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While ends even if the condition is unfilled Java Multithreading


While ends even if the condition is unfilled Java Multithreading

By : john_ itle_
Date : November 18 2020, 03:01 PM
Hope that helps Your condition means that the loop should continue while both right and left are false, and it stops once any of them is true. You should try with while((left != true) || (right != true)), meaning the loop will stop only once both are true.
code :


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Java Regex Starts With and Ends With Condition Replacer

Java Regex Starts With and Ends With Condition Replacer


By : D. Dominguez
Date : March 29 2020, 07:55 AM
it fixes the issue I have lines at my text as like: , You can give the following a try:
code :
String s = "=== Kendo ===";
String repl = "$1" + System.getProperty("line.separator") + "_";
String newString = s.replaceAll("(?m)^(=.*=)$", repl); // $1\n_
=== foo ===
one
two
=== bar ===
three
four
=== foo ===
_
one
two
=== bar ===
_
three
four
public static void main(String[] args) {
    String s = "=== Etiam ===\neu\nmagna\nsit\namet\norci\nrutrum\nfeugiat\n\n=== Nunc ===\nurna\nlorem,\negestas\net\nvarius\nfermentum,\nconsectetur\nsed\nmauris\n";

    long start = System.currentTimeMillis();
    for (int i = 0; i < 100000; i++)
        replaceAllNoRegex(s);

    System.out.println("Tokens: " + (System.currentTimeMillis()-start));

    start = System.currentTimeMillis();
    for (int i = 0; i < 100000; i++)
        replaceAllIndex(s);

    System.out.println("Index: " + (System.currentTimeMillis()-start));

    start = System.currentTimeMillis();
    for (int i = 0; i < 100000; i++)
        s.replaceAll("(?m)^(=.*?=)$", "$1\n_");

    System.out.println("Regex: " + (System.currentTimeMillis()-start));
}

public static String replaceAllNoRegex(String s) {
    StringTokenizer st = new StringTokenizer(s,"\n");
    StringBuilder sb = new StringBuilder();
    String next;
    while (st.hasMoreElements()) {
        next = (String) st.nextElement();
        sb.append(next);
        if (next.startsWith("=") && next.endsWith("=")) {
            sb.append("\n_");
        }
        sb.append("\n");
    }
    return sb.toString();
}

public static String replaceAllIndex(String s) {
    int index = 0, indexEnd, indexStart = 0;
    StringBuilder sb = new StringBuilder();

    while (index == 0 || (index = s.indexOf("\n=", index)) != -1) {
        indexEnd = s.indexOf("\n",index+2);
        if (indexEnd != -1 && s.charAt(indexEnd-1) == '=') {
            sb.append(s.substring(indexStart,indexEnd));
            sb.append("\n_\n");
            indexStart = indexEnd + 1;
        }
        index = indexEnd+1;
    }
    sb.append(s.substring(indexStart));
    return sb.toString();
}
Java multithreading Race condition scenario

Java multithreading Race condition scenario


By : frival
Date : March 29 2020, 07:55 AM
With these it helps Your program as it is has a very low chance of suffering from race condition, because all threads add to field a, so the order does affect the final result. Only if two threads read the same value of a, then first assigns a new value and then the second assigns a new value, you could "lose" an increment.
Here is a modified version that more frequently suffers from race condition:
code :
public class Step4 {

  public int getA() {
    return a;
  }

  public void addToA(int number) {
    try {
        Thread.sleep(100);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

    for(int i=0;i<number;i++)
        this.a = this.a + 1;
  }

  public void multiplyA(int number) {
    try {
        Thread.sleep(100);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

    this.a = this.a * number;
  }

  int a = 2;
  static Step4 s4;

  public static void main(String[] args) throws InterruptedException {

    for (int i = 0; i < 10; i++) {
        s4 = new Step4();
        doRun();
        System.out.println("*******");
    }
  }

  private static void doRun() throws InterruptedException {
    Thread thread1 = new Thread(new Runnable() {
        @Override
        public void run() {
            s4.addToA(5);
        }
    });

    Thread thread2 = new Thread(new Runnable() {
        @Override
        public void run() {
            s4.multiplyA(3);
        }
    });

    Thread thread3 = new Thread(new Runnable() {
        @Override
        public void run() {
            s4.addToA(6);
        }
    });

    Thread thread4 = new Thread(new Runnable() {
        @Override
        public void run() {
            s4.addToA(4);
        }
    });


    thread1.start();
    thread2.start();
    thread3.start();
    thread4.start();

    thread1.join();
    thread2.join();
    thread3.join();
    thread4.join();

    System.out.println(s4.getA());

  }

}
Cumulative sum based on a condition but reset after condition ends

Cumulative sum based on a condition but reset after condition ends


By : user3229046
Date : March 29 2020, 07:55 AM
wish help you to fix your issue We can use data.table rleid to create groups and return cumsum or NA based on flag
code :
library(dplyr)

demo %>%
  group_by(group = data.table::rleid(flag)) %>%
  mutate(new_mag = if(first(flag)) cumsum(data) else NA) %>%
  ungroup %>%
  select(-group)

#     data flag  continuousfailure magnitude new_mag
#    <dbl> <lgl>             <dbl>     <dbl>   <dbl>
# 1 -1121. FALSE                 0       NA      NA 
# 2  -460. FALSE                 0       NA      NA 
# 3  3117. FALSE                 0       NA      NA 
# 4   141. FALSE                 0       NA      NA 
# 5   259. FALSE                 0       NA      NA 
# 6  3430. TRUE                  1     3430.   3430.
# 7   922. TRUE                  2     4352.   4352.
# 8 -2530. TRUE                  3     1822.   1822.
# 9 -1374. TRUE                  4      448.    448.
#10  -891. TRUE                  5     -443.   -443.
# … with 90 more rows
group_by(group = cumsum(flag != lag(flag, default = first(flag)))) %>%
group_by(group = with(rle(flag), rep(seq_along(lengths), lengths)))
set.seed(123)
demo <- data.frame(data = rnorm(100, mean = 0, sd = 2000), 
flag = c(rep(FALSE, 5), rep(TRUE, 10), rep(FALSE, 25), rep(TRUE, 23),rep(FALSE, 13),
rep(TRUE, 5), rep(FALSE, 19)),continuousfailure = c(rep(0, 5), 1:10, rep(0, 25), 
1:23, rep(0, 13), 1:5, rep(0, 19)),magnitude = NA)
Java multithreading - awaiting condition and releasing all threads

Java multithreading - awaiting condition and releasing all threads


By : Prakash Thangella
Date : March 29 2020, 07:55 AM
I hope this helps you . I recommend Phaser
Java Thread : Multithreading - Race condition

Java Thread : Multithreading - Race condition


By : SCX
Date : March 29 2020, 07:55 AM
This might help you You're passing two different instance of DataProcessor to the threads in class UserA and UserB, if you start these main methods it will run normally. the race-condition won't occur in your application.
For race-condition to occur you have to pass the shared object, i.e. multiple threads to operate on a same object and the shared objects should have field/attribute to get shared between multiple threads
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