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My program produces print statement infinity in a loop. Don't know how to fix it


My program produces print statement infinity in a loop. Don't know how to fix it

By : Florian Kauerauf
Date : November 20 2020, 03:01 PM
hop of those help? So I'm trying to learn Python and I have written a program that is essentially designed to play a game with the user and a computer. , This part is the bug:
code :
while(userscore <= Game_End_Points and computerscore <= Game_End_Points):
        print_current_player(is_user_turn)
def print_current_player(is_user_turn):

    if (is_user_turn == True):
        print("It is now human's turn")
    if (is_user_turn == False):
        print("It is now computer's turn")


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Infinity loop in while statement

Infinity loop in while statement


By : Robert Lopes
Date : March 29 2020, 07:55 AM
With these it helps The problem is that the failed input operation doesn't extract any characters from the stream (and you'll keep reading the invalid input over and over), so you have to empty the input manually. For example:
code :
char buf[1000];

// ...

if(scanf("%d", &s) != 1)
{
    puts("Error, try again: ");
    fgets(buf, 1000, stdin);
}
How to convert infinity while loop to a pipeline statement

How to convert infinity while loop to a pipeline statement


By : maxa
Date : March 29 2020, 07:55 AM
wish of those help @PetSerAl gave the crucial pointer in a comment on the question: A script block containing an infinite loop, invoked with the call operator (&), creates an infinite source of objects that can be sent through a pipeline:
& { while ($true) { ... } }
code :
& { while ($true) { Get-Date; Start-Sleep 1 } } | Select-Object -First 5
do { 
   & { while ($true) { Get-Date; Start-Sleep 1 } } |
     % { $i = 0 } { $_; if (++$i -eq 5) { break } }  # `break` stops the pipeline and
                                                     # breaks out of the dummy loop
} while ($false)
& { while (-not $done) { Get-Date; Start-Sleep 1 } } |
  % { $done = $false; $i = 0 } { $_; if (++$i -eq 5) { $done = $true } }
Why is the while loop in my program running to infinity

Why is the while loop in my program running to infinity


By : Kate
Date : March 29 2020, 07:55 AM
To fix the issue you can do You aren't striping the newline characters from the inputs you are reading from the file. Each of the lines has a hidden \n at the end of them. It is a simple fix to just add .strip()
code :
choice = myFile.readline().strip()
Why this c program fall into infinity loop?

Why this c program fall into infinity loop?


By : a.gh
Date : March 29 2020, 07:55 AM
Any of those help , Given
code :
while(scanf("%[^\n]s", s)!=EOF)
{
   printf("%s", s);
}
foo\n
bar\n
<<EOF>>
\n
bar\n
<<EOF>>
while(scanf(" %[^\n]", s)!=EOF)
{
   printf("%s", s);
}
while(scanf(" %9[^\n]", s)!=EOF)
{
   printf("%s", s);
}
while (scanf(" %9[^\n]", s) == 1)
{
   printf("%s", s);
}
while (fgets(s, 10, stdin))
{
    printf("%s", s);
}
while (fgets(s, 10, stdin))
{
    fputs(s, stdout);
}
My ASM Program for x86 8086 dont print well

My ASM Program for x86 8086 dont print well


By : user2043820
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have this code in asm x86 with DOSBox virtualization :
code :
mov al,1     <-- function number goes in AH
int 21h
add bl,al
mov ah, 1
int 21h
mov bl, al

mov ah, 1
int 21h
add bl, al     ; This now contains 2 times '0'

sub bl, '0'    ; Here you correctly subtract 1 of those
mov dl, bl
mov ah, 2
int 21h
mov ah, 01h
int 21h          ; eg. input '3'
sub al, '0'      ; '3' - '0' = 3
mov bl, al       ; 3

mov ah, 01h
int 21h          ; eg. input '5'
sub al, '0'      ; '5' - '0' = 5
add bl, al       ; 3 + 5 = 8

mov dl, bl
add dl, '0'      ; 8 + '0' = '8' 
mov ah, 02h
int 21h          ; outputs '8'
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