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How do you add the value of one integer to another?


How do you add the value of one integer to another?

By : Willie Justice
Date : November 21 2020, 03:00 PM
Does that help Just use the plus operator.
So it would be myVariable + myOtherVariable, you can also store this in a variable like this myStoreVar = myVar + myOtherVar.
code :


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Integer i = 23; versus Integer i = new Integer(23); Previous answers not satisfactory

Integer i = 23; versus Integer i = new Integer(23); Previous answers not satisfactory


By : user2420012
Date : March 29 2020, 07:55 AM
I think the issue was by ths following ,
If I say Integer i = 23; it is clearly creating an object i of type Integer.
error: passing ‘const Integer’ as ‘this’ argument of ‘Integer Integer::pow(int)’ discards qualifiers

error: passing ‘const Integer’ as ‘this’ argument of ‘Integer Integer::pow(int)’ discards qualifiers


By : Stiga Huang
Date : March 29 2020, 07:55 AM
this one helps. This is an issue with const correctness, where a const function is trying to call a non-const function.
code :
// ...

bool Integer::isQuadraticResidue() const;
Integer Integer::pow(int x);

// ....
Integer Integer::inverse() const;
Integer Integer::squared() const;
Integer Integer::pow()     const;
Method put(Integer, Integer) in the type Map<Integer,Integer> is not applicable for the arguments (String, Integer

Method put(Integer, Integer) in the type Map<Integer,Integer> is not applicable for the arguments (String, Integer


By : eagle407
Date : March 29 2020, 07:55 AM
I hope this helps you . Answer was provided for this problem, on another question I asked here:
Can I override a Map with Map?
Convert Map<Integer, List<Object>> to Map<Integer, Map<String, Map<LocalDate, Integer>>> u

Convert Map<Integer, List<Object>> to Map<Integer, Map<String, Map<LocalDate, Integer>>> u


By : user2526430
Date : March 29 2020, 07:55 AM
To fix the issue you can do I receive some result sets from a database and store each row as an object of type DbRow, this is the class: , You're possible looking for something like :
code :
Map<Integer, Map<String, Map<LocalDate, Long>>>  countDistinctDatesPerMonthPerClient(List<DbRow> input) {
    return input.stream()
            .collect(Collectors.groupingBy(DbRow::getClientNumber,
                    Collectors.groupingBy(DbRow::getTakeoverMonth,
                            Collectors.groupingBy(DbRow::getContractDate, Collectors.counting()))));
}
A character gives integer as output if we input an integer into it but this doesn't happen when an integer is assigned t

A character gives integer as output if we input an integer into it but this doesn't happen when an integer is assigned t


By : user3512855
Date : March 29 2020, 07:55 AM
help you fix your problem While you assign an integer to the character variable, it reads the integer from the memory and store at its location and while interpreting that char value, it returns ASCII equivalent of it. While reading cin buffer into the character variable(char) it reads 1 byte of the char or its ASCII value in the memory and gives the output as ASCII equivalent of it.
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