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Firestore - reducing amount of writes and reads by making changes locally, then pushing data to servers


By : Rodney French
Date : July 31 2020, 01:00 AM
will be helpful for those in need It depends on what you mean. One document write is always going to cost one document write, no matter when or how that document was written. Batch writes don't in any way reduce the number of documents written, they just make all the document writes take effect at the exact same moment in time.
If you're staging lots of changes to a single document to take effect later, then feel free to do that. Just write the document whenever you've figured out what final document looks like, and no sooner.
code :


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Making a Program that Reads and Writes Data - Then Computes Min, Max, Average


By : Maher
Date : March 29 2020, 07:55 AM
To fix this issue Here are some pointers:
each exit point of a method returning something must return something, if the line new Scanner(f); throws an exception, the first return is not reached, so you need a default one, like this:
code :
private int[] readData() {
    File f = new File("data.txt");
    int count = 0;
    int[] newData = new int[100];
    try {
        Scanner s = new Scanner(f);
        while (s.hasNext()) {
            newData[count++] = s.nextInt(); // maybe you should handle the case where your input is too large for the array "newData"
        }
        return Arrays.copyOf(newData, count);
    } catch (Exception e) {
        System.out.println("Could not read the file.");
    }

    return null;
}
private int min(int[] data) {
    int min = Integer.MAX_VALUE; // handy constant :)
    for (int i = 0; i < data.length; i++) {
        if (data[i] < min) {
            min = data[i];
        }
    }
    return min;
}

private int max(int[] data) {
    int max = 0;
    for (int i = 0; i < data.length; i++) {
        if (data[i] > max) {
            max = data[i];
        }
    }
    return max;
}
private double average(int[] data) {
    int sum = 0;
    for (int i = 0; i < data.length; i++) {
        sum += data[i]; // here if you want a sum it's += not =
    }
    return (1.0 * sum) / data.length; // you want a double division, local "average" was useless
}
for (int value : newData) {
    // use value
}

Is std::mutex enough for making all prior reads-writes happen before following reads-writes all in same thread?


By : Carlos
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further For a single-threaded application none of this matters, your program will see the reads and writes in the order you perform them, even if they don't actually happen in that order. This stuff only matters when the data is shared across multiple threads and cores.

What is the most cost-efficient method of making document writes/reads from Firestore?


By : user6600
Date : March 29 2020, 07:55 AM
it fixes the issue The cost of a write operation has no bearing on the number of fields you write. It's purely based on the number of times you call update() or set() on a document reference, weither independently, in a transaction, or in a batch.
If you choose to write each N fields using N separate updates, then you will be charged N writes. If you choose to write N fields using 1 update, then you will be charged 1 write.

Making data reads/writes atomic in C11 GCC using <stdatomic.h>?


By : user3568821
Date : March 29 2020, 07:55 AM
will help you For C11 atomics you don't even have to use functions. If your implementation (= compiler) supports atomics you can just add an atomic specifier to a variable declaration and then subsequently all operations on that are atomic:
code :
_Atomic(int) toto = 65;
...
toto += 2;  // is an atomic read-modify-write operation
...
if (toto == 67) // is an atomic read of toto

Reducing the number of reads firestore


By : user3702274
Date : March 29 2020, 07:55 AM
I think the issue was by ths following ,
I have a 10-12 field with one online/offline info field. So let's say if no other field changed but online/offline status changed for some profiles then the listener is going to read that document again.
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