IndexOutOfRange error when filling a List Python

IndexOutOfRange error when filling a List Python

By : user2171886
Date : October 25 2020, 09:10 AM
it helps some times Because the outer list comprehension determines the number of rows, which equals len(s2):
code :
M  = [[0 for x in range(s1)] for y in range(s2)]
for i in range(s1):
    for j in range(s2):
        if ....:
            M[i][j] = ...

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IndexOutOfRange error when accessing OleDbDataReader items

IndexOutOfRange error when accessing OleDbDataReader items

By : user7354818
Date : March 29 2020, 07:55 AM
seems to work fine I have some sql that works fine in access 2010 and returns the correct values. However, in VB.NET, when I run it causes the above error in the while loop. dr.HasRows is returning 'TRUE' but the var 'itm' shows nothing in auto window. Can someone please explain why this is happening and how I can correct it. , You don't need the square brackets here:
code :
itm = CStr(dr.Item("[MaxOfRequest no]")) 
itm = CStr(dr.Item("MaxOfRequest no"))
c# openFileDialog IndexOutofRange error

c# openFileDialog IndexOutofRange error

By : user2027189
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You haven't prompted the user to select a file... you need to show the OpenFileDialog.
code :
bmpOpenFileDialog.ShowDialog();  // <-- you forgot this line
IndexOutOfRange in while loop and route error

IndexOutOfRange in while loop and route error

By : user3814109
Date : March 29 2020, 07:55 AM
Hope that helps Loops in C# usually range from 0 to n-1, so be double-sure that starting at 1 is what you want.
Other than that, the error results probably from the fact that Model only contains 5 or less elements, so accessing Model[5] results in an error, as the elements in Model are indexed from 0 to (at most) 4.
Python : list index out of range error for filling in data set

Python : list index out of range error for filling in data set

By : Jeff Zhang
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have a data set [101,102,105,106,108,111] with a corresponding times [1,2,5,6,8,11]. I need to fill in the data set with zeros when the difference between the nth and nth + 1 time is not 1. so far i have tried many and this is one: , The following approach should work:
code :
import itertools

data_set = [101,102,105,106,108,111] 
data_times = [1,2,5,6,8,11]

new_time_set = range(data_times[0], data_times[-1]+1)
new_data_set = []

last_time = data_times[0]

for data, time in itertools.izip(data_set, data_times):
    new_data_set.extend([0] * (time-last_time-1) + [data])
    last_time = time    

print "Data:", new_data_set
print "Times:", new_time_set
Data: [101, 102, 0, 0, 105, 106, 0, 108, 0, 0, 111]
Times: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
new_time_set = range(int(data_times[0]), int(data_times[-1])+1)
Error IndexOutOfRange when getting processid

Error IndexOutOfRange when getting processid

By : Ali.Aswani
Date : March 29 2020, 07:55 AM
I hope this helps . Most likely there is no running process with the string that you are using as a filter. Then the call returns an empty array.
You cannot get an array element 0 from an empty array, that's why you are getting this exception.
code :
return ProcList.FirstOrDefault()?.Id;
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