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Extracting all words and clusters of letters in a string and then making each word a seperate piece of data using gsub()

By : Smef
Date : August 02 2020, 01:00 AM
hop of those help? Say we have: , You can use strsplit:
code :
result <- unlist(strsplit(stringTest, " |\\d"))
result[result != ""]
#> [1] "Here"     "we"       "have"     "words"    "Here"     "we"      
#> [7] "have"     "avwerfaf"
unlist(lapply(strsplit(stringTest, "\\W|\\d"), function(x) x[x != ""]))

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How to reverse words in a string and letters in those words unless the word is a number

By : JakeElwood
Date : March 29 2020, 07:55 AM
this one helps. Hello & it's nice to be with you all. I was successful in reversing arrays using the built-in functions .split('').reverse().join('') presented in this site, but I need to keep digits in order, not reversed. Is there anything to do or to add to let it exclude the digits from being reversed, or to re-reverse the digits only after reversing the full array? Here's the array flipping function,
code :
"hello 123.45".split(/([^\d\.])/).reverse().join('')

Extracting capital words and extracting the last word in a string

By : George Mills
Date : March 29 2020, 07:55 AM
seems to work fine I have a df that looks like this:
code :
df <- within(df, st_name <- sub(".*?([A-Z]{3,}).*", "\\1", x, perl=TRUE))

df <- within(df, st_type <- sub(".+? ([A-Z]+)$", "\\1", x, perl=TRUE))
#                         x           y    st_name st_type
#1     800 Block of MAIN ST  1.92908789       MAIN      ST
#2 100 Block of CHESTNUT AV  0.02487045   CHESTNUT      AV
#3   BAY ST / WELLINGTON ST -2.33411242        BAY      ST
#4     LARKIN ST / ELLIS ST -1.17946144     LARKIN      ST
#5 MAPLE ST / WELLINGTON ST  0.12913797      MAPLE      ST
df$st_name <- sub(".*?([A-Z]{3,}).*", "\\1", df$x, perl=TRUE)
df$st_type <- sub(".+? ([A-Z]+)$", "\\1", df$x, perl=TRUE)

R : Remove words with 3 or more repeating letters using GSUB

By : bart schoonaert
Date : March 29 2020, 07:55 AM
I hope this helps you . A quick search brought up this SO answer. Using that you can do something like:
code :
## string with repeated letters
s <- "It has been raining verrrry badly heeere last few days"

## split string into vector of words to select
svec <- unlist(strsplit(s, " "))

## find words with 3 or more repeated letters/numbers
## (for any general symbol use '.' instead of '\\w')
rmword <- grep("(\\w)\\1{2, }", svec)

## join words into single string again, removing the unwanted ones
paste(svec[-rmword], collapse = " ")

## output:
[1] "It has been raining badly last few days"
rm.repeatLetters <- function(x){
  xvec <- unlist(strsplit(x, " "))
  rmword <- grepl("(\\w)\\1{2, }", xvec)
  return(paste(xvec[!rmword], collapse = " "))
df <- data.frame(id=c(1, 2, 3), text=c(s, s, s), stringsAsFactors=FALSE)
## > df
##   id                                                   text
## 1  1 It has been raining verrrry badly heeere last few days
## 2  2 It has been raining verrrry badly heeere last few days
## 3  3 It has been raining verrrry badly heeere last few days

df$text <- sapply(df$text, rm.repeatLetters)
## > df
##   id                                    text
## 1  1 It has been raining badly last few days
## 2  2 It has been raining badly last few days
## 3  3 It has been raining badly last few days

How to add letters / words / characters to a special word in a string in javascript?

By : user3436741
Date : March 29 2020, 07:55 AM
Does that help Find substring in Javascript and prepend/append some characters
StackOverflow to the rescue!
code :
function addify( str, ending ){
  return str.replace(/@(\w+)/g, `@$1${ending}`);

console.log( addify( 'i like @cheese', 'burgers' ) );
console.log( addify( 'party @ my place', 'not!' ) );

Extracting first word from a string that has more than three letters

By : Nandini
Date : March 29 2020, 07:55 AM
Hope this helps so I have a string: , Try this easy solution:
code :
string<-"I am a dentist in a health organization."
words<-unlist(strsplit(string," "))
[1] "dentist"
df<-data.frame(string=c("I am a dentist in a health organization.","a dentist in a health organization.","health organization."))

  words<-unlist(strsplit(string," "))



                                    string    word
1 I am a dentist in a health organization. dentist
2      a dentist in a health organization. dentist
3                     health organization.  health
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