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How to get Y value at a given X value of a trendline


How to get Y value at a given X value of a trendline

By : illusion_of_life
Date : November 22 2020, 03:01 PM
Does that help I have created a trend-line using the lpoly command (local polynomial smoothed trendline). , One can do this using the generate() option of the lpoly command:
code :
webuse motorcycle, clear
lpoly accel time, generate(x y)
list y x in 1/10

     +------------------------+
     |          y           x |
     |------------------------|
  1. | -1.6245329   2.4000001 |
  2. |  -1.775922   3.5265307 |
  3. | -1.9832878   4.6530613 |
  4. | -2.2217888   5.7795918 |
  5. | -2.3814197   6.9061224 |
     |------------------------|
  6. | -2.5199665    8.032653 |
  7. | -3.3919962   9.1591836 |
  8. | -8.8572222   10.285714 |
  9. | -16.957709   11.412245 |
 10. | -26.693355   12.538775 |
     +------------------------+
twoway line y x


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Add Trendline to ASP.Net Chart

Add Trendline to ASP.Net Chart


By : Moh Som
Date : March 29 2020, 07:55 AM
I hope this helps you . There's a pretty good article on doing that on the 4Guys from Rolla site:
"Using Microsoft's Chart Controls In An ASP.NET Application: Adding Statistical Formulas"
Weighted trendline

Weighted trendline


By : Mr. Glodny
Date : March 29 2020, 07:55 AM
it helps some times With data in A2:C7, based on the standard weighted least squares formula, you can try:
code :
=LINEST(B2:B7*C2:C7^0.5,IF({1,0},1,A2:A7)*C2:C7^0.5,0)
=INDEX(LINEST((B2:B7-SUM(B2:B7*C2:C7)/SUM(C2:C7))*C2:C7^0.5,IF({1,0},1,A2:A7)*C2:C7^0.5,0,1),3,1)
SSres = 59.76
SSreg(u) = 1461.24
SSTot(u) = 1521
Rsq(u) = 1 - 59.76/1521 = 0.9607 
SSTot(c) =SUMPRODUCT(C2:C7*(B2:B7-SUM(B2:B7*C2:C7)/SUM(C2:C7))^2) = 244.93
Rsq(c) = 1 - 59.76/244.93 = 0.756
How do I get endpoints of a trendline?

How do I get endpoints of a trendline?


By : Fauzan ppnh
Date : March 29 2020, 07:55 AM
To fix the issue you can do Want to change your scale from Amps/Time to MilliAmps/Time? Multiply by 1000 Trouble with Unix timestamp? Because your timescale reaches back to Jan 1, 1970. Pick a timestamp as your 'zero' time and subtract it from all of the others.
How to get trendline equations in R

How to get trendline equations in R


By : user2136834
Date : March 29 2020, 07:55 AM
like below fixes the issue i have a series of data in form of time and temperature value. I want to generate a trendline and find the subsequent equation. This could be done in excel. but, how could i find equation of the trendline in R. ,
but where is the underlying equation?
code :
> coef(model)
(Intercept)           x
  1.2093273   0.9786051
paste('y =', coef(model)[[2]], '* x', '+', coef(model)[[1]])
Trendline in GraphView?

Trendline in GraphView?


By : luo dao
Date : March 29 2020, 07:55 AM
this one helps. Is there a way in GraphView to graph and find the equation of a linear trendline that represents the data points on a line graph? , There is no trendline in GraphView (at least from what I know of).
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