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Create file form python in a user specified directory


Create file form python in a user specified directory

By : Xin Li
Date : November 20 2020, 03:01 PM
hop of those help? There is a much easier way to do this. You are correct in thinking that if the file already exists, you don't want to open it with mode 'w' as this will erase the contents. However, you can 'append' to an empty (new) file as well as a file which has already been created and has contents with the 'a' (append) mode.
So you can just do:
code :
system_file = open(test + '.csv', 'a')


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Create a user in Active Directory from an Infopath form

Create a user in Active Directory from an Infopath form


By : user2176670
Date : March 29 2020, 07:55 AM
around this issue I have now found out what the problem was. I needed to set the form to 'full trust' Tools>form options> Security and Trust. I also had to sign the form with my certificate.
Now I am able to run the code from that button.
How to create a list from filenames in a user specified directory in Python?

How to create a list from filenames in a user specified directory in Python?


By : Ramon Barragan Valen
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I want to create a new list in Python from filenames in a user defined directory . , You could do:
code :
import os
import glob

files = list(glob.glob(os.path.join(directory,'*.*')))
create form from 2 models python django: [Errno 2] No such file or directory

create form from 2 models python django: [Errno 2] No such file or directory


By : Cizl
Date : March 29 2020, 07:55 AM
this one helps. You need to specify a sub-directory of MEDIA_ROOT to upload to that exists on your local file system. Check what is being returned by the get_upload_file_name function and check that that is a sub-directory of MEDIA_ROOT (defined in settings.py) on your local file system:
code :
class Image(models.Model):
    image = models.FileField(upload_to=get_upload_file_name, default="") 
How do I access a file in a sub-directory on user input without having to state the directory in Python 2.7.11?

How do I access a file in a sub-directory on user input without having to state the directory in Python 2.7.11?


By : Yuxiang Que
Date : March 29 2020, 07:55 AM
wish helps you You are using os.path.join('Detector', 'TestCases'), that should return 'Detector/TestCases', but you aren't storing that variable anywhere.
I suppose that you are in Detector directory and you want to open files in TestCases. I that case you can use path join (It concatenates its arguments and RETURNS the result):
code :
    import os.path

    file = None
    while not file:
        input = raw_input('What file to open? ')
        try:
            filepath = os.path.join('TestCases', input)
            file = open(filepath, 'r')
        except IOError:
            print "Can't find " + input
tensorflow.python.framework.errors_impl.NotFoundError: Failed to create a directory: ; No such file or directory

tensorflow.python.framework.errors_impl.NotFoundError: Failed to create a directory: ; No such file or directory


By : chinu
Date : March 29 2020, 07:55 AM
it helps some times This generally happens when code is written for linux os in mind and executed on windows as the directory structure in both os are bit different. for example if in python code the path given with linux in mind could be like this "/tmp/output" this will never work in windows it will give you error. In windows either it should be "./tmp/output" or complete path "c:/tmp/output". I always maintain os specific code for both windows and linux in mind. Check for determination of os the link enter link description here
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