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Two index's of an array have same memory adress


By : Yevish
Date : August 02 2020, 02:00 AM
it should still fix some issue I was working on a project to practice movement through an array and I found a very weird occurrence. While messing around, I discovered that when I moved my player to the edge of the array, it showed up on the edge and a row beneath it and on the complete opposite column. Showcase of problem , Valid indices into
code :
int map[9][9];
for (int col = 0; col <= 9; col++) {
    for (int row = 0; row <= 9; row++) {
        map[col][row] = 0;
    }
} 
int map[10][10];
for (int col = 0; col < 10; col++) {
    for (int row = 0; row < 10; row++) {
        map[col][row] = 0;
    }
} 


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Cannot Access Memory Adress at error when trying to access a shared data array with pthreads


By : user263885
Date : March 29 2020, 07:55 AM
seems to work fine I have a pthread program with two threads. First thread writes to Array[0 - 196607] and second thread writes to Array[196608 - 393215].
code :
*data[i]->array = *array;
struct a { int* array; }
data[i]->array = array;

Using memory adress from pointer to print character array (string) C


By : Loganandh N
Date : March 29 2020, 07:55 AM
will help you If you have two pointers, both pointing to the same array (or to one beyond the end of the array), then you can subtract them from each other.
For example:
code :
char mening[] = "tjena pa dig hog";
char *pointer_to_mening = &mening[10];  // Pointer to the eleventh character

// Should print 10 (which is the index of the eleventh character)
printf("The distance is %zu\n", pointer_to_mening - mening);

How to properly reverse a string by replacing the memory in the adress, not creating new memory in MIPS Assembly


By : user10900
Date : March 29 2020, 07:55 AM
wish helps you
My first thought was to ... this is going to loop until both of the addresses point to the same point...
code :
    la  $a0, STR_str
    la  $a1, reverse_string
    jal reverse_string
beqz    $a0, rs_exit        # Check if string is NULL, exit if it is
li  $t0, 0
li  $t1, 0
add $t0, $t0, $a0       # Save leftmost adress of string
add $t1, $a0, $v0       # Save rightmost adress of string
    beqz    $a0, rs_exit  # Check if string is NULL, exit if it is
    add $t0, $a0, $zero   # t0 = left pointer (start of string)
    add $t1, $a0, $v0     # t1 = start of string plus unknown value in v0
lbu $t2, 0($t0)     # Save leftmost character in temporary register
lbu $t3, 0($t1)     # Save rightmost character in temporary register
sb  $a0, 0($t2)     # Replace rightmost character with leftmost character
sb  $a0, 0($t3)     # Replace leftmost character with rightmost character

Why is memory adress getting printed instead the values of array in c+.+


By : user5834261
Date : March 29 2020, 07:55 AM
like below fixes the issue C++ doesn't provide an overload for arrays when using the iostream library. If you want to print the values of an array, you'll need to write a function or find one somebody else has written.
What's happening under the hood is list is decaying to an int*, and that's what you're seeing printed.

How the pointer and the pointer's adress can share the same memory adress?


By : user5943579
Date : March 29 2020, 07:55 AM
this will help
&ar is the address of the array, its type is "pointer to an array of three integers".
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