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By : Tim Waters
Date : November 21 2020, 03:00 PM
With these it helps you can use simply array_unique and array_diff_assoc function . here is an example code :
``````\$array = [1,2,3,1,2];
\$unique_array = array_unique(\$array);
\$array = array_diff_assoc(\$array, \$unique_array);
\$array = \$array_unique(\$array);
print_r(\$array);
``````
``````Array (  => 1  => 2 )
`````` ## How to find element number from either a single, or a range of values in an array

By : Bonnie Raborn
Date : March 29 2020, 07:55 AM
Any of those help There are a couple of ways to address this, which range from quick to complex. The easiest way is to brute force it like such:
code :
``````int max = 0;
//int test = 0;
for (int counter = 0; counter < countOfArray.length; counter++)
{
if (countOfArray[counter] >= max)
{
max = countOfArray[counter];
//test = counter + 1;
}
}

System.out.print("The number that appears the most is");
boolean first = true;
for(int i = 0; i < countOfArray.length; i++)
{
if(countOfArray[i] == max)
{
if(first)
first = false;
else
System.out.print(",");
System.out.print(" " + (i+1) );
}
}
System.out.println(".");
``````
``````6   2   6   5   6   8   9   3   5   8
9   8   10  10  4   5   8   9   8   5
1   7   8   5   6   7   10  4   5   4
2   7   9   2   3   3   1   2   10  3
5   2   10  1   1   6   3   3   8   10
2   6   10  2   5   1   4   10  8   7
7   8   7   3   7   8   3   4   5   5
7   8   9   8   6   6   8   1   10  3
2   5   4   6   9   9   10  10  1   10
9   4   10  9   7   3   4   3   2   4

The number 1 occurs 7 times.
The number 2 occurs 9 times.
The number 3 occurs 11 times.
The number 4 occurs 9 times.
The number 5 occurs 11 times.
The number 6 occurs 9 times.
The number 7 occurs 9 times.
The number 8 occurs 13 times.
The number 9 occurs 9 times.
The number 10 occurs 13 times.

1   *******
2   *********
3   ***********
4   *********
5   ***********
6   *********
7   *********
8   *************
9   *********
10  *************

The number that appears the most is 8, 10.
`````` ## add Incremented Number value to array based on common string values

By : user2333033
Date : March 29 2020, 07:55 AM
I hope this helps . This code simply counts up the number of occurrences of a string, then stores that in the tempNum array, and when the searching through arr1 is complete, the tempNum array is returned to the caller.
code :
``````private function findVal(arr1:Array, arr2:Array): Array {

var tempNum:Array = new Array(arr1.length);

for (var i:int = 0; i < arr1.length; i++) {
var num:int = 0;
for (var j:int = 0; j < arr2.length; j++) {
if (arr1[i] == arr2[j]) {
num++;  // count up the number of occurrences as you iterate through arr2 and compare with arr1
}
}
tempNum[i] = num; // store the number of occurrences of string at index i of arr1 that occurred in arr2
}

return(tempNum);
}
`````` ## how to combine 2 array values into single one by common value

By : alostplectra
Date : March 29 2020, 07:55 AM
wish help you to fix your issue 1.fetching the values from a same table with different date , Do it like below:-
code :
``````\$final_array = array();

if(count(\$arr1)>=count(\$arr2)){
foreach (\$arr1 as \$arr){
\$key='';
foreach (\$arr2 as \$ar2){
if(\$arr['isp'] == \$ar2['isp']){
\$final_array[\$arr['isp']] = array(\$arr['isp'],\$arr['sent_yest'],\$ar2['sent_today']);
\$key ='';break;
}else{
\$key = \$arr['isp'];
}
}
if(\$key!==''){
\$final_array[\$key] = array(\$arr['isp'],\$arr['sent_yest'],0);
\$key ='';
}
}
}

if(count(\$arr2)>count(\$arr1)){
foreach (\$arr2 as \$ar2){
\$key='';
foreach (\$arr1 as \$arr){
if(\$ar2['isp'] == \$arr['isp']){
\$final_array[\$ar2['isp']] = array(\$ar2['isp'],\$arr['sent_yest'],\$ar2['sent_today']);
\$key ='';break;
}else{
\$key = \$ar2['isp'];
}
}
if(\$key!==''){
\$final_array[\$key] = array(\$ar2['isp'],0,\$ar2['sent_today']);
\$key ='';
}
}
}

echo "<pre/>";print_r(\$final_array);
`````` ## How to List the Sum of a Number of Values in an Array for a Number of Times and Find the Most Common Output?

By : user3715333
Date : March 29 2020, 07:55 AM
Make 2D table of size 6 x Maxsum.
code :
``````if (A[k-1][s-v] > 0)
A[k][s] = A[k-1][s-v] + 1
`````` ## Merge array like common values from all arrays go first and then less common values afterwards and remaining values at t

By : Tarun Rawal
Date : September 25 2020, 09:00 AM
this one helps. merge the arrays (array_merge) count the values (array_count_values) sort the values (reversed) and keep the keys (arsort) get the keys (array_keys)
code :
``````    \$array1 = array( 1, 2, 3 );
\$array2 = array( 2, 3, 4 );
\$array3 = array( 2, 5, 6 );

\$ar = array_merge(\$array1, \$array2, \$array3);
\$counts = array_count_values(\$ar);
arsort(\$counts);
\$output = array_keys(\$counts);

var_dump(\$output);
``````
``````array(6) {
=>
int(2)
=>
int(3)
=>
int(1)
=>
int(4)
=>
int(5)
=>
int(6)
}
`````` 