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Can I have an array of nested numba objects?


Can I have an array of nested numba objects?

By : Olivier Giroud
Date : November 18 2020, 03:01 PM
wish help you to fix your issue There are a few limitations to what you are trying to do:
Numba can't turn a string into a native type, so as far as I'm aware, you can't have instance variables of type string Numba does not support arrays or lists of objects as arguments to numba-jitted functions or jitclasses.
code :


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JavaScript filter through array of objects with a nested array and check for variable match within nested array

JavaScript filter through array of objects with a nested array and check for variable match within nested array


By : dreamoo
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further If you want to filter your main array such that it only contains objects that have fiberPhase anywhere in their fiber_phases array, you'd use filter with includes in the predicate:
code :
return this.blocks.filter(block => block.fiber_phases.includes(fiberPhase));
return this.blocks.filter(block => block.fiber_phases.indexOf(fiberPhase) !== -1);
.map(entry => Object.assign({}, entry))
.map(entry => ({...entry}))
How to push data from a nested array, inside an array of objects, to a new array? while maintaining its nested structure

How to push data from a nested array, inside an array of objects, to a new array? while maintaining its nested structure


By : user845492
Date : March 29 2020, 07:55 AM
I hope this helps you . I have an array that contains multiple objects. These objects also contain arrays of objects like this: , Just .map the interests of each item:
code :
const data=[{id:1,name:"Jack",interests:[{id:9,name:"basketball"},{id:8,name:"art"}]},{id:2,name:"Jenny",interests:[{id:7,name:"reading"},{id:6,name:"running"}]}]
const mapped = data.map(({ interests }) => interests);
console.log(mapped);
const data=[{id:1,name:"Jack",interests:[{id:9,name:"basketball",foo:'bar'},{id:8,name:"art",foo:'bar'}]},{id:2,name:"Jenny",interests:[{id:7,name:"reading",foo:'bar'},{id:6,name:"running",foo:'bar'}]}]
const mapped = data.map(({ interests }) =>
  // Use only `id` and `foo` properties, discard the `name`s:
  interests.map(({ id, foo }) => ({ id, foo }))
);
console.log(mapped);
How to generate a nested array of objects from an array of objects in nested set model?

How to generate a nested array of objects from an array of objects in nested set model?


By : himanshu paliwal
Date : March 29 2020, 07:55 AM
will be helpful for those in need I wrote this recursive solution. Hope it can help. If you have any doubt please ask me. I just check if an element is inside right and left property of another one. In this case I add it into his fathers (and each anchestor). I repeat the same operation until there are no more "fathers".
code :
const categories = [
  {
      id: 1,
      name: "Products",
      lft: 1,
      rgt: 22
  },
  {
      id: 2,
      name: "Boats",
      lft: 2,
      rgt: 15
  },
  {
      id: 3,
      name: "Rescue Boats",
      lft: 3,
      rgt: 4
  },
  {
      id: 4,
      name: "Dive Boats",
      lft: 5,
      rgt: 6
  },
  {
      id: 5,
      name: "Tamarans",
      lft: 7,
      rgt: 8
  },
  {
      id: 6,
      name: "Dragon Boats",
      lft: 9,
      rgt: 10
  },
  {
      id: 7,
      name: "Kayaks",
      lft: 11,
      rgt: 12
  },
  {
      id: 8,
      name: "Speedboats",
      lft: 13,
      rgt: 14
  },
  {
      id: 9,
      name: "Other Products",
      lft: 16,
      rgt: 21
  },
  {
      id: 10,
      name: "Slides",
      lft: 17,
      rgt: 18
  },
  {
      id: 11,
      name: "Buoys",
      lft: 19,
      rgt: 20
  }
]

function create_tree(array){
  if(array.every(x => array.every(y => !(y.lft > x.lft && y.rgt < x.rgt))))
    return array.map(x => {return{id:x.id, name:x.name, subcategories: x.subcategories}});
  else
  return create_tree(array.map(x => {return {
    id: x.id,
    name: x.name,
    lft: x.lft,
    rgt: x.rgt,
    subcategories: array.filter(y => y.lft > x.lft && y.rgt < x.rgt).map(t => {return (t.subcategories) ? {id: t.id, name: t.name, subcategories: t.subcategories} : {id: t.id, name: t.name}})
  }}).filter(t => t.subcategories && t.subcategories.length > 0));
}

console.log(create_tree(categories));
how to query nested array of objects by also filtering nested array of nested array in mongo

how to query nested array of objects by also filtering nested array of nested array in mongo


By : user3014201
Date : March 29 2020, 07:55 AM
This might help you To achieve this you need to add a few stages: first, $unwind the subComponent array, and define subComponenet as the new root of the document with $replaceRoot. Then, use a second $project stage to filter the parts array:
code :
db.collection.aggregate([
  { "$match": { "_id": "1_1" }},
  { "$project": {
    "subComponents": {
      "$filter": {
        "input": "$subComponents",
        "as": "subComponent",
        "cond": { "$eq": ["$$subComponent._id", "subId_1"] }
      }
    }
  }},
  { "$unwind": "$subComponents" },
  { "$replaceRoot": { "newRoot": "$subComponents" }},
  { "$project": {
    "name": 1,
    "type": 1,
    "parts": {
      "$filter": {
        "input": "$parts",
        "as": "part",
        "cond": { "$in": ["$$part._id", ["partId_1", "partId_2"]] }
      }
    }
  }}
])
[
  {
    "_id": "subId_1",
    "name": "subComponentName_subId_1",
    "type": "SUB_COMPONENT_TYPE_1",
    "parts": [
      {
        "_id": "partId_1",
        "description": "part description partId_1",
        "status": true,
        "type": "type_partId_1"
      },
      {
        "_id": "partId_2",
        "description": "part description partId_2",
        "status": true,
        "type": "type_partId_2"
      }
    ]
  }
]
Struggling with nested Numpy array when implementing Numba

Struggling with nested Numpy array when implementing Numba


By : user3606645
Date : March 29 2020, 07:55 AM
To fix this issue to @hpaulj for the awnser, I was struggling my way through a simple problem.
My solution is to put every loop result list into a list, after closing the loops the list is then transformed to an array. Where it first took way to long it now takes up less then 2 min (which does make me somewhat suspicious;)).
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