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Discord.NET Users playing the same game


Discord.NET Users playing the same game

By : Paul Jefferyes
Date : November 21 2020, 03:00 PM
may help you . There is no need to have params string[] s for the game parameter. Just use the Remainder attribute.
I have also simplified this code alot :
code :
    [Command("playing")]
    public async Task GetUsersPlaying([Remainder]string game)
    {
        await Context.Message.DeleteAsync();

        var users = Context.Guild.Users.Where(x => x.Game.ToString() == game).Distinct().Select(x => x.Username);
        var count = users.Count();

        var SeparatedList = string.Join(", ", users);

        string message;
        if (count > 1)
            message = $"There are {count} users playing {game}. [{SeparatedList}]";
        else if (count == 1)
           message = $"There is {count} user playing {game}. [{SeparatedList}]";
        else
            message = $"There is no one playing {game}.";

        await  Context.Channel.SendMessageAsync(message);
    }


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How to set a discordie discord bot to be playing a game?

How to set a discordie discord bot to be playing a game?


By : meneni shamili
Date : March 29 2020, 07:55 AM
hope this fix your issue Use: client.User.setGame('#Help for help');
Discordie documentation
How to get how many hours has users spent playing my game? Steamworks API

How to get how many hours has users spent playing my game? Steamworks API


By : Cybotive
Date : March 29 2020, 07:55 AM
should help you out You might still have a chance to get it to work. As far as I know, there's a way to get the total hours played (as shown in the Gameplay stats) by using the deprecated Community XML Data:
Prevent users from putting dots in front of their nicknames on Discord (discord.js / Discord Bot)

Prevent users from putting dots in front of their nicknames on Discord (discord.js / Discord Bot)


By : Qazim Rama
Date : March 29 2020, 07:55 AM
will help you You can use the guildMemberUpdate event to check when a member changes their nickname and then you can check if the new nickname startsWith a '.', here's an example of how that would look:
I prefer using displayName rather than nickname as if the member doesn't have a nickname their nickname will return null
code :
client.on('guildMemberUpdate', (oldMember, newMember) => {  // this event triggers when a member changes their nickname.
    if (newMember.displayName.startsWith('.')) { // checks if the new nickname starts with a .
        newMember.setNickname(oldMember.displayName) //changes the member's nickname back to their old nickname
            .catch(console.error);
    }
});
Discord Bot, problem while mentioning discord @users

Discord Bot, problem while mentioning discord @users


By : L. Collado-Torres
Date : March 29 2020, 07:55 AM
may help you . If you go to the discord.js site and click on Documentation in the top right, it will bring you to a page where you can learn about all of the objects in the discord.js api.
In your client.on("message"), message is defined, it is a message object, so to find that in the docs scroll down and look on the left side for Message, and click on it. You can now see all of the attributes that class has, it has an author, which the docs say is of type User. I have told you if you send a user object in a message, it will mention the user. So, send message.author and tada!
With discord.py, whats a way to get my discord bot to display a custom message in the 'playing' section on the members t

With discord.py, whats a way to get my discord bot to display a custom message in the 'playing' section on the members t


By : Zakk Mayer
Date : March 29 2020, 07:55 AM
wish helps you Edit: Based on constructor parameter for Client you can't pass activity like that in async branch, you can however do that in rewrite branch. I suggest you move to rewrite since it's better updated.
For your answer, you need to set it later for example in the on_ready method:
code :
bot = discord.Client()

@bot.event
async def on_ready():
    await bot.change_presence(game=discord.Game(name='some game'))
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