteria but by the sounds of it you are actually adding it to the WHERE clause.
code :
SELECT *, null AS score,
       '0' AS SortOrder
    FROM products
    WHERE datelive = -1
    AND hidden = 0
UNION
SELECT e.*, (SUM(r.a)/(COUNT(*)*1.0)+
       SUM(r.b)/(COUNT(*)*1.0)+
       SUM(r.c)/(COUNT(*)*1.0)+
       SUM(r.d)/(COUNT(*)*1.0))/4 AS score,
       '1' AS SortOrder
    FROM products e
    LEFT JOIN reviews r ON r.productID = e.productID
    WHERE e.hidden = 0
    AND e.datelive != -1
    GROUP BY e.productID
    HAVING COUNT(*) >= 5
UNION
SELECT e.*, (SUM(r.a)/(COUNT(*)*1.0)+
       SUM(r.b)/(COUNT(*)*1.0)+
       SUM(r.c)/(COUNT(*)*1.0)+
       SUM(r.d)/(COUNT(*)*1.0))/4 AS score,
       '2' AS SortOrder
    FROM products e
    LEFT JOIN reviews r ON r.productID = e.productID AND r.approved = 1
    WHERE e.hidden = 0
    AND e.datelive != -1
    GROUP BY e.productID
    HAVING COUNT(*) < 5
    ORDER BY SortOrder ASC, score DESC

Select from database with count and count based conditions?


By : user3003926
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a table with data relating to a user, and two important columns:
code :
SELECT user_id FROM usertable WHERE (referal_date BETWEEN '2014-12-2' AND CURDATE())ORDER BY refer_count DESC;
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