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How to handle undefined arrays in Angular for different templates?


By : updz
Date : July 31 2020, 07:00 PM
wish of those help you need to use safe navigation operator ?. in case result is null or undefined elseBlock will be visible
code :
<ng-container *ngIf="results?.length;else elseBlock">
    <div class="result" *ngFor="let result of results">
        <a href="link-goes-here">Open Result</a>
        <search-result  [result]="result"></search-result>
    </div>
</ng-container>

<ng-template #elseBlock>
    No Results dude.
</ng-template>


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How to iterate over an observable stream of arrays in Angular 2 templates?


By : Kristian Østergaard
Date : March 29 2020, 07:55 AM
will help you If phrases$ emits an array, the type seems to be incorrect. Should it not be:
code :
@select('phrase') phrases$: Observable<number[]>;
<div *ngFor="let phrase in phrases$ | async">
  <div>{{phrase}}</div>
<div>

Angular 7 and arrays pushing two arrays into one array is giving an error of undefined


By : EspenS
Date : March 29 2020, 07:55 AM
I wish this help you If I got your problem right... here is the simple way to achieve your requirement.
code :
 let lines = ["1,xx","2,yy","3,zz"];
 let name = [];
 let array = [];
      lines.forEach((line, index) => {
        //console.log(line);
        let obj = { 
        id : line.split(',')[0],
        name : line.split(',')[1]
        };
        
        //ids.push((line.split(',')[0]));
        //name.push(line.split(',')[1]);
        array.push(obj)
      });
      
console.log(array);

May I use templates as a safe solution to handle arrays polymorphically?


By : Rich Byrne
Date : March 29 2020, 07:55 AM
I hope this helps you . It is known that treating items of an array polymorphically is dangerous because, in general, base and derived classes have different sizes, and the pointer arithmetic will most likely fail. , As long as you do it like in your second example and not, e.g., like
code :
doSomethingOnBases<Base>(deriveds, 60);
template <typename X, std::size_t N>
void doSomethingOnArray(X (&arr)[N])
{
    for(auto a = &arr[0]; a != &arr[0] + N; ++a)
        a->doSomething();
}
for (auto& a : arr)
    a->doSomething();
for (Base& b : arr)
    …

How to handle undefined variables and arrays in a good practice way on Laravel


By : Vic Med
Date : March 29 2020, 07:55 AM
Hope that helps Sometimes I get an exception just because the supply for foreach tag doesn't contain an array. , It has been a while and I believe this is the best solution so far.

Handle arrays with undefined size


By : Carlos Tamayo
Date : March 29 2020, 07:55 AM
seems to work fine If you don't know the exact size of the array in advance, you are going to create garbage either way. You'll either overallocate the size of the array or end up having to allocate a new array, copy the values from the old one and dump the old reference. Either way, garbage, and that's how an ArrayList works internally. It's literally just a List wrapper around an array.
FWIW, I think you are way overthinking the issue. An array of objects is just an array of references. None of the items in the array actually do more than hold enough space to reference a memory address until you initialize them.
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