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mongodb filter and project only matched subdocuments


mongodb filter and project only matched subdocuments

By : Claude Frankfroute
Date : November 19 2020, 03:01 PM
help you fix your problem Lets say we have following documents:
code :
db.stackOverflow.aggregate([ 
  {$unwind:"$reports”},
  {$unwind:"$reports.data"},
  {$match:{"reports.data.DATA_ID":{$in:[/^abcd/,/^01234/]}}},
  {$group:{_id:null, data:{$push:{"DATA_ID":"$reports.data.DATA_ID"}}}}
])


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Mongodb. Method to limit subdocuments that only have the given fields of the `projection` (that is, filter)?

Mongodb. Method to limit subdocuments that only have the given fields of the `projection` (that is, filter)?


By : Sienny
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I believe that empty fields are returned in this case because document is an array and Mongodb does not want to change the array index of any elements.
You can get an array of subdocuments with the aggregation framework:
code :
db.monday.aggregate(
  [
    { $match: 
      {'document.subdocument' : 
        { $exists: 1 }
      }
    },
    { $unwind: "$document" }, 
    { $match: 
      {'document.subdocument' : 
        { $exists: 1 }
      }
    },
    { $project: { subdocument: "$document.subdocument", _id: 0 } }
  ])
 [
    {
        "subdocument" : "Hello World"
    },
    {
        "subdocument" : "Hello Moon"
    }
 ]
MongoDB Filter for both matched and un-matched conditions

MongoDB Filter for both matched and un-matched conditions


By : Murad Ramazanli
Date : March 29 2020, 07:55 AM
Any of those help
Not sure why you think you need to use the aggregation filter for this when a simple query will suffice:
code :
db.tickets.find({
    "$and": [
        { "assignments.asignee": "Team" },
        { "assignments.asignee": {"$nin": teamMemberFilter } }
    ]
})
db.tickets.aggregate([
  { "$project": {
    "matched": {
      "$let": {
        "vars": {
          "names": { "$map": {
            "input": "$assignments",
            "as": "a",
            "in": "$$a.asignee"
          }}
        },
        "in": {
          "$and": [
            { "$eq": [ 
              { "$size": { "$setIntersection": [ "$$names", ["Team"] ] } },
              1
            ]},
            { "$eq": [ 
              { "$size": { "$setIntersection": [ "$$names", teamMemberFilter ] } },
              0
            ]},
          ]
        }
      }
    }
  }}
])
In a mongodb database, how do I find() and filter out any subdocuments?

In a mongodb database, how do I find() and filter out any subdocuments?


By : Nivitt Malik
Date : March 29 2020, 07:55 AM
this one helps. If you want to dynamically remove any nested objects without specifying any existing keys, you can achieve that using aggregation framework:
code :
db.col.aggregate([
    {
        $project: {
            keysAndValues: {
                $objectToArray: "$$ROOT"
            }
        }
    },
    {
        $addFields: {
            keysAndValues: {
              $filter: {
                 input: "$keysAndValues",
                 as: "kvPair",
                 cond: { $ne: [ { $type: "$$kvPair.v" }, "object" ] }
              }
            }
        }
    },
    {
        $replaceRoot: {
            newRoot: { $arrayToObject: "$keysAndValues" }
        }
    }
])
MongoDb / C# filter and get all subdocuments

MongoDb / C# filter and get all subdocuments


By : Bruno Gross
Date : March 29 2020, 07:55 AM
like below fixes the issue I'm having difficulties querying a Mongo-DB collection. , This should get you going:
code :
var result = collection
    .Aggregate()
    .Match(c => c.CustomerId == 2)
    .Project(c => new
        {
            c.CustomerId,
            Addresses = c.Addresses.Where(a => a.Name.IndexOf(searchTerm) != -1)
        })
    .ToList();
db.Customer.aggregate([{
    $match: { CustomerId: 2 }
}, {
    $project: {
        CustomerId: "$CustomerId",
        Addresses: {
            $filter: {
                input: "$Addresses",
                as: "a",
                cond: {
                    $ne: [ { $indexOfBytes: [ "$$a.Name", "Dan" ] }, -1 ]
                }
            }
        },
        _id: 0
    }
}])
var result = collection
    .Aggregate()
    .Match(c => c.CustomerId == 2)
    .Project(c => new
        {
            c.CustomerId,
            Addresses = c.Addresses.Where(a => a.Name.ToUpper().IndexOf(searchTerm.ToUpper()) != -1)
        })
    .ToList();
MongoDB Using Mongoose Filter Based on SubDocuments

MongoDB Using Mongoose Filter Based on SubDocuments


By : faerunvale
Date : March 29 2020, 07:55 AM
I hope this helps . You can't explicitly refer to length property of an array. To check if array is not empty you can check if it's of $type "array" and if its $size is $not 0.
code :
Dish.find({ reviews: { $type: "array", $not: { $size: 0 } } },
    function(error,dishes){
      console.log(dishes)
})
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