Python 3 two dimensional list comprehension

Python 3 two dimensional list comprehension

By : Mischa
Date : November 22 2020, 03:01 PM
will be helpful for those in need I have two lists that are used to assemble a third. I compare list_one to list_two and if the value of a field in list_one is located in list_two both the values from list_two are copied into list_final. If the value of a field is missing from list_two then I'd like to see a null value (None) placed into list_final. list_final would have the same number of items and in the same order as list_one: , What was happening in your code:
code :
list_final = [x if [x,0] in list_two else [None,None] for x in list_one]
list_one = ['one', 'two', 'three', 'four', 'five', 'six', 'seven']
list_two = [['seven','7'], ['five','5'], ['four','4'], ['three','3'], ['one','1']]

# Turns list_two into a nice and convenient dict much easier to work with
# (Could be inline, but best do it once and for all)
list_two = dict(list_two)  # {'one': '1', 'three': '3', etc}

list_final = [[k, list_two[k]] if k in list_two else [None, None] for k in list_one]

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Two-dimensional list comprehension Python 2

Two-dimensional list comprehension Python 2

By : MB Media
Date : March 29 2020, 07:55 AM
this one helps. I'd like to know how I can convert the strings in a list to integers. , This would be the correct list comprehension:
code :
[[float(c) for c in row] for row in data]
[[1.0, -160.0], [2.0, -3000.0], [4.0, -2.0], [5.0, 0.27]]
[[float(c) if c.lstrip('-').isdigit() else c for c in row] for row in data ]
Python list comprehension for three-dimensional array

Python list comprehension for three-dimensional array

By : pxshock
Date : March 29 2020, 07:55 AM
will help you I have a three dimensional array in this format: , You need to iterate one level deeper:
code :
x = [[[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]], [[11, 12, 13, 14, 15], [16, 17, 18, 19, 20]], [[21, 22, 23, 24, 25], [26, 27, 28, 29, 30]], [[21, 22, 23, 24, 25]]]
y = [[i[:3] for i in b] for b in x]
z = [[i[-2:] for i in b] for b in x]
[[[1, 2, 3], [6, 7, 8]], [[11, 12, 13], [16, 17, 18]], [[21, 22, 23], [26, 27, 28]], [[21, 22, 23]]]
[[[4, 5], [9, 10]], [[14, 15], [19, 20]], [[24, 25], [29, 30]], [[24, 25]]]
Defining a two dimensional array using python list comprehension

Defining a two dimensional array using python list comprehension

By : Jason
Date : March 29 2020, 07:55 AM
it fixes the issue A list comprehension is a single statement that initializes an array with some data, so you don't need another initialization. In the second case, you need to first initialize the array before assigning values to its elements.
How to add 0's into two dimensional list using list comprehension in python?

How to add 0's into two dimensional list using list comprehension in python?

By : Jared Dilg
Date : March 29 2020, 07:55 AM
this will help It doesn't work, because list.insert() modifies the list in-place and returns None, so you will end up with a list of Nones which are return values from all .insert()s.
List comprehension format is not adequate for what you want, because it is designed to create new lists, and you seem to want to modify the list in-place. If you want to create new lists instead, you can use this:
code :
test_list = [sublist + [0] for sublist in test_list]
two dimensional list comprehension , Python 3

two dimensional list comprehension , Python 3

By : SixSigma BioAcademy
Date : March 29 2020, 07:55 AM
should help you out i have Two dimensional list , Use :
code :
[[0 if i<=0.5 else 1 for i in x ] for x in lst] #where lst is the original list

o/p : [[0, 0, 1], [0, 0, 1], [0, 0, 1]]
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