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By : user2171861
Date : October 25 2020, 09:10 AM
and created an in_ellipse function code :
``````def in_ellipse(point, ellipse):
return true if point in ellipse
return false

dot_a = ellipse_center
dot_b = dot
for i in range(20):
center_point = ((dot_b.y - dot_a.y)/2, (dot_b.x - dot_a.x)/2)
if in_ellipse(center_point):
dot_a = center_point
else:
dot_b = center_point

return center_point
`````` ## Calculating a point on an ellipse

By : Kamal Jeet
Date : March 29 2020, 07:55 AM
Any of those help Why not use the polar form of an ellipse where the angle is measured from the ellipse centre??? http://en.wikipedia.org/wiki/Ellipse#Polar_form_relative_to_center From this equation, if you know the value of the angle between A and B (say theta), and you know the value of central angle of the new point C (say phi), then your required point D can be calculated from this polar form using an angle (theta + phi) ## How to efficiently generate a straight line with random slope and intercept in Python?

Date : March 29 2020, 07:55 AM
wish helps you You can use numpy array broadcasting to create your y array in one step as shown below.
code :
``````import numpy as np
import matplotlib.pyplot as plt

x = np.arange(start=0, stop=5, step=0.1)

n_data = len(x)
n_rnd = 1000

m = np.random.normal(loc=1, scale=0.3, size=n_rnd)
b = np.random.normal(loc=5, scale=0.3, size=n_rnd)

y = m * x[:, np.newaxis] + b

for val in y.transpose():
plt.plot(x, val, alpha=0.05)

# Or without the iteration:
# plt.plot(x, y, alpha=0.05)

plt.show()
`````` ## Calculating shortest distance from point to line defined by intercept and slope in R

Date : March 29 2020, 07:55 AM
I wish this helpful for you Test this (Modified from here)
code :
``````#Perpendicular distance from point 'a' to a line with 'slope' and 'intercept'
dist_point_line <- function(a, slope, intercept) {
b = c(1, intercept+slope)
c = c(-intercept/slope,0)
v1 <- b - c
v2 <- a - b
m <- cbind(v1,v2)
return(abs(det(m))/sqrt(sum(v1*v1)))
}

dist_point_line(c(2,1), 1, 0)
# 0.7071068
``````
``````apply(df, 1, function(x) dist_point_line(as.numeric(x[1:2]), slope = 1, intercept = 0) )
# 0.0000000 0.7071068 1.4142136 2.1213203 2.8284271 3.5355339 2.8284271 2.1213203 1.4142136 0.7071068
`````` ## Equation of a straight line passing through two points and distance point straight - C

By : sharoon albert
Date : March 29 2020, 07:55 AM
wish of those help first of all transform your line equation to another form
Ax + By + C = 0 // keep int mind that A^2 + B^2 != 0 (this means that A or B are unable to be equall to zero in one moment)
code :
``````d = abs(A * Mx + B * My + C)/sqrt(A * A + B * B)
`````` ## Graph point on straight line (number line) in Python

By : Anna MM
Date : March 29 2020, 07:55 AM
it should still fix some issue I don't know of a specific package for this but you could do something like this in Matplotlib using hlines, vlines and plot. 