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Get common number of values in a single array


Get common number of values in a single array

By : Tim Waters
Date : November 21 2020, 03:00 PM
With these it helps you can use simply array_unique and array_diff_assoc function . here is an example
code :
$array = [1,2,3,1,2];
$unique_array = array_unique($array);
$array = array_diff_assoc($array, $unique_array);
$array = $array_unique($array);
print_r($array);
Array ( [3] => 1 [4] => 2 ) 


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How to find element number from either a single, or a range of values in an array

How to find element number from either a single, or a range of values in an array


By : Bonnie Raborn
Date : March 29 2020, 07:55 AM
Any of those help There are a couple of ways to address this, which range from quick to complex. The easiest way is to brute force it like such:
code :
int max = 0;
//int test = 0;
for (int counter = 0; counter < countOfArray.length; counter++)
{
    if (countOfArray[counter] >= max)
    {
        max = countOfArray[counter];
        //test = counter + 1;
    }
}

System.out.print("The number that appears the most is");
boolean first = true;
for(int i = 0; i < countOfArray.length; i++)
{
    if(countOfArray[i] == max)
    {
        if(first)
            first = false;
        else
            System.out.print(",");
        System.out.print(" " + (i+1) );
    }
}
System.out.println(".");
6   2   6   5   6   8   9   3   5   8   
9   8   10  10  4   5   8   9   8   5   
1   7   8   5   6   7   10  4   5   4   
2   7   9   2   3   3   1   2   10  3   
5   2   10  1   1   6   3   3   8   10  
2   6   10  2   5   1   4   10  8   7   
7   8   7   3   7   8   3   4   5   5   
7   8   9   8   6   6   8   1   10  3   
2   5   4   6   9   9   10  10  1   10  
9   4   10  9   7   3   4   3   2   4   

The number 1 occurs 7 times.
The number 2 occurs 9 times.
The number 3 occurs 11 times.
The number 4 occurs 9 times.
The number 5 occurs 11 times.
The number 6 occurs 9 times.
The number 7 occurs 9 times.
The number 8 occurs 13 times.
The number 9 occurs 9 times.
The number 10 occurs 13 times.

1   *******
2   *********
3   ***********
4   *********
5   ***********
6   *********
7   *********
8   *************
9   *********
10  *************

The number that appears the most is 8, 10.
add Incremented Number value to array based on common string values

add Incremented Number value to array based on common string values


By : user2333033
Date : March 29 2020, 07:55 AM
I hope this helps . This code simply counts up the number of occurrences of a string, then stores that in the tempNum array, and when the searching through arr1 is complete, the tempNum array is returned to the caller.
code :
private function findVal(arr1:Array, arr2:Array): Array {

    var tempNum:Array = new Array(arr1.length);

    for (var i:int = 0; i < arr1.length; i++) {
        var num:int = 0;
        for (var j:int = 0; j < arr2.length; j++) {
            if (arr1[i] == arr2[j]) {
                num++;  // count up the number of occurrences as you iterate through arr2 and compare with arr1
            }
        }
        tempNum[i] = num; // store the number of occurrences of string at index i of arr1 that occurred in arr2
    }

    return(tempNum);
}
how to combine 2 array values into single one by common value

how to combine 2 array values into single one by common value


By : alostplectra
Date : March 29 2020, 07:55 AM
wish help you to fix your issue 1.fetching the values from a same table with different date , Do it like below:-
code :
$final_array = array();

if(count($arr1)>=count($arr2)){
  foreach ($arr1 as $arr){
      $key='';
      foreach ($arr2 as $ar2){
         if($arr['isp'] == $ar2['isp']){
            $final_array[$arr['isp']] = array($arr['isp'],$arr['sent_yest'],$ar2['sent_today']);
            $key ='';break;
         }else{
             $key = $arr['isp'];
         }
      }
      if($key!==''){
            $final_array[$key] = array($arr['isp'],$arr['sent_yest'],0);
            $key ='';
      }
  }
}

if(count($arr2)>count($arr1)){
   foreach ($arr2 as $ar2){
       $key='';
      foreach ($arr1 as $arr){
         if($ar2['isp'] == $arr['isp']){
            $final_array[$ar2['isp']] = array($ar2['isp'],$arr['sent_yest'],$ar2['sent_today']);
             $key ='';break;
         }else{
             $key = $ar2['isp'];
         }
      }
      if($key!==''){
            $final_array[$key] = array($ar2['isp'],0,$ar2['sent_today']);
            $key ='';
      }
   }
}

echo "<pre/>";print_r($final_array);
How to List the Sum of a Number of Values in an Array for a Number of Times and Find the Most Common Output?

How to List the Sum of a Number of Values in an Array for a Number of Times and Find the Most Common Output?


By : user3715333
Date : March 29 2020, 07:55 AM
help you fix your problem If I understand your problem right, you can solve it using dynamic programming.
Make 2D table of size 6 x Maxsum.
code :
if (A[k-1][s-v] > 0)
     A[k][s] = A[k-1][s-v] + 1
Merge array like common values from all arrays go first and then less common values afterwards and remaining values at t

Merge array like common values from all arrays go first and then less common values afterwards and remaining values at t


By : Tarun Rawal
Date : September 25 2020, 09:00 AM
this one helps. merge the arrays (array_merge) count the values (array_count_values) sort the values (reversed) and keep the keys (arsort) get the keys (array_keys)
code :
    $array1 = array( 1, 2, 3 );
    $array2 = array( 2, 3, 4 );
    $array3 = array( 2, 5, 6 );

    $ar = array_merge($array1, $array2, $array3);
    $counts = array_count_values($ar);
    arsort($counts);
    $output = array_keys($counts);

    var_dump($output);
array(6) {
  [0]=>
  int(2)
  [1]=>
  int(3)
  [2]=>
  int(1)
  [3]=>
  int(4)
  [4]=>
  int(5)
  [5]=>
  int(6)
}
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