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Find array in another array and get index of result


Find array in another array and get index of result

By : Mert
Date : November 22 2020, 03:01 PM
this one helps. I have this array: , Try following:
code :
const parseData = (arr, obj) => {
  let found = arr.find(a => JSON.stringify(a.attributes) === JSON.stringify(obj));
  return found ? found.id : null;
}

console.log(parseData(arr, obj)); //434


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Given an array as input find the output array that has median of each sub array whose index starts from 0 to i(i = 1,2..

Given an array as input find the output array that has median of each sub array whose index starts from 0 to i(i = 1,2..


By : user3362167
Date : March 29 2020, 07:55 AM
Hope this helps Basically what we need here is a data structure that supports two operations: adding an arbitrary element and finding the median of all elements added to it so far.
Loop through an array to find the index of a user input, then replace the value at the same index of another array

Loop through an array to find the index of a user input, then replace the value at the same index of another array


By : Melody Ramirez
Date : March 29 2020, 07:55 AM
hope this fix your issue There are a few problems:
As @Glubus pointed out, [word] doesn't make a character array. Use word.split(''). You set up your underscores string to have spaces in it, making it twice as long as word, so the index needs to be multiplied by two to compensate You aren't catching every instance of a guessed letter, because indexOf only returns the first one
code :
var wordArray = word.split('');
var underscoresArray = underscores.split('');
for (var i = 0; i < wordArray.length; i++) {
  // Catch every letter, eg. the "p"s in "popcorn"
  if (wordArray[i] == guess) {
    // Underscored indices are twice the word indices
    // "popcorn" -> "p _ p _ _ _ _"
    underscoresArray[i * 2] = guess;
  };    
}
// Only need to do this once after all changes are made
underscores = underscoresArray.join(''); // Collapse back to string
$('#words').after(underscores);
console.log(underscores);
numpy array indexing: list index and np.array index give different result

numpy array indexing: list index and np.array index give different result


By : Paula Navea
Date : March 29 2020, 07:55 AM
Hope that helps If it's an array it's interpreted as shape of the final array containing the indices - but if it's an list it's the indices along the "dimensions" (multi-dimensional array indices).
So the first example (with an array) is equivalent to:
code :
[[x[0], x[1],
 [x[1], x[2]]
[x[0, 1], x[1, 2]]
x[[0, 1], [1, 2]]
          ^^^^^^----- indices for the second dimension
  ^^^^^^------------- indices for the first dimension
Array > Object: how to index an array of objects with reduce, omitting the index from nested element in result (es201

Array > Object: how to index an array of objects with reduce, omitting the index from nested element in result (es201


By : user1971477
Date : March 29 2020, 07:55 AM
hop of those help? If you want to make and object with id as key and remaining object as value. You can try following using Rest Parameters
ES2017
code :
const peopleArray = [{"id": "Antoine","country": "France"},{"id": "Alejandro","country": "Spain"}];

const result = peopleArray.reduce( (ac, o) => { 
  ac[o.id] = Object.assign({}, o); 
  delete ac[o.id].id; 
  return ac; 
}, {});
console.log(result);
const peopleArray = [{"id": "Antoine","country": "France"},{"id": "Alejandro","country": "Spain"}];

const result = peopleArray.reduce( (ac, {id, ...rest}) => Object.assign(ac, {[id]: rest}), {} );
console.log(result);
FInd and strore index of array one using array two elements and store all index of array one in array 3

FInd and strore index of array one using array two elements and store all index of array one in array 3


By : Mohammed Mourad
Date : October 10 2020, 03:00 PM
wish helps you I have main array like this although it is not complete array but that;'s the format of array , This code does both steps:
code :
arr1 = [{
    transformMatrix: null,
    fill: "#FFFFFF",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  },
  {
    transformMatrix: null,
    fill: "#000000",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  },
  {
    transformMatrix: null,
    fill: "#FFFFFF",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  },
  {
    transformMatrix: null,
    fill: "#0000FF",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  },
  {
    transformMatrix: null,
    fill: "#FFFFFF",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  },
  {
    transformMatrix: null,
    fill: "#FFFFFF",
    dirty: false,
    stroke: "#000000",
    strokeWidth: 0.172
  }
]

dupe = new Set()
arr2 = arr1.filter(({fill}) => {
  if (dupe.has(fill)) {
    return false
  } else {
    dupe.add(fill)
    return true
  }
})

obj = arr2.reduce((acc1, {fill:f1}) => {
  acc1[f1] = arr1.reduce((acc2, {fill:f2}, i) => f1 === f2 ? [...acc2, i] : acc2, [])
  return acc1
}, {})

console.log(obj)
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