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How to call a grandparent method in perl


By : Ayyub
Date : August 01 2020, 06:00 PM
fixed the issue. Will look into that further I was recently needing to call the grandparent of a class. Let's say I have: , You could use the following:
code :
$self->Superhero::SaveWorld(%args);


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call grandparent method without calling parent and without modifying parent/grandparent


By : MJD
Date : March 29 2020, 07:55 AM
may help you . I figured this out before I finished the question, but I decided to post it anyway:
base::getValue() seems to be the correct solution, php seems to do some magic there, so base class has $value property set, when called from its child.

Overriding a grandparent's virtual method that was called in grandparent's constructor


By : user3705664
Date : March 29 2020, 07:55 AM
I hope this helps . What you're trying to do isn't possible. At the time of GrandParent's constructor, the only part of the Child object that has been constructed and initialized is the GrandParent part - including the vtable. That is, when you call printMe(), the entry will be GrandParent's. It's only after Child gets constructed that the vtable entry for printMe() gets updated to point to Child::printMe.
Note that it's good that C++ works like this. If Child::printMe had been the one called, then you'd be calling a member function on a not-yet-constructed object. Nothing good can come of that.

Call Grandparent Method without executing parent method through Mixin


By : viky
Date : March 29 2020, 07:55 AM
seems to work fine One method is to use inspect.getmro() but that is likely to break if the user writes class D(B, Mixin).
Let me demonstrate:
code :
class A(object):
    def class_name(self):
        print "A"


class B(A):
    def class_name(self):
        print "B"
        super(B, self).class_name()
    # other methods ...

class Mixin(object):
    def class_name(self):
        print "Mixin"
        # need to call Grandparent class_name instead of parent's
        # super(Mixin, self).class_name()


class D(Mixin, B):
    # Here I need to override class_name method from B and call B's super i.e. A's class_name, 
    # It is better if I can able to do this thourgh Mixin class. (
    pass

class E(B, Mixin): pass
import inspect
print inspect.getmro(D) # returns tuple with (D, Mixin, B, A, object)
print inspect.getmro(E) # returns tuple with (E, B, A, Mixin, object)

How to call grandparent method in Nodejs


By : user1738292
Date : March 29 2020, 07:55 AM
help you fix your problem You can call the exact function using Function.prototype.call:
code :
class C extends B {
  callA() {
    A.prototype.printFunction.call(this);
  }
}

How to call a grandparent method


By : Rashmi19
Date : March 29 2020, 07:55 AM
I hope this helps you . You can, of course, accomplish this with the help of the parent class. If your foo calls [super foo] and your superclass then in turn calls [super foo] because it expects this behavior, then you're all set. This is a common pattern (e.g. -init and -dealloc).
But you can't jump directly using normal Obj-C syntax. Every subclass defines its own set of semantics for a class around its state and methods. If you could arbitrarily call implementations anywhere up your inheritance chain without the intermediate implementations knowing anything about it, then no implementation would have any guarantees about the integrity of its own state, and it would break the abstractions around classes.
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