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MySQL - selecting all records except the ones already associated in the relational table


MySQL - selecting all records except the ones already associated in the relational table

By : Pytboune
Date : November 21 2020, 03:00 PM
This might help you It's been a while since I had to write raw MySQL queries and lost touch a bit. I have a following situation in tables , This is a simple exclusion join:
code :
SELECT c.ID, c.NAME
FROM Company AS c
LEFT OUTER JOIN Client_Company AS cc ON c.ID=cc.COMPANY_ID AND cc.CLIENT_ID=10
WHERE cc.COMPANY_ID IS NULL


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MySQL; limiting records from one table when selecting from three

MySQL; limiting records from one table when selecting from three


By : Nishant
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Assuming upload date is unique for a person, use a sub query to get the latest photo date for each person and join that against the photos table:-
code :
SELECT * 
FROM persons
INNER JOIN personcategorylookup ON personcategorylookup.personUID = persons.uID
INNER JOIN 
(
    SELECT personUID, MAX(uploadDate) AS latest_photo_date
    FROM photos 
    GROUP BY personUID
) sub0
ON sub0.personUID = persons.uID
INNER JOIN photos ON sub0.personUID = photos.personUID AND sub0.latest_photo_date = photos.uploadDate
WHERE personcategorylookup.categoryUID = 1
Selecting records from mysql table

Selecting records from mysql table


By : user2275448
Date : March 29 2020, 07:55 AM
will help you Group by the docnum and select only those having all 4 words you look for
code :
select docnum
from your_table
where word in ('blue','pen','green','key')
group by docnum
having count(distinct word) = 4
Performing a relational Query and selecting distinct records by the combination of two columns in MySql

Performing a relational Query and selecting distinct records by the combination of two columns in MySql


By : anderesa
Date : March 29 2020, 07:55 AM
it should still fix some issue I have two tables in my database, users and user activities, The user table has id, first_name,last_name and other fields, the user activities table has, id, user_id (foreign key --> from the users table) and project id. I want to select distinct user names (combination of first and last name) where project_id is 1. , There is two approaches.
Simple Query Builder
MySQL Selecting all records from one table and their matches/NULL from another table

MySQL Selecting all records from one table and their matches/NULL from another table


By : Jenek
Date : March 29 2020, 07:55 AM
like below fixes the issue You should use left join since you want to return also row for student that has no subject assigned. Plus you want to sort the result, not group. So in the end should be like this:
code :
SELECT students.first_name, subjects.subject_name
FROM students
LEFT JOIN entries ON entries.student_id_fk = students.student_id
LEFT JOIN subjects ON entries.subject_id_fk = subjects.subject_id
ORDER BY  students.first_name;
Mysql get records having multiple values on a different (relational) table (manyToMany)

Mysql get records having multiple values on a different (relational) table (manyToMany)


By : Asif Hussain
Date : March 29 2020, 07:55 AM
Any of those help I need some help getting records based on a criteria where joining items table with their values table, having multiple search values. , Try this query
code :
SELECT p.id,p.title
FROM product_products p 
LEFT JOIN product_attribute_values v ON v.product_id = p.id
LEFT JOIN product_attribute_options o ON o.id = v.option_id
WHERE (p.id = 82 OR p.parent_id = 82)
  AND (o.id IN (25, 3))
GROUP BY p.id,p.title
HAVING COUNT(DISTINCT o.id) = 2
SELECT p.*,o.id
FROM
  (
    SELECT p.id,p.title
    FROM product_products p 
    JOIN product_attribute_values v ON v.product_id = p.id
    JOIN product_attribute_options o ON o.id = v.option_id AND o.id IN (25, 3)
    WHERE (p.id = 82 OR p.parent_id = 82)
    GROUP BY p.id,p.title
    HAVING COUNT(DISTINCT o.id) = 2
  ) p
JOIN product_attribute_values v ON v.product_id = p.id
JOIN product_attribute_options o ON o.id = v.option_id AND o.id IN (25, 3)
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