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Converting time in R to 24 hours


Converting time in R to 24 hours

By : Vlad
Date : November 20 2020, 03:01 PM
I wish this help you It should be safe to assume all times less than 100 need to be multiplied by 100. After that, it's just a matter of correcting for times before 800:
code :
correct_times <- function(times) {
  times_hmm <- ifelse(times < 100,
                      times * 100,
                      times)

  ifelse(times_hmm < 800,
         times_hmm + 1200,
         times_hmm)
}
correct_times(c(1, 12, 500, 1800, 9, 1230))
#> [1] 1300 1200 1700 1800  900 1230


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Converting time presented in hours and minutes into decimal and calculate the sum in hours using xslt 1.0

Converting time presented in hours and minutes into decimal and calculate the sum in hours using xslt 1.0


By : Žaltvyksle Žaltvyksl
Date : March 29 2020, 07:55 AM
will be helpful for those in need Do note that the solution in Joepie's answer causes compile-time syntax error in any compliant XSLT 1.0 processor (it can only be executed without compilation errors if one uses an XSLT 2.0 processor):
code :
SAXON 6.5.4 from Michael Kay
Java version 1.6.0_31
Error at xsl:value-of on line 11 of file:/(Untitled):
  Error in expression                      sum(hours/number(substring-before(., ':'))) +                     sum(hours/number(substring-after(., ':'))) div 60                 : Unexpected token [<function>] in path expression
Transformation failed: Failed to compile stylesheet. 1 error detected.
Press any key to continue . . . 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/*">
     <xsl:copy>
       <xsl:variable name="vrtfTimes">
         <xsl:for-each select="*">
           <t>
               <xsl:value-of select=
               "substring-before(., ':') + substring-after(.,':') div 60"/>
           </t>
         </xsl:for-each>
       </xsl:variable>
       <TotalHours>
         <xsl:value-of select="floor(sum(ext:node-set($vrtfTimes)/*))"/>
       </TotalHours>
     </xsl:copy>
 </xsl:template>
</xsl:stylesheet>
<Record>
    <hours>10:30</hours>
    <hours>20:30</hours>
    <hours>10:60</hours>
</Record>
<Record>
   <TotalHours>42</TotalHours>
</Record>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="/*">
   <xsl:copy>
     <xsl:variable name="vrtfTimes">
       <xsl:for-each select="*">
         <t>
           <xsl:value-of select=
             "substring-before(., ':') + substring-after(.,':') div 60"/>
         </t>
       </xsl:for-each>
     </xsl:variable>

     <xsl:variable name="vSum" select="sum(ext:node-set($vrtfTimes)/*)"/>
     <TotalHours>
             <xsl:value-of select="floor($vSum)"/>
             <xsl:text>:</xsl:text>
             <xsl:value-of select="round(60* ($vSum - floor($vSum)))"/>
     </TotalHours>
   </xsl:copy>
 </xsl:template>
</xsl:stylesheet>
<Record>
    <hours>10:30</hours>
    <hours>20:30</hours>
    <hours>10:60</hours>
    <hours>1:15</hours>
    <hours>1:03</hours>
</Record>
<Record>
   <TotalHours>44:18</TotalHours>
</Record>
Converting Hours passed to Current Time

Converting Hours passed to Current Time


By : user2705428
Date : March 29 2020, 07:55 AM
this one helps. There are two parts:
You have to apply modulo 24 to the elapsed time. Why. If you start at 9 o'clock today, and 24 hours elapsed, you add zero hours (24 % 24) and you have 9 o'clock the next day. Let us assume 37 have elapsed. Apply #1 above and you have 13 hours beyond 24. Add 13 to 9 and you have 22 hours (10 o'clock PM). If you don't want to use 24 hour calendar, subtract 12 from current hour IF current hour > 12.
code :
currentTime += elapsedTime % 24; 
if(currentTime > 12) 
{
    currentTime -= 12;
}
public class PassingTrains
{
    static int currentTime = 9, firstDistance = 0, secondDistance = 0,
            firstSpeed = 40, secondSpeed, elapsedTime;
    static Scanner input = new Scanner(System.in);

    public static String passTime()
    {
        System.out.print("Enter the speed of the passenger train: ");
        secondSpeed = input.nextInt();
        while (currentTime < 11)
        {
            firstDistance += firstSpeed;
            currentTime++;
        }
        while (firstDistance > secondDistance)
        {
            firstDistance += firstSpeed;
            secondDistance += secondSpeed;
            elapsedTime++;  // changed this

        }
        // added the next two lines
        currentTime += elapsedTime % 24;
        currentTime = (currentTime > 12) ? currentTime - 12 : currentTime;

        if (firstDistance == secondDistance)
        {
            return ("at " + currentTime); // fixed this
        }
        else
        {
            return ("between " + ((currentTime - 1 == 0) ? 12 : currentTime - 1) + " o'clock and " + currentTime); \\fixed this
        }
    }

    public static void main(String[] args)
    {
        System.out.println("The passenger train passed the freight train at "
                + passTime() + " o'clock");
        System.out.println("The freight train was traveling " + firstSpeed
                + " mph");
        System.out.println("The passenger train was traveling at "
                + secondSpeed + " mph");
    }
}
Python converting time zone into hours?

Python converting time zone into hours?


By : Areeba Gill
Date : March 29 2020, 07:55 AM
will be helpful for those in need From the documentation:
Converting double to time(hours and Minute)

Converting double to time(hours and Minute)


By : sule
Date : March 29 2020, 07:55 AM
it helps some times I am new to program in VBA i am stuck with a small conversion , I have an input data as "double", I have another 2 value as in time format . I want to add this double in time format and out put as time , You're on the right path but over-complicating...
code :
Result = TotalHours + ((StartTime + EndTime) * 24)
Converting a UTC date to a local time with Swift: hours added instead of hours removed

Converting a UTC date to a local time with Swift: hours added instead of hours removed


By : sid
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further It is simple actually. timeZone property of DateFormatter is telling the DateFormatter what timezone the string generated from Date should be in OR what timezone is the string that you are trying to convert to Date.
What it means in your case?
code :
  let formatter = DateFormatter()
  formatter.dateFormat = "yyyy/MM/dd' 'HH:mm:ss"
  formatter.timeZone = TimeZone(secondsFromGMT:0) // UTC
  let defaultTimeZoneStr = formatter.string(from: self)
  let dateFormatter = DateFormatter()
  formatter.timeZone = TimeZone.current // Local
  dateFormatter.dateFormat = "yyyy/MM/dd' 'HH:mm:ss"

  return dateFormatter.date(from:defaultTimeZoneStr)!
extension Date {
  func format(_ format: String) -> String {
    let formatter = DateFormatter()
    formatter.dateFormat = format
    formatter.timeZone = TimeZone.current // Local
    return formatter.string(from: self)
  }
}
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