Matrix with counts of wins and losses between methods in R

Matrix with counts of wins and losses between methods in R

By : GURU 010101
Date : November 21 2020, 03:00 PM
it should still fix some issue You actually don't need that many data points in this matrix to keep all the same information; the Method 2 row of Method 1+ (Method 1 beats Method 2 x number of times) will always be equal to the Method 1 row of Method 2- (Method 2 loses to Method 1 x number of times). So, we can get this information like so:
code :
# First we make a function to count the wins in two columns
# (this will be useful later to feed to apply)
count_wins <- function(columns, data) {
    return(sum(data[ , columns[1]] < data[ , columns[2]]))
# Then we set the seed for some reproducible data
# Create some random example data
df <- data.frame(method1=sample(1:10, 5, replace=TRUE),
                      method2=sample(1:10, 5, replace=TRUE),
                      method3=sample(1:10, 5, replace=TRUE))
#   method1 method2 method3
# 1       3       1      10
# 2       8       6       5
# 3       5       9       7
# 4       9       6       6
# 5      10       5       2
# We make an empty matrix to store results
result <- matrix(NA, nrow=ncol(df), ncol=ncol(df))
# Create a matrix of all column pairings
combos <- combn(x=ncol(df), m=2)
# And use apply, upper/lower.tri, and count_wins to fill the matrix
result[upper.tri(result)] <- apply(combos, 2, count_wins, df)
result[lower.tri(result)] <- apply(combos[2:1,], 2, count_wins, df)
# Then we just name the rows and columns
rownames(result) <- colnames(result) <- paste0('method', 1:3)
#         method1 method2 method3
# method1      NA       1       2
# method2       4      NA       1
# method3       3       3      NA

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How to tally wins and losses using SUM and CASE?

How to tally wins and losses using SUM and CASE?

By : Hardik Yadav
Date : March 29 2020, 07:55 AM
will be helpful for those in need I am using SQL Server 2008
code :
    SUM(CASE WHEN Vote = 0 THEN 1 ELSE 0 END) AS Losses
FROM     Votes
WHERE    BikeID = 101
Combine wins and losses in same row

Combine wins and losses in same row

By : ficknergs
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Do this as a single query, with conditional aggregation. I think this is the query:
code :
 select sum(case when (s.hometotalruns - s.awaytotalruns) > 0 and t2.TeamName = 'Pirates' 
                 then 1 else 0
            end) as roadlosses,
        sum(case when (s.hometotalruns - s.awaytotalruns) > 0 and t1.TeamName = 'Pirates'
                 then 1 else 0
            end) as homewins,
        'Pirates' as TeamName
 from scores s
 inner join games g
 on g.GameID=s.GameID
 inner join teams t1
 on t1.TeamID=g.HomeTeam
 inner join teams t2
 on t2.Teamid=g.AwayTeam
 where 'Pirates' in (t1.TeamName, t2.teamName);
SQL - Counting Wins and Losses

SQL - Counting Wins and Losses

By : BlackCyan
Date : March 29 2020, 07:55 AM
will help you I'm having a bit of trouble creating a mySQL query for counting wins and losses from a table that contains each individual game result. The table looks like:
code :
    season, team,
    count(case when outcome = 'W' then 1 else null end) as wins,
    count(case when outcome = 'L' then 1 else null end) as losses
    select season, winning_team as team, 'W' as outcome from cbb.regular_season union all
    select season, losing_team as team, 'L' as outcome from cbb.regular_season
    ) as games
group by season, team
Sorting Wins and Losses

Sorting Wins and Losses

By : Joe
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Let say your data set is found on A1:K2
And on A4 you will enter the lookup number.
code :
Calculate the Probability of winning (wins/ (wins + losses)) with 10,000 simulations in the game of craps.. this is part

Calculate the Probability of winning (wins/ (wins + losses)) with 10,000 simulations in the game of craps.. this is part

By : D C
Date : March 29 2020, 07:55 AM
hop of those help? Your code has already all the logic needed. To repeat it as many times you want, there are different ways. They are known as loops. If you search on Google you will find for, while, do/while and some others (you have a while already inside the code).
For your question, the basic would be to repeat it 10,000 times the same things.
code :
public class CrapsGame {

    public static void main(String[] args) {

        // Create some variables to control the times it won and times it lost
        int timesWon = 0;
        int timesLost = 0;

        // Here we're saying it's gonna repeat 10000 times, incrementing 1 by 1
        for(int i=0; i<10000; i++) {
            // Here you will insert all the existing logic from your program

            // In the existing code, increment the variables declared according

            if(roll == 2 || roll == 3 || roll == 12){
                System.out.println("You Lose !");
            }else if(roll == 7 || roll == 11){
                System.out.println("You Win !");
                // Where you find it won, insert `timesWon++;`
                // Where you find it lost, insert `timesLost++;`
        // Here it exits the for loop (after 10000 times)
        // Here's where you can calculate

        System.out.println("Probability of winning: " + (timesWon/(timesWon + timesLost)));
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