Pymongo sort comments in descending order

Pymongo sort comments in descending order

By : Stefan
Date : November 19 2020, 03:01 PM
this will help There are a couple of things worth mentioning with regard to the schema design you posted:
If one post have a lot of long comments, it can plausibly be over 16 MB in size, which is the size limit of a MongoDB document. Putting comments in an array makes it hard to sort, as you have discovered.
code :

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How can I sort comments in descending order?

How can I sort comments in descending order?

By : EKriss
Date : March 29 2020, 07:55 AM
I hope this helps . I have a problem with WordPress comment template. , Try
code :
'comments_array' hook in function.php

add_filter( 'comments_array' , 'shuffle_comments' , 10, 2 );

function shuffle_comments( $comments , $post_id ){ 
    return shuffle( $comments ); 
How can I make my Quick Sort Algorithm sort the arrays in both Ascending and Descending order?

How can I make my Quick Sort Algorithm sort the arrays in both Ascending and Descending order?

By : Anon Ymous
Date : March 29 2020, 07:55 AM
I wish this helpful for you You can change your Quicksort method to accept an IComparer comparer, and then use that to make the comparisons.
Then you can use Comparer.Default if you want the default comparison order, or you can use Comparer.Create() to create a custom (e.g. reversed) comparison.
code :
using System;
using System.Collections.Generic;

namespace ConsoleApp1
    class Program
        static void Main()
            int[] data = {6, 7, 2, 3, 8, 1, 9, 0, 5, 4};


            Console.WriteLine(string.Join(", ", data)); // Prints 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

            QuickSort(data, Comparer<int>.Create((a, b) => b.CompareTo(a)));

            Console.WriteLine(string.Join(", ", data)); // Prints 9, 8, 7, 6, 5, 4, 3, 2, 1, 0

        public static void QuickSort<T>(T[] data)
            Quick_Sort(data, 0, data.Length - 1, Comparer<T>.Default);

        public static void QuickSort<T>(T[] data, IComparer<T> comparer)
            Quick_Sort(data, 0, data.Length - 1, comparer);

        public static void Quick_Sort<T>(T[] data, int left, int right, IComparer<T> comparer)
            int i, j;
            T pivot, temp;
            i = left;
            j = right;
            pivot = data[(left + right) / 2];
                while ( (comparer.Compare(data[i], pivot) < 0) && (i < right)) i++;
                while ( (comparer.Compare(pivot, data[j]) < 0) && (j > left)) j--;
                if (i <= j)
                    temp = data[i];
                    data[i] = data[j];
                    data[j] = temp;
            } while (i <= j);
            if (left < j) Quick_Sort(data, left, j, comparer);
            if (i < right) Quick_Sort(data, i, right, comparer);
How to sort a list in descending order according to a map which is already sorted in descending order

How to sort a list in descending order according to a map which is already sorted in descending order

By : oae17
Date : March 29 2020, 07:55 AM
With these it helps I have a JSON array (list of maps) similar to: , Given this (from the original post):
code :
def listOfMap = [[TESTCASE:1, METHOD:'CLICK', RESULT:'PASS'],  
def percentage(passCount, failCount) {
    failCount / (passCount + failCount) * 100

def result = listOfMap.groupBy{it.METHOD}.collectEntries{
                def rec = new Expando()
                def count = it.value.countBy{ it.RESULT } 

                rec."passCount" = count.'PASS' ?: 0
                rec."failCount" = count.'FAIL' ?: 0
                rec."percentage" = percentage(rec."passCount",

                [(it.key) : rec]

def sortedResult = result.sort { a, b -> 
                       b.value."percentage" <=> a.value."percentage" 
sortedResult.each { println it }
$ groovy Example.groovy 
TYPETEXT={failCount=1, percentage=100, passCount=0}
CLICK={failCount=2, percentage=66.6666666700, passCount=1}
why Arrays.sort() can't sort primitive type array in descending order?

why Arrays.sort() can't sort primitive type array in descending order?

By : Happyninja 443
Date : March 29 2020, 07:55 AM
may help you . Look at the signature of the Arrays#sort method you are trying to use
code :
  public static <T> void sort(T[] a, Comparator<? super T> c) {
sort records in a descending order with apps-script range.sort() issue

sort records in a descending order with apps-script range.sort() issue

By : eiv
Date : March 29 2020, 07:55 AM
I hope this helps you . I'm looking to sort some records on a sheet via app-script, but I get this error when using range.sort({column: 1, ascending: false});
code :
function sort() {
  var sheet = SpreadsheetApp.openById('1tdfsdfsdbfXMg6wmE7oFG2reA2yt_YTf7IRG').getSheetByName('Sugestions');
  var lastRow = sheet.getLastRow();
  var range = sheet.getRange(3, 1,lastRow-2,11);
  range.sort({column: 1, ascending: false}); // I'm trying to sort column A in a decending order
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