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Why datetime can't recognise the string?


Why datetime can't recognise the string?

By : Johnny Karlen
Date : November 20 2020, 03:01 PM
this will help In this code item.date_time looks like "2017-10-18T04:57:39.000Z". When I put this (or any other similar string) instead of item.date_time - it works well. But despite the fact that item.date_time is equal to strings like this - it calls System.FormatException when I use it. ,
str[0] is equal "\"2017-10-18T04:57:39.000Z\""
code :
    item.date_time = str[0].Trim('"');
    item.datetime = DateTime.ParseExact(item.date_time, "yyyy-MM-ddTHH:mm:ss.000Z", CultureInfo.InvariantCulture);


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Why won't vim recognise a plugin command in the vimrc, but it will recognise it when running?

Why won't vim recognise a plugin command in the vimrc, but it will recognise it when running?


By : shahab computer
Date : March 29 2020, 07:55 AM
around this issue As you determined yourself, plugins are processed after the .vimrc.
What you can do if you don't like using a VimEnter autocmd, is put a file in your ~/.vim/after/plugin directory for any commands that should run after plugins are loaded.
Which formats (explictly) does DateTime.TryParse recognise?

Which formats (explictly) does DateTime.TryParse recognise?


By : Nan Meng
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I think you are looking for this
DateTime.GetDateTimeFormats
code :
DateTime july28 = new DateTime(2009, 7, 28, 5, 23, 15, 16);

string[] july28Formats = july28.GetDateTimeFormats();

// Print out july28 in all DateTime formats using the default culture.
foreach (string format in july28Formats) {
    Console.WriteLine(format);
}
Cannot recognise $startTime as a system.datetime due to a format error

Cannot recognise $startTime as a system.datetime due to a format error


By : jonathas
Date : March 29 2020, 07:55 AM
seems to work fine Hi I get this format error when I try and specify the value for a DateTime parameter. Here is my script which I am running by pressing F5 in Powershell ISE: , I can't exactly duplicate what you are seeing. Here is my script:
code :
7> Get-Content .\startTime.ps1
param
(
    [Parameter(Mandatory=$true)]
    [datetime]$startTime
)

write-output $startTime
8> .\startTime.ps1 (Get-Date)

Monday, March 30, 2015 9:48:01 PM
10> .\startTime.ps1 (new-object DateTime 2015,03,31)

Tuesday, March 31, 2015 12:00:00 AM
11> .\startTime.ps1 $(new-object DateTime 2015,03,31)

Tuesday, March 31, 2015 12:00:00 AM
Php datetime function doesn't recognise dates before 1000

Php datetime function doesn't recognise dates before 1000


By : JulsR
Date : March 29 2020, 07:55 AM
I hope this helps you . DateTime has no such limitation, but the date function you use to initialise it, does. You can use DateTime::setDate to set any year you want:
code :
php > $a = new DateTime("2015-08-24");
php > echo $a->format(DateTime::ISO8601);
2015-08-24T00:00:00+0000

php > $a->setDate(90, 8, 24);
php > echo $a->format(DateTime::ISO8601);
0090-08-24T00:00:00+0000

php > $a->setDate(90090, 8, 24);
php > echo $a->format(DateTime::ISO8601);
90090-08-24T00:00:00+0000
How to replace invalid datetime string with a correct format of datetime string when using DateTime.ParseExact()?

How to replace invalid datetime string with a correct format of datetime string when using DateTime.ParseExact()?


By : Proplaner
Date : March 29 2020, 07:55 AM
I wish this help you I would like to order my list based on a string type property that contains DateTime. In order to do that, I convert the string property into DateTime inside the OrderBy() or OrderByDescending(). So here is my code: , what about a simple condition inside the OrderBy()
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