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mysql get user rank based on score and lowest time


mysql get user rank based on score and lowest time

By : Roley
Date : November 16 2020, 03:01 PM
I wish this help you DEMO:
One can use user variables to simulate a row_number to give us a rank. to get the duration difference simply subtract the times. end - start we can then sort by score descending and duration ascending.
code :
SELECT A.*, @RN:=@RN+1 as Rank
FROM SO46833505_TBL  A
CROSS JOIN  (Select @RN:=0) Z
ORDER BY  score desc, end_time-Start_Time asc;


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How can I calculate rank based on highest points and lowest time in SQL server

How can I calculate rank based on highest points and lowest time in SQL server


By : Kunal Wadhwa
Date : March 29 2020, 07:55 AM
I hope this helps you . I have searched and searched but have been unable to get this working. I'd really appreciate it if someone could help me out.
code :
with user_ranked_games as (
  select user_id,
         credits,
         time_played,
         row_number() over (  partition by user_id 
                              order by credits desc, time_played asc
                           ) as game_rank
    from games
)
select top 5
       rank() over (order by g.credits desc, g.time_played asc) as rank,
       g.user_id,
       u.alias,
       g.credits,
       g.time_played
  from user_ranked_games g
  join users u
    on g.user_id = u.user_id
 where g.game_rank=1
order by rank
with user_ranked_games as (
  select user_id,
         credits,
         time_played,
         row_number() over (  partition by user_id 
                              order by credits desc, time_played asc
                           ) as game_rank
    from games
),
ranked_users as (
  select rank() over (order by g.credits desc, g.time_played asc) as rank,
         g.user_id,
         u.alias,
         g.credits,
         g.time_played
    from user_ranked_games g
    join users u
      on g.user_id = u.user_id
   where g.game_rank=1
)
select * from ranked_users where user_id=93
create view ranked_users as
with user_ranked_games as (
  select user_id,
         credits,
         time_played,
         row_number() over (  partition by user_id
                              order by credits desc, time_played asc
                           ) as game_rank
    from games
),
select rank() over (order by g.credits desc, g.time_played asc) as rank,
       g.user_id,
       u.alias,
       g.credits,
       g.time_played
  from user_ranked_games g
  join users u
    on g.user_id = u.user_id
 where g.game_rank=1
select top 5 * from ranked_users order by rank
select * from ranked_users where user_id=93
Get Rank User with PHP/MySQL Without Inserting Current User's Score into the table

Get Rank User with PHP/MySQL Without Inserting Current User's Score into the table


By : user7679383
Date : March 29 2020, 07:55 AM
this will help I have a web-based game I'm creating in PHP with a MySQLi database. I'm looking to get the 'rank' of a user but it's a little different than other answers I've seen on here. , You could incorporate the new score into a query something like
code :
SELECT id, username, score, time FROM scores
UNION ALL
SELECT 0 as id, 'YOURSCORE' as username, 99999 as score, 45 as time
ORDER BY score desc, time desc
Find the rank of a user's lowest lap time

Find the rank of a user's lowest lap time


By : MadaraCZech
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have a number of race car drivers, that race at different tracks. I want to get their best lap time at each particular track, and rank it against other users best lap times at that particular track. I want to do this for all users at all tracks. So I want to return a large leaderboard.
code :
SELECT track_id, user_id, duration, 
  CASE WHEN track_id!=@track THEN @rank:=0 END as reset,
  @rank := @rank + 1 AS rank,
  @track:=track_id
FROM
(
  SELECT DISTINCT s1.track_id, s1.user_id, s1.duration
  FROM session_lap_times s1
  LEFT JOIN session_lap_times s2
    ON s1.user_id=s2.user_id
   AND s1.track_id = s2.track_id
   AND s1.duration > s2.duration
  WHERE s2.duration IS NULL
    AND s1.track_id IN (SELECT id FROM tracks WHERE verified=1)
  ORDER BY s1.duration ASC
) zz, (SELECT @rank := 0, @track := null) z;
Calculate rank of the users based on their max score using mysql

Calculate rank of the users based on their max score using mysql


By : Boopy McFlob
Date : March 29 2020, 07:55 AM
Hope that helps You are looking for DENSE_RANK, But it supports mysql version higher than 8.0
use correlated-subquery to get max value by each User_id use two variables one to store rank another to store previous value to make the DENSE_RANK number.
code :
CREATE TABLE T(
   User_id int,
   Score int
); 

insert into t values (1,12258); 
insert into t values (1,112);
insert into t values (2,9678);
insert into t values (5,9678);
insert into t values (3,689206);
insert into t values (3,1868);
SELECT User_id,Score,Rank
FROM (
  SELECT User_id,
         Score,
         @rank :=IF(@previous = t1.score, @rank, @rank + 1) Rank,
         @previous := t1.Score
  FROM T t1 CROSS JOIN (SELECT @Rank := 0,@previous := 0) r
  WHERE t1.Score = 
  (
    SELECT  MAX(Score)  
    FROM T tt
    WHERE t1.User_id = tt.User_id
  ) 
  ORDER BY Score desc
) t1
| User_id |  Score | Rank |
|---------|--------|------|
|       3 | 689206 |    1 |
|       1 |  12258 |    2 |
|       2 |   9678 |    3 |
|       5 |   9678 |    3 |
How can I calculate rank based on highest Score and lowest Minutes in MySql Server

How can I calculate rank based on highest Score and lowest Minutes in MySql Server


By : Al ex
Date : March 29 2020, 07:55 AM
seems to work fine My Table Structure is , The easiest way is to use variables:
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