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How do I parse my json into CSV using regex?


How do I parse my json into CSV using regex?

By : Mark
Date : November 20 2020, 03:01 PM
I wish did fix the issue. The easiest thing is to do a regular expression for each value you're trying to extract - that way you're not dependent on ordering:
code :
SELECT REGEXP_SUBSTR(RAW_STRING, '"Type".*:.*"(.*)"', 1, 1, NULL, 1) AS TYPE, 
       REGEXP_SUBSTR(RAW_STRING, '"MessageId".*:.*"(.*)"', 1, 1, NULL, 1) AS MESSAGEID,
       REGEXP_SUBSTR(RAW_STRING, '"TopicArn".*:.*"(.*)"', 1, 1, NULL, 1) AS TOPICARN,
       REGEXP_SUBSTR(RAW_STRING, '"Message".*:.*"(.*)"', 1, 1, NULL, 1) AS MESSAGE,
       REGEXP_SUBSTR(RAW_STRING, '"Timestamp".*:.*"(.*)"', 1, 1, NULL, 1) AS TIMESTAMP,
       REGEXP_SUBSTR(RAW_STRING, '"SignatureVersion".*:.*"(.*)"', 1, 1, NULL, 1) AS SIGNATUREVERSION,
       REGEXP_SUBSTR(RAW_STRING, '"Signature".*:.*"(.*)"', 1, 1, NULL, 1) AS SIGNATURE,
       REGEXP_SUBSTR(RAW_STRING, '"SigningCertURL".*:.*"(.*)"', 1, 1, NULL, 1) AS SIGNINGCERTURL,
       REGEXP_SUBSTR(RAW_STRING, '"UnsubscribeURL".*:.*"(.*)"', 1, 1, NULL, 1) AS UNSUBSCRIBEURL
  FROM RAW_STRING_TABLE;


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How to parse Json using Regex?

How to parse Json using Regex?


By : District Tobacco Con
Date : March 29 2020, 07:55 AM
hope this fix your issue Try this if you want to capture the first (demo):
code :
/module.getid\((.*?)\); *module.getresult(?:.*?)\);$/m
/module.getid\((.*?)\); *module.getresult(.*?)\);$/m
Parse JSON Object in python without the json library (Using only regex)

Parse JSON Object in python without the json library (Using only regex)


By : Lonelyy HU
Date : March 29 2020, 07:55 AM
this will help It's not that complicated really, when you do the get request, you will get a bunch of code, from which you only need little parts, like for example, if you want to parse the news feeds from an user, and get the images and its captions:
code :
query = "https://api.instagram.com/v1/users/"+profile_id+"/media/recent?access_token="+token
response = urlopen(query)
the_page = response.read()
feed = {}
feed['images'] = []
feed['captions'] = []
matchImage = re.findall(r'"standard_resolution":{"url":"(.*?)"', the_page)
matchCaption = re.findall(r'"caption":(.*?),(.*?),', the_page)
if len(matchImage) > 0:
    for x in xrange(0,len(matchImage)):
    image = matchImage[x].replace('\\','')
    if matchCaption[x][0] == 'null':
        feed['images'].append(image)
        feed['captions'].append('No Caption')
    else:
        caption = re.search(r'"text":"(.*?)"', matchCaption[x][1])
        caption = caption.group(1).replace('\\','')
        feed['images'].append(image)
        feed['captions'].append(caption)
javascript parse regex from json

javascript parse regex from json


By : user5612592
Date : March 29 2020, 07:55 AM
wish helps you First you should store it like {"delimiter": "\\S+\\s*"}.
Check the code:
code :
var data = {"delimiter": "\\S+\\s*"};
var delim= new RegExp(data.delimiter, "g");

console.log(delim);
Obtaining single line of a JSON response, using either Json.Parse or Regex in C#

Obtaining single line of a JSON response, using either Json.Parse or Regex in C#


By : Айрат Хафизов
Date : March 29 2020, 07:55 AM
I hope this helps . Newtonsoft is a better choice and I'll walk you through how to use it.
First, create the C# classes you'll need to hold the result of the parsing. In your example, they will look like this:
code :
public class SpeechResponse
{
    public Result[] results { get; set; }
}

public class Result
{
    public Alternative[] alternatives { get; set; }
}

public class Alternative
{
    public string transcript { get; set; }
    public float confidence { get; set; }
}
var response = JsonConvert.DeserializeObject<SpeechResponse>( json );
string phrase = response.results[0].alternatives[0].transcript;
How to parse JSON-like file with regex

How to parse JSON-like file with regex


By : user3011528
Date : March 29 2020, 07:55 AM
Does that help You need to escape the . before appVersion since it is a special character in Regex and you can use \d instead of .* to match only digits. If you want just the number to be captured, without the quotes you can take them out of the parentheses.
code :
const regex = /\.appVersion = "(\d+)";/
const found = data.match(regex)
const appVersion = found[1];
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