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Hiding inherited members


By : irowboat
Date : July 27 2020, 08:00 PM
I wish this helpful for you Override them like Michael Suggests above and to prevent folks from using the overridden (sp?) methods, mark them as obsolete:
code :
[Obsolete("These are not supported in this class.", true)]
public override  void dontcallmeanymore()
{
}


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New static fields and hiding the public inherited members


By : user1734852
Date : March 29 2020, 07:55 AM
Hope this helps When would it be useful? I really don't think it's a good idea to hide members in this way. It's just going to cause a maintenance nightmare - when you see "Height" you can't easily tell which member it's really referring to.
IMO, "new" should only be used as a last act of desperation, usually if a base class has introduced a member which clashes with one of your existing ones. It shouldn't be used as a way of deliberately avoiding normal OO design principles.

Reflection : Getting members from inherited interface, but not from inherited class


By : user2104706
Date : March 29 2020, 07:55 AM
wish of those help You can go about this in a number of ways, depending on your exact aim.
One idea is to get all properties normally then filter out those coming from class A using DeclaringType, e.g.
code :
var typeOfA = typeof(A);
var notFromA = allMembers.Where(
    p => p.DeclaringType != typeOfA && !p.DeclaringType.IsSubclassOf(typeOfA));
var members = typeof(B).GetInterfaces().SelectMany(i => i.GetMembers());

Enforcing type safety of inherited members in inherited classes


By : user3181493
Date : March 29 2020, 07:55 AM
I wish this helpful for you UPDATE: This question was the inspiration for a series of articles on my blog. for the interesting question!
code :
interface ICharacter
{
    public IWeapon Weapon { get; }
}
interface IWeapon {  }
class Sword : IWeapon { }
class Warrior : ICharacter 
{
    IWeapon ICharacter.Weapon { get { return this.Weapon; } }
    public Sword Weapon { get; private set; }
}

Use hiding members in inherited class constructor


By : toni5
Date : March 29 2020, 07:55 AM
hop of those help? I don't know if you need the constant member in the base, but if you want to specify its value from a derived class constructor, as well as that of the mutable member, you can just use a protected c'tor:
code :
class BaseClass {
    private:
    const int constant_variable { 21 };

    protected:
    BaseClass(int init) : constant_variable{init}, mutable_variable{init}
    {}

    public:
    int mutable_variable;
    BaseClass(): mutable_variable(constant_variable) {}
};

class DerivedClass: public BaseClass {
    public:
    DerivedClass() : BaseClass(42) {}
};

Derived class calls an inherited function that uses non-inherited members


By : rajiv
Date : March 29 2020, 07:55 AM
it helps some times base::print cannot see member variables in derived. You have a few options:
Use protected if you actually want base::x and derived::x to be different. Pass px and py to base's constructor: derived(int px = 3, int py = 3) : base(px, py) { } Make base::print a virtual member function and override it in derived.
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