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In Mac OSX Terminal, how can we determine tally up a count of .jpg files that do not have a certain word inside?


In Mac OSX Terminal, how can we determine tally up a count of .jpg files that do not have a certain word inside?

By : AODA
Date : November 21 2020, 03:00 PM
wish of those help I recently downloaded all my photos from Google Photos using their Takeout option. They usually have issues with missing photos so I am trying to make sure the number of photos I have online match the number I downloaded. The MAIN problem here is that Google Takeout will not only create a new folder for each day (2014-12-23) for example, but ALSO contains other files inside the folder such as metadata.json and 2014-12-23-edited.jpg. , You can use:
code :
find /path/to/top/folder -iname "*.jpg" '!' -iname "*-edited.jpg" | wc -l


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How to count occurrences of a word in all the files of a directory? But with count incremented only once per word per fi

How to count occurrences of a word in all the files of a directory? But with count incremented only once per word per fi


By : Joep Bovendeaard
Date : March 29 2020, 07:55 AM
Any of those help This question is an additional constraint on this this question. I wanted achieve the word count by avoiding multiple counts for that same word in the same file? Eg : if word "aaa" appears in "file1.txt" 10 times, but count should increase only by 1 but not 10 & so on for other files too within a directory. , So what you want is the number of files that contain that word. Easy:
code :
grep -l word *|wc -l
searching a word in multiple pdf files and indexing pdf based on the word count

searching a word in multiple pdf files and indexing pdf based on the word count


By : user3056918
Date : March 29 2020, 07:55 AM
hop of those help? It seems like you're looking for a starting point or idea rather than a specific solution - you have a few options here.
First of all you need to make sure that the text content of the PDFs is searchable. Here's one way for example, using Adobe Acrobat.
C - How to count exact word in a string? (exluding the times the word is inside of another)

C - How to count exact word in a string? (exluding the times the word is inside of another)


By : eddie H
Date : March 29 2020, 07:55 AM
seems to work fine After you've found "if" using strstr, check the characters immediately before and after to make sure they're not a letter. Like:
code :
{
  char *p = str;
  while (((p = (strstr(p, "if"))) != NULL)) {
    if ((p == str || !isalnum((unsigned char) p[-1])) &&
         !isalnum((unsigned char) p[2]))
      ++ifs;
    ++p;
  }
}
Ruby using count to tally instances of a word instead of its component letters

Ruby using count to tally instances of a word instead of its component letters


By : H2O
Date : March 29 2020, 07:55 AM
will help you count counts the number of individual characters, not the instances of the string.
Try:
code :
wins = tencentbeernight.scan(teamname).length
My word tally program only tallies the last word in a text file. Where did I go wrong?

My word tally program only tallies the last word in a text file. Where did I go wrong?


By : Sudarshan Sodhani
Date : March 29 2020, 07:55 AM
I wish this help you I want to tally up the word freq. from text files. The issue I'm facing is that only the last word is tallied. , Your problem is here:
code :
wordcount = {word:count_1}
wordcount[word] = count_1
def main():
    import collections

    rep = input("Enter a text file: ")
    infield = open(rep, 'r')

    s = infield.read()
    punctuation = [',',';','.',':','!',"'","\""]
    for ch in punctuation:
        s = s.replace(ch,' ')
    s = s.split()
    wordcount = collections.Counter(s) # <===
    print (wordcount.most_common())    # <===

main()
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