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Trying to query my DB and pass results into an object then to the front, mysql and java


Trying to query my DB and pass results into an object then to the front, mysql and java

By : sandip dey
Date : November 18 2020, 03:01 PM
will be helpful for those in need So currently I am attempted to query my DB and pull out all of the results, make them an object, then push the object to an array of objects, I am having trouble making this work correctly.
code :
public class Table {

public List<Car> getTableConnection() throws ClassNotFoundException, SQLException {
    Work work = new Work();
    ResultSet result = null;
    Statement sp = null;
    Connection conn = null;
    ResultSet rs = null;
    List<Car> cars = new ArrayList<>();

    try {
        **conn =work.createConnection();**
        sp = conn.createStatement();
        conn.setAutoCommit(false);
        result = sp.executeQuery("SELECT * FROM cardetails");
        while (result.next()) {
            Car car = new Car();
            car.setId(result.getInt("id"));
            car.setYear(result.getString("Year"));
            car.setMake(result.getString("Make"));
            car.setModel(result.getString("Model"));
            car.setColor(result.getString("Color"));
            car.setAvailable(result.getString("Availability"));
            cars.add(car);
        }
    } catch (Exception e) {

    } finally {

    }
    return cars;
}


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Bringing specific results to the front using one MySQL query

Bringing specific results to the front using one MySQL query


By : gholamreza Najafi
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Use a CASE expression in your ORDER BY clause, and assign specific values to the countries you want to appear first.
e.g.
code :
SELECT * FROM global_flags
  ORDER BY (CASE WHEN country="United States" THEN 0 WHEN country="United Kingdom" THEN 1 ELSE 2 END), country;
How to pass mysql query and connection string and getting results?

How to pass mysql query and connection string and getting results?


By : user3506389
Date : March 29 2020, 07:55 AM
This might help you I have a SQL connection string like this:
code :
public DataTable GetVisits(System.DateTime startDate, System.DateTime endData)
{
    const string SQL = "SELECT CONCAT(UPPER(SUBSTRING(visit_Status, 1, 1)), SUBSTRING(visit_Status FROM 2))  as Status, COUNT('x') AS Visits FROM(visits)  WHERE visit_Date BETWEEN @startDate AND @endData GROUP BY visit_Status";
    const string CONNSTR = "Data Source=myServerAddress;Initial Catalog=myDataBase;User Id=myUsername;Password=myPassword;";
    var tblVisits = new DataTable("Visits");
    using (var conn = new MySql.Data.MySqlClient.MySqlConnection(CONNSTR)) {
        var cmd = new MySql.Data.MySqlClient.MySqlCommand(SQL, conn);
        var da = new MySql.Data.MySqlClient.MySqlDataAdapter(cmd);
        var param = new MySql.Data.MySqlClient.MySqlParameter("@startDate", MySql.Data.MySqlClient.MySqlDbType.Date);
        param.Direction = ParameterDirection.Input;
        param.Value = startDate;
        cmd.Parameters.Add(param);
        param = new MySql.Data.MySqlClient.MySqlParameter("@endDate", MySql.Data.MySqlClient.MySqlDbType.Date);
        param.Direction = ParameterDirection.Input;
        param.Value = endData;
        cmd.Parameters.Add(param);
        conn.Open();
        da.Fill(tblVisits);
    }

    return tblVisits;
}
Pass test score results to mysql query

Pass test score results to mysql query


By : David Borka
Date : March 29 2020, 07:55 AM
Hope that helps You're coming at this from the wrong angle.
It's easy for someone to fake passing your quiz if they are technically minded. All they need to do is fire up the browser's developer tools and edit the data on the page. You're better off using something that doesn't rely on trusting data from the client. Of course, this might just a be a frivolous quiz where it doesn't really matter if the user passed or not. JavaScript runs on the client while PHP runs on the server. They cannot share variables in this way. You will need to send the score to the server in some way. This question might be a good place to start.
Prohibit PHP Function To Echo Results In Front-End, When Using For MySQL Query

Prohibit PHP Function To Echo Results In Front-End, When Using For MySQL Query


By : Yogita Mahajan
Date : March 29 2020, 07:55 AM
Hope this helps You must keep sub decrypted part in function and return whole decrypted string . This example work for more than 14 symbol. And dividing string into array str_split better solution
code :
function decrypt_code($str){
    $someArray = str_split($str); // size is not bounded

    $decrypt_code;
    foreach($someArray as $value1){ 
        if($value1 == "A"){$decrypt_code .= "1";}
        elseif($value1 == "B"){$decrypt_code .= "2";}
        elseif($value1 == "C"){$decrypt_code .= "3";}
        elseif($value1 == "D"){$decrypt_code .= "4";}
        elseif($value1 == "E"){$decrypt_code .= "5";}
        elseif($value1 == "F"){$decrypt_code .= "6";}
        elseif($value1 == "G"){$decrypt_code .= "7";}
        elseif($value1 == "H"){$decrypt_code .= "8";}
        elseif($value1 == "I"){$decrypt_code .= "9";}
        elseif($value1 == "J"){$decrypt_code .= "0";}
    }

    return $decrypt_code;
}
How to pass mysql query in function and get the results

How to pass mysql query in function and get the results


By : user1621106
Date : March 29 2020, 07:55 AM
I hope this helps . As far as I see in module mysql you have the feature called preparing queries.
So basically you should pass query and parameters for executing, f.e. your function definition will look like this function(query, parameters, callback), and than use mysql.format(query, parameters) before executing the query.
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