Removing vowels from an input string using a loop

Removing vowels from an input string using a loop

By : Tomislav Tumbas
Date : November 21 2020, 03:00 PM
it helps some times I'm very much in favor of using a while loop for this, but since you stated you can only use a for loop...
The problem is that your loop will iterate until i = 5, even if a vowel is detected. We need a way to tell the loop to pretend that never happened. You can't decrement i, or you'll be stuck at the same character forever.
code :
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
    Scanner keyboard = new Scanner(System.in);
    String s = "";
    System.out.println("Type a tweet: ");
    String input = keyboard.nextLine();
    int f = 0;
    int tweetLengthAllowed = 5;
    for(int i = 0; i < tweetLengthAllowed; ++i) { //Must be a for loop
        char c = input.charAt(i);

        if(c == 'a'|| c == 'e'|| c == 'i'|| c == 'o'|| c =='u' || 
            c == 'A' || c == 'E' ||  c == 'I' ||  c == 'O' || c == 'U') {

            f = 1;
            tweetLengthAllowed++; //Allows the loop to continue for one more interation
        } //end if
            s = s += c;
            f = 0;
        }//end else
    } //end for

} //end main
} //end class

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MIPS assembly - removing vowels from an input string

MIPS assembly - removing vowels from an input string

By : Brad Vaile
Date : March 29 2020, 07:55 AM
seems to work fine So. I took a look at what you've writen and I've fixed it.
My first thought is I don't know what you are doing with the stack and stack pointer ($sp). It didn't seem necessary so I took it out.
code :
    .globl  main

    # display prompt
    li      $v0, 4
    la      $a0, prompt
    # accept input string
    li      $v0, 8
    la      $a0, str
    li      $a1, 82

    li      $t1, 0          # initiate index
    li      $t3, 0          # vowel count

    lb $t0 str($t1)

    # check if vowel
    li      $t2, 'a'       # a
    beq     $t0, $t2, vowel
    li      $t2, 'e'       # e
    beq     $t0, $t2, vowel
    li      $t2, 'i'       # i
    beq     $t0, $t2, vowel
    li      $t2, 'o'       # o
    beq     $t0, $t2, vowel
    li      $t2, 'u'       # u
    beq     $t0, $t2, vowel

    # if not a vowel, store it at current index in string less vowel count
    sub     $t2, $t1, $t3
    sb      $t0, str($t2)
    j       next
vowel:  # if vowel, inc count
    addi $t3, $t3, 1
    addi $t1, $t1, 1

    beqz    $t0, done       # once we reach null char, finish
    j       poploop

    li      $v0, 4
    la      $a0, str
    li      $v0, 10         # exit program

str:    .space 82
prompt: .asciiz "Input a string:\n"
Removing all the vowels from a string - PL/SQL

Removing all the vowels from a string - PL/SQL

By : user3211887
Date : March 29 2020, 07:55 AM
To fix this issue Technically, the assignment calls for an anonymous pl/sql block, and prompting user for input. So you'd have something like this:
code :
set serveroutput on
set verify off

accept vstring prompt "Please enter your string: ";
   vnewstring varchar2(100);
   vnewstring := regexp_replace('&vstring', '[aeiouAEIOU]','');
   dbms_output.put_line('The new string is: ' || vnewstring);
Please enter your string: This is a test
The new string is: Ths s  tst

PL/SQL procedure successfully completed.
counting the vowels, without using raw input and the string 's' is defined.My result a infinite loop, whats wrong in it

counting the vowels, without using raw input and the string 's' is defined.My result a infinite loop, whats wrong in it

By : Elliana Rochelle Lop
Date : March 29 2020, 07:55 AM
I wish this help you simply use for loop to iterate every character from the string.
code :
In [28]: s = "qazxswedcvfrgbnhyujmkiopl"

In [29]: count = 0

In [30]: for i in s:
   ....:     if i.lower() in ["a", "i", "o", "u", "e"]:
   ....:         count += 1

In [31]: print count
Removing from vowels from a string

Removing from vowels from a string

By : heinz_ho
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Here is the code I have:
code :
[character for character in sentence if character not in vowels] # returns list
''.join([character for character in sentence if character not in vowels]) # returns string without vowels
C program to accept a string input and print number of vowels and most repeated vowels in the string

C program to accept a string input and print number of vowels and most repeated vowels in the string

By : Anthony Poujouanine
Date : March 29 2020, 07:55 AM
hop of those help? You can try any of the below approach ...
Create a struct MAP with key and value as members. Have helper methods that allow you to populate MAP struct with key as vowel and value as no. of occurrences. Create a 2D array of vowel where row represents the vowels and column no. of occurrences. Simplest to understand would be creating an array of size 256 (ascii) and keep on increment the value at array[ascii(vowel)] by 1 on each occurrence.
code :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#define MAX 150

    int NumberOfVowels(char Statement[], char vowels[], int counts[])
        int i, j = 0;

        for(j=0; j<strlen(Statement); j++) {
            if (Statement[j] == '\0' || Statement[j] == '\n') {
            for(i=0; i<5; i++) {
                if(vowels[i] == Statement[j]) {
                    int ascii = (int) vowels[i];
                    counts[ascii] = counts[ascii] + 1;

        for(i=0; i<5; i++) {
            int ascii = (int) vowels[i];
            printf("%c - %d ", vowels[i], counts[ascii]);
        return 0;

int main()
    char Statement[MAX];
    char vowels[] = {'a', 'e', 'i', 'o', 'u'};
    int counts[256] = {0};
    int i, j;

    puts("Enter a simple statement.");
    fgets(Statement, 150, stdin);
    printf("\nYou entered: %s\n", Statement);
    for(i=0; i<=strlen(Statement); i++){
        //Converting uppercase input to lowercase
        Statement[i] = tolower((unsigned char)Statement[i]);
        printf("%c ", Statement[i]);
    //Calling the function to print no. of 
    NumberOfVowels(Statement, vowels, counts);
    return 0;
You entered: Hello How are you, I am fine!                                                                                                                           

h e l l o   h o w   a r e   y o u ,   i   a m   f i n e !    

  a - 2 e - 3 i - 2 o - 3 u - 1  
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