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Error: Your a element should be nested within your new p element

By : Ray Meibaum
Date : August 01 2020, 11:00 PM

Is element ‘ul’ cannot be nested within element ‘ol’? (i am getting this error from xhtml validator) help pls

By : user1493836
Date : March 29 2020, 07:55 AM
will help you The
    inside needs to be inside an li, so either make a new li or un-close the first one.

I get an error that says "VC: Element Valid: Content model of element 'recipes' disallows element 'heading' at this

By : umair liaquat
Date : March 29 2020, 07:55 AM
it should still fix some issue The DTD specifies the permitted contents of the root element:
code :
<!ELEMENT recipes (recipe,heading,heading2, heading3) >
<!ELEMENT recipes (heading, heading2, heading3, recipe*) >

python. counting in nested list the max of 3rd element of each element according to the second element

By : user3336738
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Simple way using numpy.amax and list comprehension.
This will find your values:
code :
import numpy as np    
maxB = [x for x in LLList if x[1]=='B' and x[2] == np.amax([x[2] for x in LLList if x[1]=='B'])]
[LLList.index(x) for x in maxB]

Python: Drop duplicate element within nested list, if element is an element within another nested list

By : Muhammad Haris Hanee
Date : March 29 2020, 07:55 AM
I wish this helpful for you If order doesn't matter:
use set operations on each pair of nested lists. Subtracting two sets produces a new set with only the elements from the first that don't appear in the second. Use the zip() function to pair up the nested lists from your two input lists. If your output must consist of nested lists again, convert the result of the set operation back to a list, with list() Use a list comprehension to process each pair of nested lists, creating a new list with the results.
code :
[list(set(b) - set(a)) for a, b in zip(listA, listB)]
[set(b) - set(a) for a, b in zip(listA, listB)]
>>> listA = [['A', 'B', 'C', 'D', 'E'], [1, 2, 3, 4, 5], ['!', '@', '#', '$', '%']]
>>> listB = [['E', 'A', 'T', 'F', 'W'], [5, 6, 8, 2, 9], ['@', '^', '&', '#', '*']]
>>> [list(set(b) - set(a)) for a, b in zip(listA, listB)]
[['W', 'F', 'T'], [8, 9, 6], ['^', '&', '*']]
>>> [set(b) - set(a) for a, b in zip(listA, listB)]  # without list(...)
[{'W', 'F', 'T'}, {8, 9, 6}, {'^', '&', '*'}]
[[v for v in nested_b if v not in set_a] for set_a, nested_b in zip(map(set, listA), listB)]
>>> [[v for v in nested_b if v not in set_a] for set_a, nested_b in zip(map(set, listA), listB)]
[['T', 'F', 'W'], [6, 8, 9], ['^', '&', '*']]

CSS style rule for div element belonging to multiple classes nested within another element's class

By : Juan Pablo Rimoldi
Date : March 29 2020, 07:55 AM
Hope that helps
I am trying to create a style rule to apply the Border Box model to the div elements belonging to the following classes:
code :
div.cell div.container,
div.cell div.row,
div.cell div[class^="column"],
div.cell div[class^="cell"],
div.cell a {

  box-sizing: border-box;

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