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A recursion problem of python in the first project(hog) of cs61a


By : KraYu
Date : July 29 2020, 10:00 PM
like below fixes the issue At the very least, you need to initialize index so nonlocal index doesn't raise a syntax error, since there is no nonlocal variable by that name.
code :
def make_test_dice(*outcomes):
    index = -1
    def dice():
        nonlocal index
        index = (index + 1) % len(outcomes) 
        return outcomes[index]
    return dice
d = make_test_dice(1, 2, 3)
def f():
    def g():
        def h():
            nonlocal i
            i = 1


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Recursion problem in trees + python


By : Lampside Web Design
Date : March 29 2020, 07:55 AM
help you fix your problem I would like to mention that this is a homework but am not asking for help related to code. , A quick guess, fix to to:
code :
 ...
 else:
      return delete(tree,node.Child,value) # you missed the return here
 ...

Xml parsing with Python using recursion. Problem with return value


By : user3195810
Date : March 29 2020, 07:55 AM
will be helpful for those in need With recursion you want to pay attention to your base cases, and your recursive cases. Whatever your base cases happen to be, if you expect to be able to collect information from your recursion, they have to return data that your recursive cases can (and more importantly do) use. Similarly you need to make sure the data your recursive cases return can be used by each other.
First identify your base and recursive cases. The base cases are the "leaf" nodes, with no children. In a base case you want to just return some data, and not call the recursive function again. This is what allows you to get "back up the stack" as they say, and prevent infinite recursion. The recursive cases will require you to save the data collected from a series of recursive calls, which is almost what you're doing in your for loop.
code :
# Recursive case: node has one or more child
if len( children ) >= 1 :
    # Loop through all the children
    for child in children:
        # call to recursion function
        getCoords( child, searchNode )
# If node has one or more child
if len( children ) >= 1 :
    # Data structure for your results
    coords = []
    # Loop through all the children
    for child in children:
        # call to recursion function
        result = getCoords( child, searchNode )
        # Add your new results together
        coords.extend(result)
    # Give the next instance up the stack your results!
    return coords
# Base case 1: does not have children and is the 'searchNode'
elif len( children ) == 0 and child.tag == searchNode:
    # Return the text from the node, inside a list
    return [child.text]
# Base case 2: doesn't have children and does not match 'searchNode'
else:
    # Return empty list so your extend() function knows what to do with the result
    return []
searchNode = 'coordinates'
# loop through all 'Placemark nodes' in document
for mark in placemark:
    # Get children of 'Placemark' node
    children = mark.getchildren()
    # I imagine that getchildren() might return None, so check it
    # otherwise you'll get an error when trying to iterate on it
    if children:
        # Loop through children nodes
        for child in children:
            # if a 'Polygon' node is found
            if child.tag == 'Polygon':
                # call recursion function and print (or save) result
                print getCoords( child, searchNode)

recursion problem with nested lists in python


By : Ryan Clamp
Date : March 29 2020, 07:55 AM
wish help you to fix your issue you call your function, but don't do anything with its return value when calling it recursively
code :
    else:
        d.extend(flat_list(i))

recursion problem with nested lists using yield in python


By : user3341627
Date : March 29 2020, 07:55 AM
hope this fix your issue You should yield all of the items generated by the flat_list(i) call. You can do this with yield from.
code :
def flat_list(array):
    for i in array:
        if not isinstance(i, list):
            yield i
        else:
            yield from flat_list(i)

for x in flat_list([1, [2, 2, 2], 4]):
    print(x)
1
2
2
2
4

Python nested lists and recursion problem


By : Tim Diskataneous
Date : March 29 2020, 07:55 AM
I hope this helps . First, two general remarks about your code:
Use return True instead of return 1. Use isinstance(form, list) instead of isinstance(form, type([])).
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