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How to pass calculation form Button command to Entry field?


How to pass calculation form Button command to Entry field?

By : J.Gayler
Date : November 20 2020, 03:01 PM
Any of those help you've done very well and are very close. It is often better to use a simple function (see foo() in my example) to manipulate entry boxes etc..
The entry3.delete(0, END) will ensure that the entry is clear (try it without this line and see what happens!)
code :
from tkinter import *
import calculations


def foo():
    x = addvalues(a=value_a.get(), b=value_b.get())
    entry3.delete(0, END)
    entry3.insert(END, x)


root = Tk()

mainapp = Frame(root)
mainapp.grid()

label1 = Label(mainapp, text="Value A")
label1.grid(row=0, column=0)
value_a = IntVar()
entry1 = Entry(mainapp, textvariable=value_a)
entry1.grid(row=0, column=1)

label2 = Label(mainapp, text="Value B")
label2.grid(row=1, column=0)
value_b = IntVar()
entry2 = Entry(mainapp, textvariable=value_b)
entry2.grid(row=1, column=1)

button = Button(mainapp, text="Calculate",
                command=foo)
button.grid(row=2, columnspan=2)

label3 = Label(mainapp, text="A+B")
label3.grid(row=3, column=0)
value_c = IntVar()
entry3 = Entry(mainapp, textvariable=value_c)
entry3.grid(row=3, column=1)

root.mainloop()


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Pass a field calculation in html to another field in the SAME form

Pass a field calculation in html to another field in the SAME form


By : Thiefnet
Date : March 29 2020, 07:55 AM
it should still fix some issue So, I can only find how to pass the information to another page not the same page and this has to be done entirely on the client side, no server side work as there will be no internet connection when this is used, hence the mailto for the form data so it can be sent when a connection is available. , First of all, no idea what these are for:
code :
var time1 = document.getElementById('time1');
var time2 = document.getElementById('time1');
var time3 = document.getElementById('time1');
var time4 = document.getElementById('time1');
var time5 = document.getElementById('time1');
var time6 = document.getElementById('time1');
var time7 = document.getElementById('time1');
var time8 = document.getElementById('time1');
var build_costval = parseInt(build_cost.value) || 0;
var buy_costval = parseInt(buy_cost.value) || 0;
var build_hoursval = parseInt(build_hours.value) || 0;
var build_trainval = parseInt(build_train.value) || 0;
var build_totalval = parseInt(build_total.value) || 0;
var buy_totalval = parseInt(buy_total.value) || 0;
var designhoursval = parseInt(designhours.value) || 0;
designhoursval = parseInt(designhours.value) || 0;
build_cost.value = (wageval * designhoursval);
Prefill a field on another form with command button

Prefill a field on another form with command button


By : K Brad Munford
Date : March 29 2020, 07:55 AM
Hope this helps Not sure how well I followed the description, but it seems you might take advantage of the OpenArgs parameter with OpenForm. (Your existing code uses the WhereCondition parameter, but that is meaningless for an unbound form.)
OpenArgs is the seventh parameter to OpenForm. If I counted commas correctly, this could work:
code :
DoCmd.OpenForm "Add Item to RMA", , , , , , Me!RMANbr
DoCmd.OpenForm "Add Item to RMA", OpenArgs:=Me!RMANbr
Private Sub Form_Load()
    DoCmd.GoToRecord acDataForm, , acNewRec
    If Not IsNull(Me.OpenArgs) Then
        Me.txtRMANbr = Me.OpenArgs
    End If
End Sub
How to put a button inside of a text entry field in a form on a website using javascript, css, html

How to put a button inside of a text entry field in a form on a website using javascript, css, html


By : Franco Bresciani
Date : March 29 2020, 07:55 AM
Does that help I would like to write a greasemonkey script that make a button inside of a text entry form on some websites, so that the text entry forms would look something like this: , Okay, let's start with jQuery, since it's more concise.
code :
$('form').each(function () {
    $(this).find('input').filter(':text').each(function () {
        $(this).after($('<button>').text('My Button'));
    });
});
var forms = document.getElementsByTagName('form');
for (var i = 0; i < forms.length; i++) {
    var form = forms[i];
    var inputs = form.querySelectorAll("input[type=text]");
    for (var j = 0; j < inputs.length; j++) {
        var input = inputs[j];
        var button = document.createElement('button');
        button.innerText = 'My Button';
        input.parentNode.insertBefore(button, input.nextSibling);        
    }
}
php button that writes a form field entry to file

php button that writes a form field entry to file


By : user2900113
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , There were a few things wrong with your code.
type="button" should be type="submit" and naming the submit button, while adding to the conditional statement, it's best.
code :
$fp = fopen('suggestedterms.txt', 'a+');
<?php
$term = mysql_real_escape_string(sanitizeString($_POST['term']));

//other code for when result is found.
//if no result found:

?>

<form name="suggestit" action="" method="post" >
    <input type="hidden" name="tb1" default="<?php echo $term; ?>" /><p>
    <input type="submit" name="submit" class="styled-button-11" id="bt1" value="Suggest It!" /></p>
</form>

<?php

 if (isset($_POST['tb1']) && isset($_POST['submit'])) {
    echo writetermstofile($term);
    return;
}
function writetermstofile ($term) {


$fp = fopen('suggestedterms.txt', 'w'); // to append use 'a' or 'a+'
fwrite($fp, $term . "\n");
fclose($fp);
}
?>
<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

// rest of your code
Using popup to select correct relational field and pass value back to an entry form

Using popup to select correct relational field and pass value back to an entry form


By : Touka
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Some suggestions to consider. In your popup set a dynamic property, call it 'CreateDatasource' or whatever suits your needs.
In your assets page form where you navigate to your popup (lets say it's a button that opens the popup from your form) put the following code:
code :
var popup = app.popups.YourPopup;
popup.properties.CreateDatasource = widget.datasource;
popup.visible = true;
widget.root.properties.CreateDatasource.item.Location = widget.datasource.item; //this would set the relation only assuming your asset relation end to locations is named 'Location'
widget.root.visible = false;
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