 Convert list/vector of strings with date format into posix date class with R
By : Abhilasha Abhinav
Date : March 29 2020, 07:55 AM
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 convert a list of unix timestamps to a list of date and time strings for some other time zone in python
By : K.Madhuri
Date : March 29 2020, 07:55 AM
will help you You can convert a UNIX timestamp into a datetime object and then format it using its strftime method. However, this will give you a timezone-unaware datetime. In order to make it timezone-aware, you'll need to get the timezone from pytz and use the localize method: code :
from datetime import datetime
from pytz import timezone
# ...
def format_time(time, tz):
localized = tz.localize(datetime.fromtimestamp(time))
return localized.strftime('%d/%m/%Y %H:%M:%S')
us_pacific = timezone('US/Pacific')
dates = map(lambda t: format_time(t, us_pacific), posix_times)
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Convert range of two date time's into a list of dates and count of seconds per that date python
By : Nu Nu Khaing
Date : March 29 2020, 07:55 AM
it fixes the issue I'm interested in creating a function that gets two following datetime objects (start date and end date) as input and returns a list of tuples. I would like a tuple for each date between start and end date, and the number of seconds in this date. For example: , Try the following: code :
from datetime import timedelta
def date_range(start, end):
current = start
while True:
next_stop = (current + timedelta(days=1)).replace(
hour=0, minute=0, second=0)
if next_stop > end:
next_stop = end
yield current.date(), (next_stop - current).total_seconds()
if next_stop == end:
break
current = next_stop
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Convert integers inside a list into strings and then a date in python 3.x
By : one.bogdan
Date : March 29 2020, 07:55 AM
This might help you To split your list into size 3 chunks you use a range with a step of 3 code :
for i in range(0, len(l), 3):
print(l[i:i+3])
'/'.join([str(x) for x in l[i:i+3]])
def make_times(l):
results = []
for i in range(0, len(l), 3):
results.append('/'.join([str(x) for x in l[i:i+3]]))
return results
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 Convert Python list of duplicate date entries/values to Pandas Dataframe sorted by date
By : bitwizard
Date : March 29 2020, 07:55 AM
it should still fix some issue Maybe not the most simple or efficient answer, but this works. Basically I'm creating two DataFrame objects, getting rid of all of the nan's and then merging them on the 'Date' column. code :
import pandas as pd
list_ex = [{'Date': '12/31/2018', 'A': 'N/A'},
{'Date': '09/30/2018', 'A': '$5.75'},
{'Date': '06/30/2018', 'A': '$5.07'},
{'Date': '03/31/2018', 'A': '$3.27'},
{'Date': '12/31/2018', 'B': 'N/A'},
{'Date': '09/30/2018', 'B': '$56,576.00'},
{'Date': '06/30/2018', 'B': '$52,886.00'},
{'Date': '03/31/2018', 'B': '$51,042.00'}]
df1 = pd.DataFrame(data=list_ex, columns=['Date', 'A']).dropna()
df2 = pd.DataFrame(data=list_ex, columns=['Date', 'B']).dropna()
df3 = pd.merge(df1, df2, on='Date')
print(df3)
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code :
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