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RxJs how to merge two overlapping observable into one


RxJs how to merge two overlapping observable into one

By : Porsche VanBrocklin
Date : November 20 2020, 03:01 PM
With these it helps I think the best approach here is to buffer b$ until a$ stream reaches b$, then emit all the buffered items of b$ and switch to b$. Something like this:
code :
const a = '-1-2-3-4-5-6-7-8-9-10-11-12-13-14-15';
const b = '-13--14--15--16--17--18--19-----20---------21--------------22------23--24';

const fromMarble = str => Rx.Observable.from(str.split('-')).concatMap(x => Rx.Observable.of(x).delay(1)).filter(v => v.length).map(x => parseInt(x));

const a$ = fromMarble(a).share();
const b$ = fromMarble(b).share();

const switchingSignal$ = Rx.Observable.combineLatest(a$, b$.take(1), (a, b) => a >= b).filter(x => x).take(1).share();

const distinct$ = Rx.Observable.merge(
	a$.takeUntil(switchingSignal$).map(x => x + '(from a)'), 
	b$.buffer(switchingSignal$).take(1).mergeMap(buffered => Rx.Observable.from(buffered)).map(x => x + '(from b$ buffer)'),
	b$.skipUntil(switchingSignal$).map(x => x + '(from b$)')
);

distinct$.subscribe(console.log);
<script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/5.5.0/Rx.js"></script>


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Tricky steam observable merge in rxjs

Tricky steam observable merge in rxjs


By : phreebsd
Date : March 29 2020, 07:55 AM
may help you . You aren't terribly far off actually. You are just missing the inclusion of zip really. Since what you really need for propagation is for both a mouse click and the request to complete. By zipping the request and the mouse click event you can make sure that neither emits without the other.
code :
const hover$ = Rx.Observable.fromEvent(myButton, 'mouseenter');
const leave$ = Rx.Observable.fromEvent(myButton, 'mouseleave');
const click$ = Rx.Observable.fromEvent(myButton, 'click');


//Make sure only the latest hover is emitting requests
hover$.flatMapLatest(() => {

  //The content request
  const pending$ = fetchContent();

  //Only cancel on leave if no click has been made
  const canceler$ = leave$.takeUntil(click$);

  //Combine the request result and click event so they wait for each other
  return Rx.Observable.zip(pending$, click$, (res, _) => res)

               //Only need the first emission
               .take(1)

               //Cancel early if the user leaves the button
               .takeUntil(canceler$);

});
RxJS Observable merge angular

RxJS Observable merge angular


By : Friedrich Josef
Date : March 29 2020, 07:55 AM
it helps some times You have the right general idea. Just a few flaws.
Never use new Observable(). It does not do what you think it does. It pretty much does not do anything useful. Always construct observables from factory methods or other observables You need to transform the params observable into a new observable using an operator. Your problem is you subscribe to the params observable, and then construct new observables each time. But other code will have already subscribed to the initial observables so they will never see the changes.
code :
sentMessages$ : Observable<Array<Message>>;
receivedMessages$ : Observable<Array<Message>>;
matchingMessages$ : Observable<Array<Message>>;

ngOnInit() {
    const params$ = this.route.params;

    // use switchMap to map the new params to a new sent observable
    // each time params change, unsubscribe from the old fetch and subscribe
    // to the new fetch.  Anyone subscribed to "sentMessages" will see the
    // change transparently
    this.sentMessages$ = params$.switchMap((params: Params) => this.sb.fetchReceived(params['id']));
    // same for received
    this.receivedMessages$ = params$.switchMap((params: Params) => this.sb.fetchSent(params['id'])));

    // merge the 2 streams together
    this.matchingMessages$ = Observable.merge(this.sentMessages$, this.receivedMessages$);
}
fetchEither(id: string): Observable<Array<Message>> {
    return this.messages$.map((messages: any) => {
        return messages.filter((message: Message) => {
            return message.recipientId == id || message.userId === id;
        });

    });
}
matchingMessages$ : Observable<Array<Message>>;

ngOnInit() {
    const params$ = this.route.params;

    // use switchMap to map the new params to a new either observable
    // each time params change, unsubscribe from the old and subscribe
    // to the new fetch.  Anyone subscribed to "matchingMessages" will see the
    // change transparently
    this.matchingMessages$ = params$.switchMap((params: Params) => this.sb.fetchEither(params['id']));
}
RXJS + Redux Observable - how to merge a new stream?

RXJS + Redux Observable - how to merge a new stream?


By : Selva Kumar
Date : March 29 2020, 07:55 AM
will be helpful for those in need This code is actually correct. The dependency was using 'rx' library rather than 'rxjs' which caused a conflict.
all
RxJS proper way to merge 3 arrays into one, as an Observable

RxJS proper way to merge 3 arrays into one, as an Observable


By : Akazel Kaspedia
Date : March 29 2020, 07:55 AM
this will help combineLatest takes an optional project function that can be used to modify the combined value.
You can specify a project function that uses Array.prototype.reduce to flatten the arrays into a single array:
code :
const arr1$ = new Rx.BehaviorSubject(['1','2']);
const arr2$ = new Rx.BehaviorSubject(['3','7']);
const arr3$ = new Rx.BehaviorSubject(['4']);

Rx.Observable
  .combineLatest(
    arr1$, arr2$, arr3$,
    (...arrays) => arrays.reduce((acc, array) => [...acc, ...array], [])
  )
  .subscribe(value => console.log(value));
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://unpkg.com/rxjs@5/bundles/Rx.min.js"></script>
RxJS Merge Observable in Callback

RxJS Merge Observable in Callback


By : suraj pal
Date : March 29 2020, 07:55 AM
To fix this issue I need a little help with making a function return an observable. I have a function (let's call it mainFunction), that calls an async function (let's call it getAsyncWithCallback) and executes a callback. Part of the callback is an async call that returns an observable (let's call it getData). , my solution:
code :
mainFunction(): Observable<any> {

    return Rx.Observable.create(observer => {
        getAsyncWithCallback((): void => {
            getData().subscribe(observer);
        })
    })
}

mainFunction().subscribe((data) => {
    console.log(data);
})); 
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