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React conditional style not rendering properly


React conditional style not rendering properly

By : Joseph U
Date : November 19 2020, 03:01 PM
Does that help I solved this by checking nextProps compared to currentProps and if there was a change in them I then set the state causing a re render.
The reason why the right table (sell orders) didn't update is because there was buy data and sell data coming down the socket. The sell orders going first almost every time (that's why it would work periodically).
code :
componentWillReceiveProps(props) {
  if (this.props.data !== props.data) {
    this.setState({previousTable: this.props.data});
  }
}


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Conditional Routing and Conditional Rendering in ReactJS and React router

Conditional Routing and Conditional Rendering in ReactJS and React router


By : CaseyNeistat
Date : March 29 2020, 07:55 AM
To fix the issue you can do Another way would be to consider that Profilecontainer as a protected URL and use the same dynamic as the authentication flow.
code :
import React from 'react';
import { Redirect } from 'react-router-dom';

const ProtectedProfile = ({ component: Component, ...rest }) => (
  <Route {...rest} render={ props => (
     props.user === props.match.params.user ? (
      <Component {...props} /> ) : (
       <Redirect to={{ pathname: '/404' }} /> )
      )} />
 );
 <ProtectedProfile path="/profile/:user" component={Profile} />
Conditional rendering of CSS style in elements React

Conditional rendering of CSS style in elements React


By : Ousmane Kone
Date : March 29 2020, 07:55 AM
Does that help I'm trying to make a signal bar which depending on the number of strength (1-3) will display the corresponding number of bars in black (activated) otherwise in grey colour. So in React i have used the following: , With inline styles, you can do some computed styles like this :
code :
const colorScheme = {
    first: ['grey', 'black', 'black', 'black'],
    second: ['grey', 'grey', 'black', 'black'],
    third: ['grey', 'grey', 'grey', 'black'],
}
class Application extends React.Component {
  render() {
    const colorNb = ((this.props.signal-strength < 4) && (this.props.signal-strength > 0)) ? this.props.signal-strength : 0;

    return (
       <div className={{sizing-box}}>
          <div className={{signal-bars, bar}}>
             <div className={{'first-bar, signal-bars, bar'}}  style={{display: 'block', color: colorScheme.first[colorNb] }} />
             <div className={{'second-bar, signal-bars, bar'}}  style={{display: 'block', color: colorScheme.second[colorNb] }} />
             <div className={{'third-bar, signal-bars, bar'}} style={{display: 'block', color: colorScheme.third[colorNb] }} /> 
         </div>
     </div>
    );
  }
}
.signal-bars {
  display: inline-block;
}

.signal-bars div {
  width: 14%;
  margin-left: 1%;
  min-height: 20%;
  display: block;
}
.signal-bars div:nth-child(1)  { height: 30%; }
.signal-bars div:nth-child(2) { height: 60%; }
.signal-bars div:nth-child(3)  { height: 90%; }
return (
   <div className="sizing-box">
       <div className="signal-bars">
           <div style={{ color: colorScheme.first[colorNb] }} />
           <div style={{ color: colorScheme.second[colorNb] }} />
           <div style={{ color: colorScheme.third[colorNb] }} /> 
       </div>
   </div>
);
React rendering invisible components when using enum for conditional rendering

React rendering invisible components when using enum for conditional rendering


By : Kenan İLGÜN
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The difference between 2 solutions is the execution order. In the first case, a new object with 2 keys a & b is created, along with corresponding components AComponent and BComponent, then taken out value of key matching displayMode. In the second case, displayMode is verified first, and based on its value, the second condition will or will not be taken. It is similar to executing: !!undefined && undefined.raiseNoError - the second condition is ignored since it doesn't pass the first condition.
Conditional rendering style

Conditional rendering style


By : user1863162
Date : March 29 2020, 07:55 AM
this one helps. you can use conditionnal test in render to add code and style
with your example :
code :
<View style={[styles.container, !isOpen && styles.buttonPadding]}>
  {isOpen ? <TimerForm /> : <TimerButton title="+" color="black" />}
</View>
<View style={[styles.container, styles.buttonPadding]}>
    <TimerForm />
</View>
<View style={[styles.container]}>
    <TimerButton title="+" color="black" />
</View>
    <View style={styles.container}>
        {isOpen && <TimerForm />}
    </View>
    <View style={styles.container}>
        {isOpen ? <TimerForm /> : null}
    </View>
React - conditional rendering of Javascript and JSX, conditional wrapper component

React - conditional rendering of Javascript and JSX, conditional wrapper component


By : Oren Nathan
Date : September 26 2020, 06:00 AM
To fix this issue The children provided to Conditional is a function. To render children as a function(render props) you should execute it like this
code :
shouldRender() ? props.children() : null
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